glob
When trying (no 'pear') to enumerate mounted drives on a win32 platform (Win XP SP3, Apache/2.2.11, PHP/5.2.9), I used:
<?php
function echo_win_drives() {
for($c='A'; $c<='Z'; $c++)
if(is_dir($c . ':'))
echo $c . ': ';
}
?>
which yielded:
A: C: D: E: F: G: H: I:
is_dir
(PHP 4, PHP 5)
is_dir — ファイルがディレクトリかどうかを調べる
説明
bool is_dir
( string $filename
)
指定したファイルがディレクトリかどうかを調べます。
パラメータ
- filename
-
ファイルへのパス。filename が相対パスの場合は、現在の作業ディレクトリからの相対パスとして処理します。 filename がシンボリックリンクあるいはハードリンクの場合は、 リンク先を解決して処理します。
返り値
ファイルがが存在して、かつそれがディレクトリであれば TRUE、それ以外の場合は FALSE を返します。
例
例1 is_dir() の例
<?php
var_dump(is_dir('a_file.txt'));
var_dump(is_dir('bogus_dir/abc'));
var_dump(is_dir('..')); //一つ上のディレクトリ
?>
上の例の出力は以下となります。
bool(false) bool(false) bool(true)
注意
注意: この関数の結果は キャッシュされます。詳細は、clearstatcache() を参照してください。
ヒント
PHP 5.0.0 以降、この関数は、 何らかの URL ラッパーと組合せて使用することができます。 どのラッパーが stat() ファミリーをサポートしているか のリストについては、サポートするプロトコル/ラッパー を参照してください。
add a note
User Contributed Notesis_dir
vstoykov at consultant dot bg
23-Apr-2009 10:43
23-Apr-2009 10:43
alanguir at detroitchamber dot com
28-Jan-2009 05:02
28-Jan-2009 05:02
When I run a scandir I always run a simple filter to account for file system artifacts (especially from a simple ftp folder drop) and the "." ".." that shows up in every directory:
<?php
if (is_dir($folder){
$contents = scandir($folder);
$bad = array(".", "..", ".DS_Store", "_notes", "Thumbs.db");
$files = array_diff($contents, $bad);
}
?>
Btx
26-Sep-2008 10:03
26-Sep-2008 10:03
<?php
public static function isEmptyDir($dir){
return (($files = @scandir($dir)) && count($files) <= 2);
}
?>
better ;)
jasoneisen at gee mail
29-Aug-2008 03:53
29-Aug-2008 03:53
An even better (PHP 5 only) alternative to "Davy Defaud's function":
<?php
function is_empty_dir($dir)
{
if (($files = @scandir($dir)) && count($files) <= 2) {
return true;
}
return false;
}
?>
NOTE: you should obviously be checking beforehand if $dir is actually a directory, and that it is readable, as only relying on this you would assume that in both cases you have a non-empty readable directory.
nielius at gmail dot com
20-Jun-2008 09:21
20-Jun-2008 09:21
@Anonymous:
If on Linux the suggested code does not work because '.' and '..' will allways be returned, it may be possible to subtract 2 from the amount of files found.
>>echo (count(glob("$dir/*") - 2) === 0) ? 'Empty' : 'Not
In that way, I think, you have solved the problem of two extra files that are counted.
Davy Defaud
20-May-2008 10:28
20-May-2008 10:28
Well, "John Doe's function" doesn't return the good value when $file != '.' && $file != '..' it must return false and not true !
Moreover, as the latest contributor told us, the directory have to be closed before returning.
This one is far safer ;-) :
<?php
function is_empty_dir($dir)
{
if ($dh = @opendir($dir))
{
while ($file = readdir($dh))
{
if ($file != '.' && $file != '..') {
closedir($dh);
return false;
}
}
closedir($dh);
return true;
}
else return false; // whatever the reason is : no such dir, not a dir, not readable
}
?>
Anonymous
24-Apr-2008 08:31
24-Apr-2008 08:31
On the previous example you may want to closedir() before returning, I tried the function and ran into some locking issues on windows when trying to delete the directory after I ran this function.
