date_timezone_set
Hi ! I've had a specific need to find out if a day is the day when a country switch to winter/spring times , aka loosing one hour or getting one hour compared to the real time .. This works in europe , but i don't know about other regulations or countries , so be warned. The switch to "spring time" is always on the last saturday of march. The switch to winter time is always last saturday of october. Hope it helps !
use it like this :
<?php
if(checkSwitchToWinterTime('20081025'){
echo 'today we switch to winter time' ;
}
function checkSwitchToWinterTime($day){
//day is yyyymmdd
$y =substr($day,0,4);
$m = substr($day,4,2);
$d = substr($day,6,2);
// if it is a saturday of october, check if it's the last one
if(date("D-m", mktime(0, 0, 0, $m, $d, $y))=="Sat-10"){ ;
if((date("m", mktime(0, 0, 0, $m, $d, $y))) != (date("m", mktime(0, 0, 0, $m, $d+7, $y)))) {
return true;
}
return;
}
return;
}
function checkSwitchToSpringTime($day){
//day is yyyymmdd
$y =substr($day,0,4);
$m = substr($day,4,2);
$d = substr($day,6,2);
// if it is a saturday of march, check if it's the last one
if(date("D-m", mktime(0, 0, 0, $m, $d, $y))=="Sat-03"){ ;
if((date("m", mktime(0, 0, 0, $m, $d, $y))) != (date("m", mktime(0, 0, 0, $m, $d+7, $y)))) {
return true;
}
return;
}
return;
}
?>
date
(PHP 4, PHP 5)
date — Formátuje místní datum/čas
Popis
string date ( string $format [, int $timestamp ] )Vrací řetězec formátovaný podle daného formátovacího řetězce s použitím daného celočíselného časového razítka timestamp nebo aktuálního místního času (není-li časové razítko zadáno). Jinými slovy, parametr timestamp je nepovinný a jeho výchozí hodnota je výsledek funkce time().
Poznámka: Platný rozsah pro časové razítko je typicky od pátku 13.12.1901 20:45:54 GMT do úterý 19.1.2038 03:14:07 GMT. (Tyto hodnoty odpovídají minimální a maximální hodnotě 32-bitového celého čísla se znaménkem). Na Windows je tento rozsah omezen na období 1.1.1970 až 19.1.2038.
K vygenerování časového razítka z řetězce reprezentujícího datum lze použít funkci strtotime(). Navíc některé databáze mají funkce, které konvertují jejich datové formáty na časová razítka (např. funce » UNIX_TIMESTAMP v MySQL).
Tabulka 34. Ve formátovacím řetězci lze používat tyto znaky:
| znak parametru format | Popis | Ukázka vracených hodnot |
|---|---|---|
| a | Příznak dopoledne/odpoledne malými písmeny | am nebo pm |
| A | Příznak dopoledne/odpoledne velkými písmeny | AM nebo PM |
| B | Internetový čas Swatch | 000 až 999 |
| d | Den měsíce, dvě číslice s úvodními nulami | 01 až 31 |
| D | Textová reprezentace dne, tři znaky | Mon až Sun |
| F | Plná textová reprezentace měsíce typu January nebo March | January až December |
| g | 12-hodinový formát hodiny bez úvodních nul | 1 až 12 |
| G | 24-hodinový formát hodiny bez úvodních nul | 0 až 23 |
| h | 12-hodinový formát hodiny s úvodními nulami | 01 až 12 |
| H | 24-hodinový formát hodiny s úvodními nulami | 00 až 23 |
| i | Minuty s úvodními nulami | 00 až 59 |
| I (velké i) | Zjištění, zda je letní čas | 1 pokud je letní čas, 0 jinak. |
| j | Den měsíce bez úvodních nul | 1 až 31 |
| l (malé 'L') | Plná textová reprezentace dne v týdnu | Sunday až Saturday |
| L | Zjištění, zda je rok přestupný | 1 pokud je přestupný rok, 0 jinak. |
