<?php
// quick & dirty way to barricade your code during version transitions
assert('version_compare("5", PHP_VERSION, "<"); // requires PHP 5 or higher');
?>
version_compare
(PHP 4 >= 4.0.7, PHP 5)
version_compare — Compares two "PHP-standardized" version number strings
Description
version_compare() compares two "PHP-standardized" version number strings. This is useful if you would like to write programs working only on some versions of PHP.
The function first replaces _, - and + with a dot . in the version strings and also inserts dots . before and after any non number so that for example '4.3.2RC1' becomes '4.3.2.RC.1'. Then it splits the results like if you were using explode('.', $ver). Then it compares the parts starting from left to right. If a part contains special version strings these are handled in the following order: dev < alpha = a < beta = b < RC < pl. This way not only versions with different levels like '4.1' and '4.1.2' can be compared but also any PHP specific version containing development state.
Parameters
- version1
-
First version number.
- version2
-
Second version number.
- operator
-
If you specify the third optional operator argument, you can test for a particular relationship. The possible operators are: <, lt, <=, le, >, gt, >=, ge, ==, =, eq, !=, <>, ne respectively.
This parameter is case-sensitive, so values should be lowercase.
Return Values
By default, version_compare() returns -1 if the first version is lower than the second, 0 if they are equal, and 1 if the second is lower.
When using the optional operator argument, the function will return TRUE if the relationship is the one specified by the operator, FALSE otherwise.
Examples
The examples below use the PHP_VERSION constant, because it contains the value of the PHP version that is executing the code.
Example #1 version_compare() examples
<?php
if (version_compare(PHP_VERSION, '6.0.0') === 1) {
echo 'I am at least PHP version 6.0.0, my version: ' . PHP_VERSION . "\n";
}
if (version_compare(PHP_VERSION, '5.3.0') === 1) {
echo 'I am at least PHP version 5.3.0, my version: ' . PHP_VERSION . "\n";
}
if (version_compare(PHP_VERSION, '5.0.0', '>')) {
echo 'I am using PHP 5, my version: ' . PHP_VERSION . "\n";
}
if (version_compare(PHP_VERSION, '5.0.0', '<')) {
echo 'I am using PHP 4, my version: ' . PHP_VERSION . "\n";
}
?>
Notes
Note: The PHP_VERSION constant holds current PHP version.
Note: Note that pre-release versions, such as 5.3.0-dev, are considered lower than their final release counterparts (like 5.3.0).
version_compare
07-Mar-2008 10:54
30-Oct-2007 02:18
It should be noted that version_compare() considers 1 < 1.0 < 1.0.0 etc. I'm guessing this is due to the left-to-right nature of the algorithm.
30-Oct-2007 08:38
I know this is somewhat incomplete, but it did a fair enough job for what I needed. I was writing some code that needed done immediately on a server that was to be upgraded some time in the future. Here is a quick replacement for version_compare (without the use of the operator argument). Feel free to add to this / complete it.
<?php
function version_compare2($version1, $version2)
{
$v1 = explode('.',$version1);
$v2 = explode('.',$version2);
if ($v1[0] > $v2[0])
$ret = 1;
else if ($v1[0] < $v2[0])
$ret = -1;
else // Major ver are =
{
if ($v1[1] > $v2[1])
$ret = 1;
else if ($v1[1] < $v2[1])
$ret = -1;
else // Minor ver are =
{
if ($v1[2] > $v2[2])
$ret = 1;
else if ($v1[2] < $v2[2])
$ret = -1;
else
$ret = 0;
}
}
return $ret;
}
?>
10-Jun-2007 05:01
Something that may trip some folks up, but is useful to mention is that the following version comparison does not work quite as I expected:
version_compare('1.0.1', '1.0pl1', '>')
However, its quite easy to get working:
version_compare('1.0.1', '1.0.0pl1', '>')
29-Sep-2004 02:28
If you're careful, this function actualy works quite nicely for comparing version numbers from programs other than PHP itself. I've used it to compare MySQL version numbers. The only issue is that version_compare doesn't recognize the 'gamma' addition that mysql uses as being later than 'alpha' or 'beta', because the latter two are treated specially. If you keep this in mind though, you should have no problems.
30-Jun-2004 07:40
Here's a wrapper which is more tolerant as far as order of arguments is considered:
<?php
function ver_cmp($arg1, $arg2 = null, $arg3 = null) {
static $phpversion = null;
if ($phpversion===null) $phpversion = phpversion();
switch (func_num_args()) {
case 1: return version_compare($phpversion, $arg1);
case 2:
if (preg_match('/^[lg][te]|[<>]=?|[!=]?=|eq|ne|<>$/i', $arg1))
return version_compare($phpversion, $arg2, $arg1);
elseif (preg_match('/^[lg][te]|[<>]=?|[!=]?=|eq|ne|<>$/i', $arg2))
return version_compare($phpversion, $arg1, $arg2);
return version_compare($arg1, $arg2);
default:
$ver1 = $arg1;
if (preg_match('/^[lg][te]|[<>]=?|[!=]?=|eq|ne|<>$/i', $arg2))
return version_compare($arg1, $arg3, $arg2);
return version_compare($arg1, $arg2, $arg3);
}
}
?>
It also uses phpversion() as a default version if only one string is present. It can make your code look nicer 'cuz you can now write:
<?php if (ver_cmp($version1, '>=', $version2)) something; ?>
and to check a version string against the PHP's version you might use:
<?php if (ver_cmp('>=', $version)) something; ?>
instead of using phpversion().
21-Jun-2004 09:50
[editors note]
snipbit fixed after comment from Matt Mullenweg
--jm
[/editors note]
so in a nutshell... I believe it works best like this:
<?php
if (version_compare(phpversion(), "4.3.0", ">=")) {
// you're on 4.3.0 or later
} else {
// you're not
}
?>
23-May-2004 11:18
Actually, it works to any degree:
<?php
version_compare('1.2.3.4RC7.7', '1.2.3.4RC7.8')
version_compare('8.2.50.4', '8.2.52.6')
?>
will both give -1 (ie the left is lower than the right).