John Doe
23-Apr-2008 01:06
23-Apr-2008 01:06
I altered the function below a bit. This implementation is simpler, faster and safer:
<?php
function is_empty_folder($folder) {
if (! is_dir($folder))
return false; // not a dir
$files = opendir($folder);
while ($file = readdir($files)) {
if ($file != '.' && $file != '..')
return true; // not empty
}
}
?>
vlasec at gmailcom
23-Mar-2008 12:34
23-Mar-2008 12:34
zombix:
I don't know much about implementation, however I think that passing through all the files is useless. This code returns false also in case that it's not even a folder plus it stops in three steps at most.
<?php
function is_empty_folder($folder){
$c=0;
if(is_dir($folder) ){
$files = opendir($folder);
while ($file=readdir($files)){
$c++;
if ($c>2)
return false; // dir contains something
}
return true; // empty dir
}
else return false; // not a dir
}
?>
zombix at metrohive dot net
17-Mar-2008 07:14
17-Mar-2008 07:14
to check if folder is empty
function is_empty_folder($folder){
$c=0;
if(is_dir($folder) ){
$files = opendir($folder);
while ($file=readdir($files)){$c++;}
if ($c>2){
return false;
}else{
return true;
}
}
}
Anonymous
18-Dec-2007 07:51
18-Dec-2007 07:51
One note regarding checking for empty directories :
>>echo (count(glob("$dir/*")) === 0) ? 'Empty' : 'Not empty';
This does not work correctly on Linux.
The '.' and '..' will always be returned even if no files are present in the directory.
sgoldbroch at DONTSPAMMEcmcplacce dot com
05-Dec-2007 10:25
05-Dec-2007 10:25
Took a while to figure this out, but - DONT USE THIS IN A LOOP WITH READDIR()! readdir() only gives the file/dir name and not the full path which is_dir apparently needs to be able to accurately evaluate the argument.
e dot loiseau at meteo-ondemand dot com
29-Jul-2007 06:42
29-Jul-2007 06:42
I had the same problem as others with not using the complete path to a folder when usin is_dir.
It's really important to use complete path.
$folder = "../pictures";
$dossier = opendir($folder);
while ($Fichier = readdir($dossier)) {
if ($Fichier != "." && $Fichier != ".." && $Fichier != "Thumbs.db") {
// if(is_dir($Fichier)) { // Do not always works
if(is_dir($folder."/".$Fichier)) { // Works always
echo "$Fichier";
} // fin if is file
} // fin if restriction des fichiers à ne pas afficher
} // fin while
closedir($dossier);
Edouard
danr at cvisual dot com dot com
18-Jul-2007 09:54
18-Jul-2007 09:54
Running PHP 5.2.0 on Apache Windows, I had a problem (likely the same one as described by others) where is_dir returned a False for directories with certain permissions even though they were accessible.
Strangely, I was able to overcome the problem with a more complete path. For example, this only displays "Works" on subdirectories with particular permissions (in this directory about 1 out of 3):
$d = opendir("./albums/mydir");
while(false !== ($f = readdir($d))) {
echo "<hr />";
if(is_dir($f)) {
echo "<b>Works:" . $f . "</b>";
}
}
However, this works properly for all directories:
$d = opendir("./albums/mydir");
while(false !== ($f = readdir($d))) {
echo "<hr />";
$dName = "./albums/mydir/" . $f;
if(is_dir($dName)) {
echo "<b>Works:" . $dName . "</b>";
}
}
I don't understand the hit-and-miss of the first code, but maybe the second code can help others having this problem.
legolas558 d0t users dot sf dot net
20-May-2007 01:33
20-May-2007 01:33
I had troubles at checking for the existance of a directory under the windows temporary path (usually c:\windows\temp\). I am using PHP 5.2.0
See also the bug tracker item: http://bugs.php.net/bug.php?id=39198
Here below the replacement function which works under the Windows temporary directory. It is a bad hack, since it creates and then removes the directory to verify its existance! But I could not find an alternative solution, that bug should be fixed.