| m | Číselná reprezentace měsíce s úvodními nulami | 01 až 12 |
| M | Krátká textová reprezentace měsíce, tři znaky | Jan až Dec |
| n | Číselná reprezentace měsíce bez úvodních nul | 1 až 12 |
| O | Odchylka od Greenwichského času (GMT) v hodinách | Příklad: +0200 |
| r | Datum formátované podle RFC 822 | Příklad: Thu, 21 Dec 2000 16:01:07 +0200 |
| s | Sekundy s úvodními nulami | 00 až 59 |
| S | Anglická pořadová přípona dne v měsíci, 2 znaky | st, nd, rd nebo th. Dobře funguje s j |
| t | Počet dní v daném měsíci | 28 až 31 |
| T | Nastavení časového pásma na tomto počítači | Příklady: EST, MDT ... |
| U | Sekundy od počátku éry Unix (1. ledna 1970 00:00:00 GMT) | Viz také time() |
| w | Číselná reprezentace dne v týdnu | 0 (pro neděli) až 6 (pro sobotu) |
| W | Číslo týdne podle ISO-8601, týdny začínají v pondělí (doplněno v PHP 4.1.0) | Příklad: 42 (42. týden v roce) |
| Y | Plná číselná reprezentace roku, 4 číslice | Příklady: 1999 nebo 2003 |
| y | Dvouciferná reprezentace roku | Příklady: 99 nebo 03 |
| z | Den v roce | 0 až 365 |
| Z | Posun časového pásma v sekundách. Posun časových pásem západně od UTC je vždy záporný, východně od UTC je vždy kladný. | -43200 až 43200 |
Nerozpoznané znaky ve formátovacím řetězci se vytiskou tak, jak jsou. Při použití gmdate() má formát Z vždy hodnotu 0.
Příklad 326. Příklady - date()
<?php
// Vytiskne něco jako: Wednesday
echo date("l");
// Vytiskne něco jako: Wednesday 15th of January 2003 05:51:38 AM
echo date ("l dS of F Y h:i:s A");
// Vytiskne: July 1, 2000 is on a Saturday
echo "July 1, 2000 is on a " . date ("l", mktime(0,0,0,7,1,2000));
?>
Rozpoznávané znaky ve formátovacím řetězci můžete ochránit před zpracováním tak, že jim předřadíte obrácené lomítko. Pokud už má znak s obráceným lomítkem speciální význam, je třeba před něj přidat ještě jedno obrácené lomítko.
Příklad 327. Ochrana znaků ve funkci date()
<?php
// vytiskne něco jako 'Saturday the 8th'
echo date("l \\t\h\e jS");
?>
Je možné použít společně date() a mktime() k nalezení dat v budoucnosti či v minulosti.
Příklad 328. Příklad - date() a mktime()
<?php
$tomorrow = mktime (0,0,0,date("m") ,date("d")+1,date("Y"));
$lastmonth = mktime (0,0,0,date("m")-1,date("d"), date("Y"));
$nextyear = mktime (0,0,0,date("m"), date("d"), date("Y")+1);
?>
Poznámka: Toto může být spolehlivější než prosté přičítání nebo odčítání sekund ve dni nebo měsíci (kvůli letnímu času).
Několik příkladů formátování pomocí date(). Nezapomeňte, že byste měli předřadit obrácené lomítko všem ostatním znakům, protože ty, které mají nyní speciální význam, budou způsobovat neočekávané výsledky, a ostatním může být přiřazen význam v budoucích verzích PHP. Ve všech takových případech také musíte používat apostrofy (k ohraničení řetězce), abyste zabránili znakům jako \n v odřádkování.
Příklad 329. Formátování pomocí date()
<?php
// Předpokládejme, že dnes je 10. března 2001, 17:16:18
$today = date("F j, Y, g:i a"); // March 10, 2001, 5:16 pm
$today = date("m.d.y"); // 03.10.01
$today = date("j, n, Y"); // 10, 3, 2001
$today = date("Ymd"); // 20010310
$today = date('h-i-s, j-m-y, it is w Day z '); // 05-16-17, 10-03-01, 1631 1618 6 Fripm01
$today = date('\i\t \i\s \t\h\e jS \d\a\y.'); // It is the 10th day.
