err, the "($old = $var)" could also evaluate to false. Adding a "|| true" would make this overall to crude, I guess. It's better to leave it out of the expression.
Obsah
- Základy
- Předdefinované proměnné
- Kontext ("scope") proměnné
- Proměnné s proměnnými názvy
- Proměnné zvenčí PHP
Proměnné jsou v PHP reprezentovány znakem dolaru, následovaným názvem příslušné proměnné. V názvech proměnných se rozlišuje velikost písmen.
Názvy proměnných jsou podřízeny stejným pravidlům jako jiná návěští v PHP. Platný název proměnné začíná písmenem nebo podtržítkem, následovaným libovolným počtem písmen, číslic nebo potržítek. Jako regulární výraz to lze zapsat takto: '[a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*'
Poznámka: Pro naše účely zde budeme za písmena považovat znaky a-z, A-Z a ASCII znaky od 127 do 255 (0x7f-0xff).
$var = "Bob";
$Var = "Joe";
echo "$var, $Var"; // vypíše "Bob, Joe"
$4site = 'not yet'; // neplatné; začíná číslicí
$_4site = 'not yet'; // platné; začíná podtržítkem
$täyte = 'mansikka'; // platné; 'ä' je ASCII 228.
V PHP 3 mají proměnné vždy přiřazenu hodnotu. To znamená, že když přiřadíte výraz do proměnné, celá hodnota původního výrazu se zkopíruje do cílové proměnné. Tedy, například, po přiřazení hodnoty jedné proměnné do druhé, změna jedné z nich se na druhé neprojeví. Více informací o tomto způsobu přiřazení viz Výrazy.
PHP nabízí jiný způsob přiřazení hodnot proměnným: přiřazení odkazu. To znamená, že nová proměnná jednoduše odkazuje (jinými slovy, "stává se aliasem" nebo "ukazuje na") na původní proměnnou. Změny na nové proměnné se projeví na té původní a naopak. To také znamená, že se nic nekopíruje; proto je přiřazení rychlejší. Avšak toto zrychlení bude zjistitelné pouze v těsných cyklech nebo při přiřazování velkých polí či objektů.
Pro přiřazení odkazu stačí jednoduše před proměnnou, která bude přiřazována (zdrojová proměnná), předřadit ampersand (&). Například následující kus kódu vypíše dvakrát 'Jmenuji se Bob':
<?php
$foo = 'Bob'; // Přiřadí hodnotu 'Bob' do $foo
$bar = &$foo; // Odkaz $foo přes $bar.
$bar = "Jmenuji se $bar"; // Změna $bar...
echo $bar;
echo $foo; // $foo je také změněno.
?>
Jednou z důležitých věcí, které je třeba si uvědomit, je to, že přes odkazy lze přiřazovat pouze pojmenované proměnné.
<?php
$foo = 25;
$bar = &$foo; // Toto je platné přiřazení.
$bar = &(24 * 7); // Neplatné; odkazuje se nepojmenovaný výraz.
function test()
{
return 25;
}
$bar = &test(); // Neplatné.
?>
Proměnné
15-Feb-2008 07:00
15-Feb-2008 04:22
@cgorbit: This does not work, because "=" has a lower operator precedence than "||". The expression "($var = $old || true)" assigns true to $var. I corrected this and further shortened the function by putting "$old = $var" into the expression, too. :)
Note the parentheses that are necessary because of the operator precedence of "=" and "&&".
