If you want to get the relative path of an included file, from within itself use this function. If you ever have a include file thats path may not be static, this can save some time.
<?php
function get_current_files_path($file_name)
{
//find the current files directory
$includes = get_included_files();
$path = "";
for ($i=0; $i < count($includes); $i++)
{
$path = strstr($includes[$i], $file_name);
if ($path != false)
{
$key = $i;
break;
}
}
$path = str_replace(getcwd(), "", $includes[$key]);
$path = str_replace("\\", "/", $path);
$path = str_replace($file_name, "", $path);
$path = ltrim($path, "/");
return $path;
}
?>
get_included_files
(PHP 4, PHP 5)
get_included_files — Retourne un tableau avec les noms des fichiers qui sont inclus dans un script
Description
Retourne un tableau contenant les noms de tous les fichiers qui ont été ajoutés au script avec les fonctions require_once(), include_once(), require() ou include().
Valeurs de retour
Retourne un tableau contenant les noms de tous les fichiers.
Le script en cours est considéré comme fichier inclus, il sera donc listé avec les autres fichiers.
Les fichiers inclus ou requis plusieurs fois ne s'affichent qu'une fois dans le tableau retourné.
Historique
| Version | Description |
|---|---|
| 4.0.1 | En PHP 4.0.1 et inférieure, cette fonction supposait que les fichiers requis utilisait l'extension .php ; les autres extensions ne fonctionnaient pas. Par ailleurs, dans cette version, le tableau retourné par la fonction get_included_files() était un tableau associatif et ne reprenait que les fichiers ajoutés avec include() et include_once(). |
Exemples
Exemple #1 Exemple avec get_included_files()
<?php
// Ce fichier est abc.php
include 'test1.php';
include_once 'test2.php';
require 'test3.php';
require_once 'test4.php';
$included_files = get_included_files();
foreach ($included_files as $filename) {
echo "$filename\n";
}
?>
L'exemple ci-dessus va afficher :
abc.php test1.php test2.php test3.php test4.php
Notes
Note: Les fichiers inclus en utilisant la directive de configuration auto_prepend_file ne sont pas listés.
Voir aussi
- include() - include
- include_once() - include_once
- require() - require
- require_once() - require_once
- get_required_files() - Alias de get_included_files
get_included_files
23-Jun-2008 04:47
29-May-2008 08:57
If you want to avoid the filepaths, just wrap get_included_files() inside preg_replace() to get rid of path info:
<?php
$filenames = preg_replace("/\/.*\//", "", get_included_files());
?>
04-Jul-2007 03:27
If you have a MAIN php script which you don't want to be included by other scripts, you could use this function. For example:
main.php:
<?php
function blockit()
{
$buf = get_included_files();
return $buf[0] != __FILE__;
}
blockit() and exit("You can not include a MAIN file as a part of your script.");
print "OK";
?>
So other script couldn't include main.php to modify its internal global vars.
28-Aug-2006 05:30
Something that's not noted in the docs, if a file is included remotely and you do a get_included_files() in the include itself it will *not* return the document that included it.
ie:
test2.php (server 192.168.1.14):
<?php
include("http://192.168.1.11/test/test3.php");
?>
test3.php (server 192.168.1.11):
<?php
$files = get_included_files();
print_r($files);
?>
returns:
Array ( [0] => /var/www/localhost/htdocs/test/test3.php )
Which means you can use get_included_files() to help intercept and prevent XSS-style attacks against your code.
08-Mar-2006 04:04
As is often the case, YMMV. I tried the __FILE__ and SCRIPT_FILENAME comparison and found this:
SCRIPT_FILENAME: /var/www/cgi-bin/php441
__FILE__: /raid/home/natpresch/natpresch/RAY_included.php
As an alternative:
count(get_included_files());
Gives one when the script is standalone and always more than one when the script is included.
07-Sep-2004 09:08
As of PHP5, this function seems to return an array with the first index being the script all subsequent scripts are included to.
If index.php includes b.php and c.php and calls get_included_files(), the returned array looks as follows:
index.php
a.php
b.php
while in PHP<5 the array would be:
a.php
b.php
If you want to know which is the script that is including current script you can use $_SERVER['SCRIPT_FILENAME'] or any other similar server global.
If you also want to ensure current script is being included and not run independently you should evaluate following expression:
__FILE__ != $_SERVER['SCRIPT_FILENAME']
If this expression returns TRUE, current script is being included or required.