$today = date("D M j G:i:s T Y"); // Sat Mar 10 15:16:08 MST 2001
$today = date('H:m:s \m \i\s\ \m\o\n\t\h'); // 17:03:17 m is month
$today = date("H:i:s"); // 17:16:17
?>
Pro formátování dat v jiných jazycích je třeba použít funkce setlocale() a strftime().
Viz také getlastmod(), gmdate(), mktime(), strftime() a time().
add a note
User Contributed Notesdate
bintjes at gmail dot com
10-Oct-2008 06:08
10-Oct-2008 06:08
adityabhai [at] gmail [dot] com
07-Oct-2008 02:56
07-Oct-2008 02:56
Aditya Bhatt (adityabhai [at] gmail [dot] com):
I have one date, and i want the next day of that date:
<?php
echo date("D F d Y",strtotime("+1 days")); // Same applies for months e.g. "+1 months"
?>
I have one date, and i want the previous day of that date:
<?php
echo date("D F d Y",strtotime("-1 days")); // Same applies for months e.g. "-1 months"
?>
adityabhai [at] gmail [dot] com
07-Oct-2008 02:52
07-Oct-2008 02:52
Aditya Bhatt (adityabhai [at] gmail [dot] com):
I have the current date & time, with me or any other date for which i want to check the month.
I want to display the next month using date function, it can be very helpful and a simple way to do this:
<?php
echo date('F j, Y, g:i a');
echo '<br />';
echo date('F j, Y, g:i a', strtotime('+1 month')); // Here you can change '+1 month' to n number of months you required in some of your calculation.
?>
Kenneth Kin Lum
02-Oct-2008 03:52
02-Oct-2008 03:52
date(DATE_RFC822) and date(DATE_RFC2822) both work. note that RFC 822 is obsoleted by RFC 2822. The main difference is the year being 08 in RFC 822 and is 2008 in RFC 2822.
To use date(DATE_RFC2822), a short form is date('r').
cservant at videotron dot ca
26-Sep-2008 08:14
26-Sep-2008 08:14
This is a code to convert RSS pubDate to a timestamp.
A timestamp is an INT which is faster and easier to sort than VARCHAR.
<?php
function pubDate_to_timestamp($time){
//Thu, 21 Aug 2008 01:14:36 PDT
//=> date("D, j M Y H:i:s T");
$time = explode(' ', $time);
$chrono = explode(':', $time[4]);
$month = array('Jan' => 1, 'Feb' => 2, 'Mar' => 3, 'Apr' => 4, 'May' => 5,
'Jun' => 6, 'Jul' => 7, 'Aug' => 8, 'Sep' => 9, 'Oct' => 10,
'Nov' => 11, 'Dec' => 12);
$mktime = mktime($chrono[0], $chrono[1], $chrono[2], $month[$time[2]], $time[1], $time[3], $time[5]);
return $mktime;
}
?>
nick at nick-web dot co dot uk
25-Sep-2008 08:48
25-Sep-2008 08:48
RE: wulf dot kaiser at mpimf-heidelberg dot mpg dot de code to work out fridays in a month. I noticed one small error. It looks like the
<?php
if ($givenMonth != '12') {
$nextGivenMonth = "1";
$nextGivenYear = $givenYear + 1;}
?>
block was setting every month to 1 because it was not equal to 12. I changed that to <?php if ($givenMonth == '12') { ?>and now all is fine!
Now - to refine it so that it only shows Fridays on the 5th or after, until the 4th of the next month.. Damm UK tax stuff!
=)
N
Landito
25-Sep-2008 04:44
25-Sep-2008 04:44
Changing the Timezones.
Europe/Germany to USA/East and change it back
I needed the actual time of NY. ;)
<?PHP
putenv("TZ=EST5EDT");
$date = date("Ymd-H:i:s");
putenv("TZ=MEZ-1MESZ");
?>
Anonymous
24-Sep-2008 04:35
24-Sep-2008 04:35
MySQL 5 will accept ISO_8601 encoded time, so it is acceptable to use date(ISO_8601)
dave dot artur at gmail dot com
24-Sep-2008 08:28
24-Sep-2008 08:28
I see a lot of solutions to date math / difference / subtraction issues, here's something I found works and is much simpler than some of the other things here. Apparently converting date values to a string allows you to apply arithmatic to them.