function var_name(&$var, $scope=0)
{
if (($old = $var) && ($key = array_search($var = 'unique'.rand().'value', !$scope ? $GLOBALS : $scope)) && (($var = $old) || true)) return $key;
}
05-Jan-2008 03:34
<?php
function var_name(&$var, $scope=0)
{
$old = $var;
if (($key = array_search($var = 'unique'.rand().'value', !$scope ? $GLOBALS : $scope)) && ($var = $old || true)) return $key;
}
?>
Because $var may casts to false
06-Jul-2007 09:13
Here's a simple solution for retrieving the variable name, based on the lucas (http://www.php.net/manual/en/language.variables.php#49997) solution, but shorter, just two lines =)
<?php
function var_name(&$var, $scope=0)
{
$old = $var;
if (($key = array_search($var = 'unique'.rand().'value', !$scope ? $GLOBALS : $scope)) && $var = $old) return $key;
}
?>
20-Feb-2007 08:48
As an addendum to David's 10-Nov-2005 posting, remember that curly braces literally mean "evaluate what's inside the curly braces" so, you can squeeze the variable variable creation into one line, like this:
<?php
${"title_default_" . $title} = "selected";
?>
and then, for example:
<?php
$title_select = <<<END
<select name="title">
<option>Select</option>
<option $title_default_Mr value="Mr">Mr</option>
<option $title_default_Ms value="Ms">Ms</option>
<option $title_default_Mrs value="Mrs">Mrs</option>
<option $title_default_Dr value="Dr">Dr</option>
</select>
END;
?>
25-Jan-2007 02:10
Here's a pair of functions to encode/decode any string to be a valid php and javascript variable name.
<?php
function label_encode($txt) {
// add Z to the begining to avoid that the resulting
// label is a javascript keyword or it starts with a
// number
$txt = 'Z'.$txt;
// encode as urlencoded data
$txt = rawurlencode($txt);
// replace illegal characters
$illegal = array('%', '-', '.');
$ok = array('é', 'è', 'à');
$txt = str_replace($illegal,$ok, $txt);
return $txt;
}
function label_decode($txt) {
// replace illegal characters
$illegal = array('%', '-', '.');
$ok = array('é', 'è', 'à');
$txt = str_replace($ok, $illegal, $txt);
// unencode
$txt = rawurldecode($txt);
// remove the leading Z and return
return substr($txt,1);
}
?>
28-Dec-2006 10:14
what is so simple and flexible about these variable..? They're all the same thing -.-"
$var = whatever;
in fact is more complicated than:
String HelloWorld = hello;
04-Aug-2006 01:44
With php 5.1.4 (and maybe earlier?) take care about not using $this as a variable name, even when in the global scope or inside a plain function: the engine will prevent assigning any value to it...
20-May-2006 05:44
Simple sample and variables and html "templates":
The PHP code:
variables.php:
<?php
$SYSN["title"] = "This is Magic!";
$SYSN["HEADLINE"] = "Ez magyarul van"; // This is hungarian
$SYSN["FEAR"] = "Bell in my heart";
?>
index.php:
<?php
include("variables.php");
include("template.html");
?>
The template:
template.html
<html>
<head><title><?=$SYSN["title"]?></title></head>
<body>
<H1><?=$SYSN["HEADLINE"]?></H1>
<p><?=$SYSN["FEAR"]?></p>
</body>
</html>
This is simple, quick and very flexibile
27-Dec-2005 11:11
> Variable names follow the same rules as other labels in PHP. A valid variable name starts with a letter or underscore, followed by any number of letters, numbers, or underscores. As a regular expression, it would be expressed thus: '[a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*'
..is not quite true. You can, in fact, only declare variables having a name like this if you use the syntax <?php $varname = "naks naks"; ?>.. but in fact a variable can have moreless any name that is a string... e.g. if you look at an array you can have
<?php
$arr[''];
$arr['8'];
$arr['-my-element-is-so-pretty-useless-'];
?>
.. by accessing the variables-namespace via {} you can have the same functinalities for all variables, e.g.
<?php ${''} = "my empty variable"; ?>
is a valid expression and the variable having the empty string as name will have the value "my empty variable".
read the chapter on "variable variables" for further information.