<?php
function temp_is_dir($dir) {
// check directory existance under temp folder (tested on Windows)
// see bug #31918 http://bugs.php.net/bug.php?id=39198
// by legolas558
if (!@mkdir($dir))
return true;
rmdir($dir);
return false;
}
?>
lordalderaan at gmail dot com
11-May-2007 01:26
11-May-2007 01:26
As was said earlier by locataweb at hotmail dot com is_dir returns false on windows shares even if they exist and are accessible.
I found that is_readable provides about the same functionality and does return true. It might provide a sufficient replacement in most cases.
gecko4 at gmail dot com
25-Feb-2007 05:03
25-Feb-2007 05:03
Here is another way to test if a directory is empty, which I think is much simpler than those posted below:
<?php
$dir = 'directory';
echo (count(glob("$dir/*")) === 0) ? 'Empty' : 'Not empty';
?>
18-Jan-2007 01:07
Be aware that is_dir() and is_file() will not work on very large (for me >2gb) files (also see http://de3.php.net/manual/en/function.is-file.php#56334).
You might try this approach - it works for me:
<?php
function isDir($dir) {
$cwd = getcwd();
$returnValue = false;
if (@chdir($dir)) {
chdir($cwd);
$returnValue = true;
}
return $returnValue;
}
?>
Please keep in mind that isDir() will fail on directories which cannot be chdired due to permission settings for example.
Eric
24-Oct-2006 08:53
24-Oct-2006 08:53
Ah ha! Maybe this is a bug, or limitation to be more precise, of php. See http://bugs.php.net/bug.php?id=27792
A workaround is posted on the page (above) and seems to work for me:
function is_dir_LFS($path){
return (('d'==substr(exec("ls -dl '$path'"),0,1))?(true):(false));
}
PS: I'm using PHP 4.3.10-16, posts report this problem up to 5.0
Eric Peterson
24-Oct-2006 12:48
24-Oct-2006 12:48
I'm not sure what is going on here... I have a function to return a listing of (sub)directories within a directory. Works great until I ran into the directory given in the warning below... 87 characters seems too short to be running into a file/directory name length issue?
This is what I'm getting (though broken into a couple lines so this forum will accept it):
Warning: is_dir(): Stat failed for
/home/office/public_html/Library/1_NNHP-produced/4_Maps
/Peterson2003/BRTEreport_DVD.zip
(errno=75 - Value too large for defined data type) in /home/office/public_html/index.php on line 104
Here is line 104:
if (is_dir($dir . "/" . $listing)) {
alan dot rezende at light dot com dot br
29-Sep-2006 01:42
29-Sep-2006 01:42
The function is_dir will always return false if the handle acquired with opendir is not from the current working directory (getcwd); exception applies to "." and "..". Thus, if you need a consistent dir listing from any directory other than the current one, you must change dir first. Example follows:
<?php
chdir( '..' );
$rep=opendir('.');
while (false != ($file = readdir($rep))){
if (is_dir($file)){
print("<a href='$file/' class='text1'>$file</a>");
}
}
?>
The above code will list all directories (with links) for the ".." directory, relative to the current working dir.
THE WRONG WAY TO DO IT FOLLOWS:
<?php
$rep=opendir('..');
while (false != ($file = readdir($rep))){
//print "$file is here (may be a dir or not)<br>";
if (is_dir($file)){
print "<a href='$file/' class='text1'>$file</a><br>";
}
}
?>
This code will turn into an empty list. If you want to make sure, uncomment the commented line...
