This is the function in php form if your php is older than 4.0.4
<?php
if(!function_exists("ctype_xdigit")){
function ctype_xdigit($string = ""){
return !strlen( trim( $string, "1234567890abcdefABCDEF" ) );
}/* endfunction ctype_xdigit */
}/* endif not function_exists ctype_xdigit */
?>
ctype_xdigit
(PHP 4 >= 4.0.4, PHP 5)
ctype_xdigit — Check for character(s) representing a hexadecimal digit
Popis
bool ctype_xdigit ( string $text )Checks if all of the characters in the provided string, text, are hexadecimal 'digits'.
Seznam parametrů
- text
The tested string.
Návratové hodnoty
Returns TRUE if every character in text is a hexadecimal 'digit', that is a decimal digit or a character from [A-Fa-f] , FALSE otherwise.
Příklady
Příklad 315. A ctype_xdigit() example
<?php
$strings = array('AB10BC99', 'AR1012', 'ab12bc99');
foreach ($strings as $testcase) {
if (ctype_xdigit($testcase)) {
echo "The string $testcase consists of all hexadecimal digits.\n";
} else {
echo "The string $testcase does not consist of all hexadecimal digits.\n";
}
}
?>
Výše uvedený příklad vypíše:
The string AB10BC99 consists of all hexadecimal digits.
The string AR1012 does not consist of all hexadecimal digits.
The string ab12bc99 consists of all hexadecimal digits.
Viz také
| ctype_digit() |
ctype_xdigit
dot dot dot dot dot alexander at gmail dot com
30-Jan-2008 10:41
30-Jan-2008 10:41
tom at hgmail dot com
14-Jan-2006 12:36
14-Jan-2006 12:36
This function shows its usefulness on a web site where a user is asked to entered a hexidecimal color code for a color. To prevent breaking W3C standard and having them enter in "neon-green" or the wrong type of code like 355511235.
In conjunction with strlen() you could create a function like this:
function check_valid_colorhex($colorCode) {
// If user accidentally passed along the # sign, strip it off
$colorCode = ltrim($colorCode, '#');
if (
ctype_xdigit($colorCode) &&
(strlen($colorCode) == 6 || strlen($colorCode) == 3))
return true;
else return false;
}