25-Nov-2005 02:03
References and "return" can be flakey:
<?php
// This only returns a copy, despite the dereferencing in the function definition
function &GetLogin ()
{
return $_SESSION['Login'];
}
// This gives a syntax error
function &GetLogin ()
{
return &$_SESSION['Login'];
}
// This works
function &GetLogin ()
{
$ret = &$_SESSION['Login'];
return $ret;
}
?>
10-Nov-2005 01:25
When using variable variables this is invalid:
$my_variable_{$type}_name = true;
to get around this do something like:
$n="my_variable_{$type}_name";
${$n} = true;
(or $$n - I tend to use curly brackets out of habit as it helps t reduce bugs ...)
13-Oct-2005 04:33
On the previous note:
This is due to how evaluation works. PHP will think of it as:
$a = whatever $b = $c is
$b = whatever $c = 1 is
... because an expression is equal to what it returns.
Therefore $c = 1 returns 1, making $b = $c same as $b = 1, which makes $b 1, which makes $a be $b, which is 1.
$a = ($b = $c = 1) + 2;
Will have $a be 3 while $b and $c is 1.
Hope that clears something up.
31-Aug-2005 05:09
Variables can also be assigned together.
<?php
$a = $b = $c = 1;
echo $a.$b.$c;
?>
This outputs 111.
09-Jul-2005 11:46
In conditional assignment of variables, be careful because the strings may take over the value of the variable if you do something like this:
<?php
$condition = true;
// Outputs " <-- That should say test"
echo "test" . ($condition) ? " <-- That should say test" : "";
?>
You will need to enclose the conditional statement and assignments in parenthesis to have it work correctly:
<?php
$condition = true;
// Outputs "test <-- That should say test"
echo "test" . (($condition) ? " <-- That should say test " : "");
?>
17-May-2005 01:06
As with echo, you can define a variable like this:
<?php
$text = <<<END
<table>
<tr>
<td>
$outputdata
</td>
</tr>
</table>
END;
?>
The closing END; must be on a line by itself (no whitespace).
01-May-2005 05:17
pay attention using spaces, dots and parenthesis in case kinda like..
$var=($number>0)?1.'parse error':0.'here too';
the correct form is..
$var=($number>0)?1 .'parse error':0 .'here too';
or
$var=($number>0)?(1).'parse error':(0).'here too';
or
$var = ($number > 0) ? 1 . 'parse error' : 0 . 'here too';
etc..
i think that's why the parser read 1. and 0. like decimal numbers not correctly written, point of fact
$var=$number>0?1.0.'parse error':0.0.'here too';
seems to work correctly..
25-Apr-2005 04:01
When constructing strings from text and variables you can use curly braces to "demarcate" variables from any surrounding text where, for whatever reason, you cannot use a space eg:
$str="Hi my name is ${bold}$name bla-bla";
which AFAIK is the same as
$str="Hi my name is {$bold}$name bla-bla";
zzapper
07-Apr-2005 09:18
In addition to what jospape at hotmail dot com and ringo78 at xs4all dot nl wrote, here's the sintax for arrays:
<?php
//considering 2 arrays
$foo1 = array ("a", "b", "c");
$foo2 = array ("d", "e", "f");
//and 2 variables that hold integers
$num = 1;
$cell = 2;
echo ${foo.$num}[$cell]; // outputs "c"
$num = 2;
$cell = 0;
echo ${foo.$num}[$cell]; // outputs "d"
?>
14-Feb-2005 04:42
Here's a function to get the name of a given variable. Explanation and examples below.
<?php
function vname(&$var, $scope=false, $prefix='unique', $suffix='value')
{
if($scope) $vals = $scope;
else $vals = $GLOBALS;
$old = $var;
$var = $new = $prefix.rand().$suffix;
$vname = FALSE;
foreach($vals as $key => $val) {
if($val === $new) $vname = $key;
}
$var = $old;
return $vname;
}
?>
Explanation:
The problem with figuring out what value is what key in that variables scope is that several variables might have the same value. To remedy this, the variable is passed by reference and its value is then modified to a random value to make sure there will be a unique match. Then we loop through the scope the variable is contained in and when there is a match of our modified value, we can grab the correct key.
