Last updated: Fri, 20 Jun 2008

mysql_fetch_row

(PHP 4, PHP 5, PECL mysql:1.0)

mysql_fetch_row — Retourne une ligne de résultat MySQL sous la forme d'un tableau

Description

array mysql_fetch_row ( resource $result )

mysql_fetch_row() retourne un tableau indexé numériquement, qui correspond à la prochaine ligne du résultat MySQL result et déplace le pointeur interne de données d'un cran.

Liste de paramètres

result: La ressource de résultat qui vient d'être évaluée. Ce résultat vient de l'appel à la fonction mysql_query().

Valeurs de retour

Retourne un tableau numérique de chaînes qui correspond à la ligne récupérée, ou FALSE s'il n'y a plus de lignes.

mysql_fetch_row() va rechercher une ligne dans le résultat associé à l'identifiant de résultat spécifié. La ligne est retournée sous la forme d'un tableau. Chaque colonne est enregistrée sous la forme d'un tableau commençant à la position 0.

Exemples

Exemple #1 Exemple avec mysql_fetch_row()


<?php
$result = mysql_query("SELECT id,email FROM people WHERE id = '42'");
if (!$result) {
   echo 'Impossible d\'exécuter la requête : ' . mysql_error();
   exit;
}
$row = mysql_fetch_row($result);

echo $row[0]; // 42
echo $row[1]; // la valeur du champ email
?>

Notes

Note: Cette fonction définit les champs NULL à la valeur PHP NULL.

Voir aussi

mysql_field_flags

mysql_fetch_object

Last updated: Fri, 20 Jun 2008

add a note User Contributed Notes
mysql_fetch_row

larkitetto at gmail dot com
21-Feb-2008 03:29


sry :) note now fixed:



<?php

$esi=mysql_list_tables($db);$ris=mysql_fetch_row($esi);

//example: $db has >= 1 tabs

echo var_dump($ris);

//echoes only array(1). solution:

while($ris=mysql_fetch_row($esi)) echo $ris[0];

/*debug:

$ris=array("1st_tab"); ... $ris=array("n_tab");$ris=false;*/

while ($ris[]=mysql_fetch_row($esi));

//debug:$ris=array(array("1st_tab"), ... array("n_tab"));

echo $ris[n][0];//echo:"n_tab"

echo $ris[0][n];//echo:array | null

?>



hope it helps

ryhan_balboa at yahoo dot com
16-Nov-2007 09:23


The following are the basic codes to get a specific row from the mysql db into a $row variable:



 

$query = "SELECT * FROM table"; 

$result = mysql_query($query); 

$row = mysql_fetch_row($result);



And $row[0], $row[1] ... $row[n] are used to access those field values. 



Does anyone know how I can add a new field to $row, so that the field count increases from n to n+1?



I have tried treating $row like an array, and tried array_push function, but didn't work.



Thanks.

m dot s at programmers-online dot net
17-Nov-2005 01:56


The following function to read all data out of a mysql-resultset, is may be faster than Rafaels solution:



<?

function mysql_fetch_all($result) {

   while($row=mysql_fetch_array($result)) {

       $return[] = $row;

   }

   return $return;

}

?>

mysql at polyzing dot com
12-Jul-2003 03:05


It is probably worth pointing out that the array elements will actually be of type string, OR NULL if the field is null in the database.



Thus, either use a double equal comparison to look for empty or null



Or, use a triple equal comparison to be able to distinguish the two cases



e.g.



if ($field === '') echo "Empty, not NULL\n";



if ($field === NULL) echo "NULL\n";



if ($field == '') echo "Empty or NULL\n";

michael and then an at sign wassupy.com
08-Apr-2003 12:09


to print an array, simply use print_r(array name)



like this:

    $myrow = mysql_fetch_row($result);

echo "<pre>";

print_r($myrow);

echo "</pre>";



this will output the array in a readable form, with the index, too. Don't forget the 'pre' tags or the output will be on a single line.

a at simongrant dot org
06-Feb-2002 05:10


Maybe worth pointing out that all the fields returned by this (and other?) calls are returned with type string. This had me puzzled for quite some time.

add a note

mysql_field_flags

mysql_fetch_object

Last updated: Fri, 20 Jun 2008