------------------------------
<?php
// Load the length of a song in seconds
$songLength = $emerge->getSongValue($sID, "songLength");
// Find when 1 frame started playing the song and convert that value to a string
// This works when pulling a datetime value from SQL
$songStart = (string)($emerge->getListItem("eID", $eID, "startTime"));
$songStart = (string)strtotime($songStart);
// The above is slightly roundabout, but seems to be the trick to getting PHP to stop treating variables like date values and doing weird math.
// Find when the current frame was loaded.
// This works when just using PHP date/time values
$loadTime = (string)date("U");
// Calculate the difference in seconds and convert to a value for a refresh entry.
$timeDiff = $loadTime - $songStart;
$length = (($songLength - $timeDiff) * 1000);
?>
jonathancnewcomb at msn dot com
20-Sep-2008 01:11
20-Sep-2008 01:11
The following is a function that will convert Unix Epoch to date format string.
<?PHP
// Function by Jonathan C Newcomb
function unix_to_date($date_format, $unix_epoch){
// Get current server GMT
$gmt = date('P');
$gmt_split = explode(':', $gmt);
$gmt_offset = $gmt_split[0];
$ret = date($date_format, mktime(0 + ($gmt_offset),0, $unix_epoch, 1, 1, 1970));
return $ret;
}
?>
domi at lab-9 dot com
16-Sep-2008 12:14
16-Sep-2008 12:14
<?php
#
# retrieve total count of weeks in a year
#
# param: (int) $year the year in which you wanna get the week count; if not int (for example from date('Y') it is automatically casted
#
# --- NOTE:
# seen a lot of stuff around but nothing as fast;
# mktime() is a very performant operation and the loop
# is executed max 13 times
#
#
# see: http://www.php.net/mktime
# see: http://www.php.net/intval
#
function total_weeks($year) {
if(!is_int($year)) $year = intval($year);
$i=31;
while(date('w', mktime(23,59,59,12,$i,$year)) != 0) $i--;
return date('W', mktime(23,59,59,12,$i,$year));
}
?>
Anonymous
12-Sep-2008 06:01
12-Sep-2008 06:01
Correct format for a MySQL DATETIME column is
<?php $mysqltime = date ("Y-m-d H:i:s", $phptime); ?>
Cortexd
27-Aug-2008 11:47
27-Aug-2008 11:47
a date function supporting the milliseconds format character
<?php
function udate($format, $utimestamp = null)
{
if (is_null($utimestamp))
$utimestamp = microtime(true);
$timestamp = floor($utimestamp);
$milliseconds = round(($utimestamp - $timestamp) * 1000000);
return date(preg_replace('`(?<!\\\\)u`', $milliseconds, $format), $timestamp);
}
echo udate('H:i:s.u'); // 19:40:56.78128
echo udate('H:i:s.u', 654532123.04546); // 16:28:43.45460
?>
pdubbb1 at gmail dot com
26-Aug-2008 05:32
26-Aug-2008 05:32
here is the simpliest way to get the start and end date of the week;
<?php
$sdate=date('c',strtotime(date('Y')."W".date('W')."0"));
$edate=date('c',strtotime(date('Y')."W".date('W')."7"));
?>
the format is for the string in strtotime is;
2008W200
this stands for year - 2008, constant never changes - W, week number of the year - 20, day of the week - 0 for sunday, 1 for monday, etc....
so 2008W200 stands for the sunday of the 20th week of 2008.
This will only work in php 5 or better
rowe_a at glan-hafren dot ac dot uk
22-Aug-2008 02:16
22-Aug-2008 02:16
simple code to get the date of the monday and sunday of the current week.
inspired by: wulf dot kaiser at mpimf-heidelberg dot mpg dot de
<?