Examples:
1. Use of a variable contained in the global scope (default):
<?php
$my_global_variable = "My global string.";
echo vname($my_global_variable); // Outputs: my_global_variable
?>
2. Use of a local variable:
<?php
function my_local_func()
{
$my_local_variable = "My local string.";
return vname($my_local_variable, get_defined_vars());
}
echo my_local_func(); // Outputs: my_local_variable
?>
3. Use of an object property:
<?php
class myclass
{
public function __constructor()
{
$this->my_object_property = "My object property string.";
}
}
$obj = new myclass;
echo vname($obj->my_object_property, $obj); // Outputs: my_object_property
?>
04-Feb-2005 11:45
$id = 2;
$cube_2 = "Test";
echo ${cube_.$id};
// will output: Test
14-Jan-2005 12:27
<?
// I am beginning to like curly braces.
// I hope this helps for you work with them
$filename0="k";
$filename1="kl";
$filename2="klm";
$i=0;
for ($varname = sprintf("filename%d",$i); isset ( ${$varname} ) ; $varname = sprintf("filename%d", $i) ) {
echo "${$varname} <br>";
$varname = sprintf("filename%d",$i);
$i++;
}
?>
07-Jan-2005 03:02
You can also construct a variable name by concatenating two different variables, such as:
<?
$arg = "foo";
$val = "bar";
//${$arg$val} = "in valid"; // Invalid
${$arg . $val} = "working";
echo $foobar; // "working";
//echo $arg$val; // Invalid
//echo ${$arg$val}; // Invalid
echo ${$arg . $val}; // "working"
?>
Carel
25-May-2004 10:58
<?php
error_reporting(E_ALL);
$name = "Christine_Nothdurfter";
// not Christine Nothdurfter
// you are not allowed to leave a space inside a variable name ;)
$$name = "'s students of Tyrolean language ";
print " $name{$$name}<br>";
print "$name$Christine_Nothdurfter";
// same
?>
09-Mar-2004 12:31
OK how about a practicle use for this:
You have a session variable such as:
$_SESSION["foo"] = "bar"
and you want to reference it to change it alot throughout the program instaed of typing the whole thing over and over just type this:
$sess =& $_SESSION
$sess['foo'] = bar;
echo $sess['foo'] // returns bar
echo $_SESSION["foo"] // also returns bar
just saves alot of time in the long run
also try $get = $HTTP_GET_VARS
or $post = $HTTP_POST_VARS
20-Jan-2004 08:15
In reference to "remco at clickbizz dot nl"'s note I would like to add that you don't necessarily have to escape the dollar-sign before a variable if you want to output it's name.
You can use single quotes instead of double quotes, too.
For instance:
<?php
$var = "test";
echo "$var"; // Will output the string "test"
echo "\$var"; // Will output the string "$var"
echo '$var'; // Will do the exact same thing as the previous line
?>
Why?
Well, the reason for this is that the PHP Parser will not attempt to parse strings encapsulated in single quotes (as opposed to strings within double quotes) and therefore outputs exactly what it's being fed with :)
To output the value of a variable within a single-quote-encapsulated string you'll have to use something along the lines of the following code:
<?php
$var = 'test';
/*
Using single quotes here seeing as I don't need the parser to actually parse the content of this variable but merely treat it as an ordinary string
*/
echo '$var = "' . $var . '"';
/*
Will output:
$var = "test"
*/
?>
HTH
- Daerion
14-Jan-2003 06:37
References are great if you want to point to a variable which you don't quite know the value yet ;)
eg:
$error_msg = &$messages['login_error']; // Create a reference
$messages['login_error'] = 'test'; // Then later on set the referenced value
echo $error_msg; // echo the 'referenced value'
The output will be:
test
