(PHP 4 >= 4.2.0, PHP 5)

is_infiniteیافتن بینهایت بودن مقدار


bool is_infinite ( float $val )

بازگرداندن TRUE اگر val بینهایت باشد (مثبت یا منفی) مانند نتیجه log(0) یا هر مقدار بزرگ برای جاگذاری در مقدار ممیز شناور این پلتفرم.



مقدار برای بررسی

Return Values

TRUE اگر val بینهایت باشد در غیر این صورت FALSE.

See Also

  • is_finite() - Finds whether a value is a legal finite number
  • is_nan() - یافتن عدد بودن یک مقدار

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User Contributed Notes 5 notes

13 years ago
If you have PHP lower than 4.2 you can simulate the behaviour:

function is_infinite($value) {
   return (substr("$value",-3) == "INF");

(tested on php 4.1.2)
stangelanda at arrowquick dot com
10 years ago
Actually any string ending in INF is more appropriate than any string beginning with INF.  Since negative infinity evaluates to "-INF" but it is still infinite.  However in either case the STRING "INF" is not infinite, only a float that converts to "INF" or "-INF" is infinite.

A more appropriate function might be:
if (!is_defined('is_infinite')) { function is_infinite($val) {
    return (
is_float($val) and ("$val"=='INF' or "$val"=='-INF'));
} }
* However the above function is untested.
11 years ago
@ david,

That will return true for any string ending with "INF".
I think substr("$value",0,3) would be more appropriate.
espertalhao04 at hotmail dot com
4 years ago
fastest version to php <4.2:
<?php function is_infinite($v){$v=$v>>0;return -9e1000==$v||$v==9e1000;}; ?>

the $v=$v>>0; is just to ensure it is a number and its not mandatory.
effectively, the function can be reduced to:
<?php function is_infinite($v){return -9e1000==$v||$v==9e1000;}; ?>

this works because any number that is too big or too small for a float is considered to be infinite or -infinite.
5 years ago
PHP_INT_MAX is The largest integer supported in this build of PHP. Usually int(2147483647). Available since PHP 4.4.0 and PHP 5.0.5
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