$day = date('d');
$wkday = date('l');
$month = date('m');
$year = date('Y');
switch($wkday) {
case 'Monday': $numDaysToSun = 6; $numDaysToMon = 0; break;
case 'Tuesday': $numDaysToSun = 5; $numDaysToMon = 1; break;
case 'Wednesday': $numDaysToSun = 4; $numDaysToMon = 2; break;
case 'Thursday': $numDaysToSun = 3; $numDaysToMon = 3; break;
case 'Friday': $numDaysToSun = 2; $numDaysToMon = 4; break;
case 'Saturday': $numDaysToSun = 1; $numDaysToMon = 5; break;
case 'Sunday': $numDaysToSun = 0; $numDaysToMon = 6; break;
}
echo $wkday;
echo " - ";
echo $day;
echo " - ";
echo $month;
echo " - ";
echo $year;
echo " - ";
echo $numDaysToSun;
echo " - ";
echo $numDaysToMon;
echo " - ";
echo $monday = date('d-m-Y', mktime('0','0','0', $month, $day-$numDaysToMon, $year));
echo " - ";
echo $sunday = date('d-m-Y', mktime('0','0','0', $month, $day+$numDaysToSun, $year));
?>
headings:
Day(string) - day - month - year - days to sun - days from mon - monday date - sunday date
output:
Friday - 22 - 08 - 2008 - 2 - 4 - 18-08-2008 - 24-08-2008
abazaba.ru
14-Aug-2008 03:53
14-Aug-2008 03:53
All novices must be very carefull when working with timestamps as second values.
From first glance it looks like date("Y-m-d H:i:s",TIMESTAMP) will return correct date, based on "how much seconds gone from 1970".
But here is the feature, it'll be corrected time, according to LOCAL timezone.
So if you take a 25200 as timestamp (10 hours),
then on one server you'll get
1970-01-01 08:00:00
and on other server you'll get
1970-01-01 09:00:00
and so on.
Though you could expect 1970-01-01 10:00:00 in all cases, because if 25200 seconds gone from 1970-01-01 00:00:00 it obviously have to be 1970-01-01 10:00:00
I spend today 3 hours to correct scripts which were created with such error by previous programmer, so please, guys, don't make me work like this and remember about conversation to LOCAL time.
phprocks at aol dot com
06-Aug-2008 11:25
06-Aug-2008 11:25
Try this for finding the difference in days between 2 dates/datetimes... take note though, date_parse requires PHP version 5.1.3 or higher.
<?php
/**
* Finds the difference in days between two calendar dates.
*
* @param Date $startDate
* @param Date $endDate
* @return Int
*/
function dateDiff($startDate, $endDate)
{
// Parse dates for conversion
$startArry = date_parse($startDate);
$endArry = date_parse($endDate);
// Convert dates to Julian Days
$start_date = gregoriantojd($startArry["month"], $startArry["day"], $startArry["year"]);
$end_date = gregoriantojd($endArry["month"], $endArry["day"], $endArry["year"]);
// Return difference
return round(($end_date - $start_date), 0);
}
?>
laszlo72 at gmail dot com
28-Jul-2008 03:16
28-Jul-2008 03:16
if you want to get the number of month
between two dates
you can use this function:
<?php
/*
$start = "YYYYMM" ;
$stop = "YYYYMM" ;
*/
function getNumMonth($start,$stop) {
$aSta = substr($start,0,4) ;
$aSto = substr($stop,0,4) ;
$mSta = substr($start,4,2) ;
$mSto = substr($stop,4,2) ;
if($aSta == $aSto) {
return $mSto-$mSta+1 ;
} else {
if(($aSto-$aSta) == 1) {
return 12-$mSta+$mSto+1 ;
} else {
return (12-$mSta+$mSto+1)+($aSto-$aSta-1)*12;
}
}
}
?>
JonathanCross.com
25-Jul-2008 01:22
25-Jul-2008 01:22
<?php
// A demonstration of the new DateTime class for those
// trying to use dates before 1970 or after 2038.
?>
<h2>PHP 2038 date bug demo (php version <?= phpversion() ?>)</h1>
<div style='float:left;margin-right:3em;'>
<h3>OLD Buggy date()</h3>
<?
$format='F j, Y';
for ( $i = 1900; $i < 2050; $i++) {
$datep = "$i-01-01";
?>
Trying: <?=$datep?> = <?=date($format, strtotime($datep))?><br>
<?
