ftp_fput

(PHP 4, PHP 5)

ftp_fput — Übertragt eine geöffnete Datei auf einen FTP-Server (upload)

Beschreibung:

int ftp_fput ( int $ftp_stream , string $remote_file , int $fp , int $mode )

Gibt bei Erfolg TRUE zurück, im Fehlerfall FALSE.

ftp_fput() übertragt das per Datei-Zeiger fp benannte und geöffnete File zum FTP-Server. Die übertragenen Daten werden in der über remote_file bestimmten Datei auf dem FTP-Server gespeichert. Der mode -Übertragungs-Parameter muss entweder FTP_ASCII oder FTP_BINARY sein.

ftp_get_option

ftp_fget

Last updated: Fri, 22 Aug 2008

add a note User Contributed Notes
ftp_fput

jopi paranoid fi
20-May-2008 12:57


When you have your file contents as a string, create temporary stream and use that as a file handle.



<?php



$contents = "This is a test file\nTesting 1,2,3..";



$tempHandle = fopen('php://temp', 'r+');

fwrite($tempHandle, $contents);

rewind($tempHandle);        



ftp_fput($this->ftp, $filename, $tempHandle, FTP_ASCII);



?>

Charlie Brown
16-Apr-2008 02:19


Fails if destination file exists. Delete first and it works.

info at daniel-marschall dot de
19-Apr-2006 12:04


This is a function i wrote to copy a complete directory to a FTP-Server-folder.



function ftp_uploaddirectory($conn_id, $local_dir, $remote_dir)

{

  @ftp_mkdir($conn_id, $remote_dir);

  $handle = opendir($local_dir);

  while (($file = readdir($handle)) !== false)

  {

    if (($file != '.') && ($file != '..'))

    {

      if (is_dir($local_dir.$file))

      {

        ftp_uploaddirectory($conn_id, $local_dir.$file.'/', $remote_dir.$file.'/');

      }

      else

        $f[] = $file;

    }

  }

  closedir($handle);

  if (count($f))

  {

    sort($f);

    @ftp_chdir($conn_id, $remote_dir);

    foreach ($f as $files)

    {

      $from = @fopen("$local_dir$files", 'r');

      @ftp_fput($conn_id, $files, $from, FTP_BINARY);

    }

  }

}



Example:



$conn_id = @ftp_connect($server);

@ftp_login ($conn_id, $username, $passwort);

ftp_uploaddirectory($conn_id, 'mydirectory/', 'theftpdirectory/');

@ftp_quit($conn_id);



I hope you'll find it useful.

BobFrank <rsfranc at yahoo dot com dot br>
23-Aug-2003 09:10


FTP upload server 2 server

<?php

$FTP_HOST ="ftp.br.geocities.com"; 

$FTP_USER ="bobfrank";

$FTP_PW   ="mypasswd";

$FTP_ROOT_DIR="/";

$LOCAL_SERVER_DIR  = "images/";

$FTP_DIR = "mydir/";

$handle=opendir($LOCAL_SERVER_DIR);

while (($file = readdir($handle))!==false)

{

    if(!is_dir($file)){

        $f[]="$file";        

      }

}

closedir($handle);

sort($f);

$count=0;

$mode = FTP_BINARY; // or FTP_ASCII

$conn_id = ftp_connect($FTP_HOST); 

if(ftp_login($conn_id, $FTP_USER, $FTP_PW)){

    print "from: ".$LOCAL_SERVER_DIR."<br>";

    print "to: ".$FTP_HOST.$FTP_ROOT_DIR.$FTP_DIR."<br>";

    ftp_pwd($conn_id);

    ftp_mkdir($conn_id,$FTP_DIR);

    ftp_chdir($conn_id,$FTP_DIR); 

    foreach($f as $files) {

        $from = fopen($LOCAL_SERVER_DIR.$files,"r");     

        if(ftp_fput($conn_id, $files, $from, $mode)){

            $count +=1;

            print $files."<br>";

        }

    }

    ftp_quit($conn_id);

}

print "upload : $count files.";

?>

darian lassan at yahoo de
04-Feb-2003 10:00


If you want to pass a string containing the filename as source and not a resource handle use ftp_put() instead. Trivial but not mentioned here.

add a note

ftp_get_option

ftp_fget

Last updated: Fri, 22 Aug 2008