This function will generate an error and return NULL instead FALSE in the next example:
<?php
$var = 3;
var_dump(get_resource_type($var));
?>
get_resource_type
(PHP 4 >= 4.0.2, PHP 5)
get_resource_type — Returns the resource type
Description
string get_resource_type
( resource
$handle
)This function gets the type of the given resource.
Parameters
-
handle -
The evaluated resource handle.
Return Values
If the given handle is a resource, this function
will return a string representing its type. If the type is not identified
by this function, the return value will be the string
Unknown.
This function will return FALSE and generate an error if
handle is not a resource.
Examples
Example #1 get_resource_type() example
<?php
// prints: mysql link
$c = mysql_connect();
echo get_resource_type($c) . "\n";
// prints: file
$fp = fopen("foo", "w");
echo get_resource_type($fp) . "\n";
// prints: domxml document
$doc = new_xmldoc("1.0");
echo get_resource_type($doc->doc) . "\n";
?>
avp200681 at gmail dot com ¶
1 year ago
hessodreamy at gmail dot com ¶
5 years ago
Furthermore, this function returns 'stream' on php 4.3 on windows & linux.
You if you want to differentiate between a file resource and other stream resources, as stated before stream_get_meta_data() gives you an array which, on my system, contains the following elements which might suggest a file handle:
[wrapper_type] => plainfile
[stream_type] => STDIO
However I've only compared this to a stream from a url, so I include this only as a suggestion.
jdhawk _at_ gmail ¶
7 years ago
In PHP5 (on Linux), the above example identifies the "file" handler as a 'stream', not 'file'.
This can be particularly worrisome if you're trying to determine the type of stream using this function.
The alternative is to use <?php stream_get_meta_data() ?>, which returns an array containing "stream_type (string) - a label describing the underlying implementation of the stream."