}
?></div>
<div style='float:left;'>
<h3>NEW DateTime Class (v 5.2+)</h3><?
for ( $i = 1900; $i < 2050; $i++) {
$datep = "$i-01-01";
$date = new DateTime($datep);
?>
Trying: <?=$datep?> = <?=$date->format($format)?><br>
<?
}
?></div>
gertrude dot mendoza at gmail dot com
18-Jul-2008 12:41
18-Jul-2008 12:41
<?php
/*
@params $firstdate, $lastdate
@return array() of array(monday,sunday)
@description returns all the mondays and sundays of the given date range
*/
function get_week_intervals($fdate,$ldate)
{
list($year,$month,$day) = explode('-',$fdate);
$daynum = date('w',
mktime(date('H'),
date('i'),
date('s'),
$month,
$day,
$year)
);
$daynum = $daynum==0? 7 : $daynum;
$week=array();
//get the dayname of the first day
//if month = current month get the current date as the last day
if($month==date('m'))
{
$lastday = date('d');
}
else
{
$lastday = date('t', strtotime($fdate));
}
if((date('l',strtotime($fdate))) == 'Sunday')
{
$monday = $fdate;
$sunday = $fdate;
}
else
{
$monday = $fdate;
$sunday = date('Y-m-d',(mktime(date('H'),
date('i'),date('s'),$month,
$day,$year))-($daynum-7)*86400);
}
$week[] = array('monday'=>$monday,'sunday'=>$sunday);
$day = date('d',strtotime($sunday." +1 day"));
while($sunday < $ldate)
{
$monday = date('Y-m-d',strtotime($sunday." +1 day"));
list($year,$month,$day) = explode('-',$monday);
$daynum = date('w',
mktime(date('H'),
date('i'),
date('s'),
$month,
$day,
$year)
);
$daynum = $daynum==0? 7 : $daynum;
$sunday = date('Y-m-d',(mktime(date('H'),date('i'),
date('s'),$month,$day,$year))-($daynum-7)*86400);
if($sunday > $ldate)
{
$sunday = $ldate;
}
$week[] = array('monday'=>$monday,'sunday'=>$sunday);
}
return $week;
}
?>
Anonymous
17-Jul-2008 09:30
17-Jul-2008 09:30
to get the date of the monday from a week these function is useful:
<?php
/* Get First Calendar Week of Year x*/
function firstkw($jahr)
{
$erster = mktime(0,0,0,1,1,$jahr);
$wtag = date('w',$erster);
if ($wtag <= 4) {
/**
* Donnerstag oder kleiner: auf den Montag zurückrechnen.
*/
$montag = mktime(0,0,0,1,1-($wtag-1),$jahr);
} else {
/**
* auf den Montag nach vorne rechnen.
*/
$montag = mktime(0,0,0,1,1+(7-$wtag+1),$jahr);
}
return $montag;
}
/*GET timestamp of monday of month x*/
function mondaykw($kwtime)
{
$firstmonday =$this->firstkw(date("Y", $kwtime));
$mon_monat = date('m',$firstmonday);
$mon_jahr = date('Y',$firstmonday);
$mon_tage = date('d',$firstmonday);
$tage = (date("W", $kwtime)-1)*7;
$mondaykw = mktime(0,0,0,$mon_monat,$mon_tage+$tage,$mon_jahr);
return $mondaykw;
}
echo mondaykw(time()); //1215986400
?>
fgabrieli at gmail dot com
14-Jul-2008 12:56
14-Jul-2008 12:56
here is a function to split a number of seconds in hours, minutes and seconds
<?php
function split_seconds($seconds)
{
// get the minutes
$minutes = floor($seconds / 60) ;
$seconds_left = $seconds % 60 ;
// get the hours
$hours = floor($minutes / 60) ;
$minutes_left = $minutes % 60 ;
// (test) show the result
echo "$hours hours $minutes_left minutes and $seconds_left seconds" ;
}
split_seconds(68648) ;
?>
best regards
fernando gabrieli
shem_lexluger at yahoo.com
14-Jul-2008 05:43
14-Jul-2008 05:43
Assuming a week starts on Monday. To calculate the week number of the current date starting from a specified date, use this function:
<?php
function weekcounter($start_date)
{
$start_date = strtotime($start_date);
$today = strtotime(date('d-m-Y'));
$week = 1;
while($start_date < $today) {
$start_date = strtotime('next Monday', $start_date);
$week++;
}
return $week;
}
// Example:
//now = 14-07-2008
echo weekcounter('01-07-2008'); //prints 3
echo weekcounter('01-06-2008'); //prints 8 instead of 7; because 1st jun is a Sunday so it is week 1 and 2nd june is week 2. Feel free to tweak.
