mysqli->field_count

mysqli_field_count

(PHP 5)

mysqli->field_count -- mysqli_field_count — Retourne le nombre de colonnes pour la dernière requête

Description

Style orienté objet :

mysqli_result

int $field_count;

Style procédural :

int mysqli_field_count ( mysqli $link )

Retourne le nombre de colonnes pour la dernière requête sur la connexion spécifiée par le paramètre link . Cette fonction peut être utile lors de l'utilisation de mysqli_store_result() pour déterminer si la requête aurait du retourner un résultat vide ou non, sans en connaître la nature.

Liste de paramètres

link: Style procédural uniquement : Un identifiant de lien retourné par la fonction mysqli_connect() ou par la fonction mysqli_init()

Valeurs de retour

Un entier représentant le nombre de champs dans un jeu de résultats.

Exemples

Exemple #1 Style orienté objet


<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "test");

$mysqli->query( "DROP TABLE IF EXISTS friends");
$mysqli->query( "CREATE TABLE friends (id int, name varchar(20))");

$mysqli->query( "INSERT INTO friends VALUES (1,'Hartmut'), (2, 'Ulf')");


$mysqli->real_query($HTTP_POST_VARS['query']);

if ($mysqli->field_count) {
    /* Une requête SELECT, SHOW ou DESCRIBE */
    $result = $mysqli->store_result();

    /* Récupération du jeu de résultats */
    $row = $result->fetch_row();

    /* Libération du jeu de résultats */
    $result->close();
}

/* Fermeture de la connexion */
$mysqli->close();
?>

Exemple #2 Style procédural


<?php
$link = mysqli_connect("localhost", "my_user", "my_password", "test");

mysqli_query($link, "DROP TABLE IF EXISTS friends");
mysqli_query($link, "CREATE TABLE friends (id int, name varchar(20))");

mysqli_query($link, "INSERT INTO friends VALUES (1,'Hartmut'), (2, 'Ulf')");

mysqli_real_query($link, $HTTP_POST_VARS['query']);

if (mysqli_field_count($link)) {
    /* Une requête SELECT, SHOW ou DESCRIBE */
    $result = mysqli_store_result($link);

    /* Récupération du jeu de résultats */
    $row = mysqli_fetch_row($result);

    /* Libération du jeu de résultats */
    mysqli_free_result($result);
}

/* Fermeture de la connexion */
mysqli_close($link);
?>

mysqli::get_charset

mysqli->error

Last updated: Fri, 05 Dec 2008

add a note User Contributed Notes
mysqli->field_count

Jonathan
06-Mar-2007 03:43


Some corrections ;o)



$mysqli_type = array();

$mysqli_type[0] = "DECIMAL";

$mysqli_type[1] = "TINYINT";

$mysqli_type[2] = "SMALLINT";

$mysqli_type[3] = "INTEGER";

$mysqli_type[4] = "FLOAT";

$mysqli_type[5] = "DOUBLE";



$mysqli_type[7] = "TIMESTAMP";

$mysqli_type[8] = "BIGINT";

$mysqli_type[9] = "MEDIUMINT";

$mysqli_type[10] = "DATE";

$mysqli_type[11] = "TIME";

$mysqli_type[12] = "DATETIME";

$mysqli_type[13] = "YEAR";

$mysqli_type[14] = "DATE";



$mysqli_type[16] = "BIT";



$mysqli_type[246] = "DECIMAL";

$mysqli_type[247] = "ENUM";

$mysqli_type[248] = "SET";

$mysqli_type[249] = "TINYBLOB";

$mysqli_type[250] = "MEDIUMBLOB";

$mysqli_type[251] = "LONGBLOB";

$mysqli_type[252] = "BLOB";

$mysqli_type[253] = "VARCHAR";

$mysqli_type[254] = "CHAR";

$mysqli_type[255] = "GEOMETRY";

Typer85 at gmail dot com
02-Jan-2007 08:33


For those interested and to clarify the Manual Entry.



For query statements that are DESIGNED to return a result set of some sort, this function will always return the number of fields in the table that was queried.



I said DESIGNED because the return value has no effect on whether or not the actual query matched any rows or not.



For example, say I have a table that has 2 fields and only 10 rows. I issue the following query:



<?php



// Assume Connection Blah Blah.



mysqli_query( $connObject , "Select * From `table` Where `Id` > 1000");



// Get Number Of Fields.



mysqli_field_count( $connObject );



// Will Return 2 --> The Number of fields in the table!



?>



It is quite clear that the query itself will never return a result set because I asked it to return rows which have an Id over 1000 and there are only 10 rows.



But because the nature of the query itself is to return a result set, the field count is always returned no matter what.



In contrast, if the query does anything that does not return a result set by nature, such as an insert or update, the field count will always be 0.



Hence, you can easily determine the nature of this query dynamically using these return values.



Good Luck,



?>

dedlfix
18-Jul-2006 10:26


There are MYSQLI_TYPE_* constants for the type property (listed in http://php.net/manual/en/ref.mysqli.php).



e.g.

<?php

if ($finfo->type == MYSQLI_TYPE_VAR_STRING)

  // a VARCHAR

jakerosoft at hotmail dot com
16-Aug-2005 09:15


<?


$fieldinfo = $result->fetch_field();


if ($fieldinfo & MYSQLI_NOT_NULL_FLAG)  {


  print "not null flag is set";


} else {


  print "not null flag is NOT set";


}


?>

Marc-Andr�
07-Jul-2005 03:56


The "type" property will return a numerical representation of a field type instead of a "meaningful" string.



Here is an array that may help you:



<?php 

$mysqli_type = array();

$mysqli_type[0] = "decimal";

$mysqli_type[1] = "tinyint";

$mysqli_type[2] = "smallint";

$mysqli_type[3] = "int";

$mysqli_type[4] = "float";

$mysqli_type[5] = "double";

$mysqli_type[7] = "timestamp";

$mysqli_type[8] = "bigint";

$mysqli_type[9] = "mediumint";

$mysqli_type[10] = "date";

$mysqli_type[11] = "time";

$mysqli_type[12] = "datetime";

$mysqli_type[13] = "year";

$mysqli_type[252] = "blob"; // text, blob, tinyblob,mediumblob, etc...

$mysqli_type[253] = "string"; // varchar and char

$mysqli_type[254] = "enum";

?>

add a note

mysqli::get_charset

mysqli->error

Last updated: Fri, 05 Dec 2008