?>
Rob A.
10-Jul-2008 09:38
10-Jul-2008 09:38
Quick function for returning the names of the next 7 days of the week starting with today.
Returns an array that can be formatted to your liking.
<?php
/**
* Returns array of next 7 days starting with today
*
*/
function next_7_days() {
// create array of day names. You can change these to whatever you want
$days = array(
'Monday',
'Tuesday',
'Wednesday',
'Thursday',
'Friday',
'Saturday',
'Sunday');
$today = date('N');
for ($i=1;$i<$today;$i++) {
// take the first element off the array
$shift = array_shift($days);
// ... and add it to the end of the array
array_push($days,$shift);
}
// returns the sorted array
return $days;
}
?>
It basically takes an array starting with Monday and shifts each day to the end of the array until the first element in the array is today.
con_tobe at yahoo dot com
09-Jul-2008 08:46
09-Jul-2008 08:46
Doing $w-- for months ending on Sat won't hurt (i.e. if you're counting weeks as is the case below), but halocastle's code is perfectly fine as is and quite fast. He/she uses $w as a key for the $weeks array. "Halo" does this BEFORE $w++, so $w-- is superfluous as the loop has already ended. For May, 2008, I get 5 weeks as expected...
Array
(
[1] => Array
(
[4] => 1
[5] => 2
[6] => 3
)
[2] => Array
(
[0] => 4
[1] => 5
------------OMITTED-----------------
[4] => 22
[5] => 23
[6] => 24
)
[5] => Array
(
[0] => 25
[1] => 26
[2] => 27
[3] => 28
[4] => 29
[5] => 30
[6] => 31
)
)
I guess the one pit-fall of the code is if you overlap months, say the following year, then $m-- makes perfect since...I think (haven't gotten that far...yet).
I modified "Halo's" code to include months, too (this is from a snippet that produces a three month calendar, hence the outer $months loop, omitted here).
<?php
$m = date('m');
$Y = date('Y');
// for() {months loop omitted
$var_date = mktime(0, 0, 0, $m, 1, $Y);
$month_name = date('F', $var_date);
$months[$month_name]['DAYS'] = date('t', $var_date);
$months[$month_name]['FIRST_DAY'] = date('w', $var_date);
//}
foreach($months as $month => $key) {
$weeks = array();
for($i = 1, $j = $key['FIRST_DAY'], $w = 1;$i <= $key['DAYS'];$i++) {
$weeks[$w][$j] = $i;
$j++;
if($j == 7) {
$j = 0;
$w++;
}
}
$months[$month]['WEEKS'] = $weeks;
}
?>
Enjoy!
dmagick at gmail dot com
02-Jul-2008 07:44
02-Jul-2008 07:44
Slight amendment to halocastle at yahoo dot com 's code as it doesn't take into account when a month finishes on a Saturday (eg May 2008).
<?php
$start_date = mktime(0, 0, 0,$start_month, 1, $start_year);
$days_in_month = date('t', $start_date);
$month_first_day = date('w', $start_date);
$j = $month_first_day;
$num_weeks = 1;
for($i = 1; $i <= $days_in_month; $i++) {
$j++;
if($j == 7) {
$j = 0;
$num_weeks++;
}
}
// if the last day of the month happens to be a Saturday,
// take one off the number of weeks
// because it was being added inside the for loop.
if ($j == 0) {
$num_weeks--;
}
?>
halocastle at yahoo dot com
30-Jun-2008 09:20
30-Jun-2008 09:20
Weeks and days for any month/year combo:
<?php
$m = 2; // February
$Y = 2008;
// constants used here for legibility, use $vars for dynamicon...
define('MONTH_DAYS',date('t', strtotime(date($m . '/01/' . $Y))));
// w:0->6 = Sun->Sat
define('MONTH_FIRST_DAY',date('w', strtotime(date($m . '/01/' . $Y))));
for($i = 1, $j = MONTH_FIRST_DAY, $w = 1;$i <= MONTH_DAYS;$i++) {
$week[$w][$j] = $i;
$j++;
if($j == 7) {
$j = 0;
$w++;
}
}
?>
print_r($week):
-----------------------
Array
(
[1] => Array
(
[5] => 1
[6] => 2
)
[2] => Array
(
[0] => 3
[1] => 4
[2] => 5
[3] => 6
[4] => 7
[5] => 8
[6] => 9
)
[3] => Array
(
[0] => 10
[1] => 11
[2] => 12
[3] => 13
[4] => 14
[5] => 15
[6] => 16
)
[4] => Array
(
[0] => 17
[1] => 18
[2] => 19
[3] => 20
[4] => 21
[5] => 22
[6] => 23
)
[5] => Array
(
[0] => 24
[1] => 25
[2] => 26
[3] => 27
[4] => 28
[5] => 29
)
)
Kavi Siegel
29-Jun-2008 07:18
29-Jun-2008 07:18
I wrote the following function to show a series of drop down boxes to select the date. When provided with a timestamp, that date is selected by default, when none is provided, the current date is selected.
<?php
function chooseDate($timestamp = ""){
if($timestamp == ""){
$timestamp = time();
}
$months = array(null, 'Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec');
unset($months[0]);
print_r($months);
$out = '<select name="month">';
foreach($months as $key => $month){
if($month == date('M', $timestamp)){
$out .= '<option value="'.$key.'" selected="selected">'.$month.'</option>';
}else{
$out .= '<option value="'.$key.'">'.$month.'</option>';
}
}
$out .= '</select><select name="days">';
for($i = 1; $i <= 32; $i++){
if($i == date('j', $timestamp)){
$out .= '<option value="'.$i.'" selected="selected">'.$i.'</option>';
}else{
$out .= '<option value="'.$i.'">'.$i.'</option>';
}
}
$out .= "</select><select name='year'>";
for($i = date('Y'); $i >= 1970; $i--){
if($i == date('Y', $timestamp)){
$out .= '<option value="'.$i.'" selected="selected">'.$i.'</option>';
}else{
$out .= '<option value="'.$i.'">'.$i.'</option>';
}
}
$out .= "</select>";
return $out;
}
?>
Usage is simple:
<?php
echo chooseDate(); // Will select current date
echo chooseDate(1149566400); // Will select June 6th, 2006
?>
aplarsen
26-Jun-2008 01:12
26-Jun-2008 01:12
@anonymous (12-Jun-2008 08:45):
date("t") returns the last day of the month, not the last working day of the month.
A cleaner example would be as follows:
<?php
function lastworkingday($date)
{
for($lastday=mktime(0,0,0,date("m",$date),
date("t",$date),date("Y",$date));
date("w",$lastday)==0 || date("w",$lastday)==6;
$lastday-=60*60*24);
return date("j",$lastday);
}
?>
kontakt at arthur minus schiwon dot de
18-Jun-2008 03:29
18-Jun-2008 03:29
to get the week of the month simply use:
ceil( date("j") / 7 );
diego at diego dot eng dot br
09-Jun-2008 04:27
09-Jun-2008 04:27
I made a small code to get the last working day of the month:
<?php
$times = strtotime(date("Y")."-".date("m")."-".date("t"));
for ($lastworkingday=0;$lastworkingday==0;$times-=86400)
if (date("w",$times)!=0 && date("w",$times)!=6) $lastworkingday = date("j",$times);
print $lastworkingday;
?>
phil dot taylor at enilsson dot com
25-May-2008 10:37
25-May-2008 10:37
Found this helpful when converting unix dates for use with the ical file format.
<?php
// Converts a unix timestamp to iCal format (UTC) - if no timezone is
// specified then it presumes the uStamp is already in UTC format.
// tzone must be in decimal such as 1hr 45mins would be 1.75, behind
// times should be represented as negative decimals 10hours behind
// would be -10
function unixToiCal