Regards...
locataweb at hotmail dot com
06-Aug-2006 10:59
06-Aug-2006 10:59
NOTE on Windows Shares (based on tests using PHP 5.1.1):
After many hours of head scratching and wondering why a script worked sometimes but not others, I discovered this revelation.
Be aware that base Windows shares are not recognised as dirs, so the following test will return false even if \\COMPUTER_NAME\SHARENAME exists.
<?php
if (is_dir('\\\\COMPUTER_NAME\\SHARENAME')) {
echo "TRUE\n";
}
else {
echo "FALSE\n";
}
//will return FALSE;
// However testing a subdir of the same base share
// using test below will return TRUE,
// despite the fact the parent base Windows share
// returns false when tested by is_dir()
is_dir('\\\\COMPUTER_NAME\\SHARENAME\\SUBDIR') {
echo "TRUE\n";
} else {
echo "FALSE\n";
}
//will return TRUE.
?>
As a work round I replaced is_dir with is_readable() instead, which identifies if the share is readable and so must exist, but this is clearly dependent on whether the share is readable.
I hope this helps someone. If there is a better work round or other purpose built solution to this problem with base windows shares, please post them so I'll know the next time.
derek at nospam dot pmachine dot com
14-Jul-2006 11:10
14-Jul-2006 11:10
regarding dmertens-php-note at zyprexia dot com's statement on 24-Sep-2005 09:53
Actually, is_dir is not affected by UID checks in safe_mode. is_dir will even return true if you lack sufficient privileges to read said directory.
dmertens-php-note at zyprexia dot com
24-Sep-2005 03:53
24-Sep-2005 03:53
Remember that the owner of the directory has to be the same of the script user, otherwise this function will always return false when PHP is running in safe_mode..
fanfatal at fanfatal dot pl
02-Jul-2005 04:04
02-Jul-2005 04:04
Hi
I wrote an usefull function to check is directory exists in directory's tree ;)
<?php
/*
* Function to check recursively if dirname is exists in directory's tree
*
* @param string $dir_name
* @param string [$path]
* @return bool
* @author FanFataL
*/
function dir_exists($dir_name = false, $path = './') {
if(!$dir_name) return false;
if(is_dir($path.$dir_name)) return true;
$tree = glob($path.'*', GLOB_ONLYDIR);
if($tree && count($tree)>0) {
foreach($tree as $dir)
if(dir_exists($dir_name, $dir.'/'))
return true;
}
return false;
}
?>
Greatings ;)
...
06-Jun-2005 06:30
With error reporting set to all, and you attempt to do:
echo var_dump(is_dir('bogus_dir/abc'));
as output you will get:
Warning: stat failed for bogus_dir/abc (errno=2 - No such file or directory) in test.php on line 12
bool(false)
If you want to use this with an error reporting level set to all, you will need to use @ to supress the generated error
akashif at freezone dot co dot uk
03-Jun-2005 11:50
03-Jun-2005 11:50
just a simple script to for those who dont have the IIS or Apache Dirlisting available , this will make onr for you
<?php
$DirPath=$_GET['DirPath'];
if($DirPath=="")
{
$DirPath='./';
}
if (($handle=opendir($DirPath)))
{
while ($node = readdir($handle))
{
$nodebase = basename($node);
if ($nodebase!="." && $nodebase!="..")
{
if(is_dir($DirPath.$node))
{
$nPath=$DirPath.$node."/";
echo "-> -> -> <a href='dir.php?DirPath=$nPath'>$node</a><br>";
}
else
{
echo "<a href='$node'>$node</a><br>";
}
}
}
}
?>
renich at woralelandia dot com
21-Apr-2005 06:45
21-Apr-2005 06:45
Here goes a PHP5.0 link-to-directory listing function and examples
<?php
//List directories only
function list_dirs($path, $target)
{
$list = scandir($path);
foreach ($list as $number => $filename)
{
if ( $filename !== '.' && $filename !== '..' && is_dir("$path/$filename") )
{
// Asign more readable and logic variables
$dir = $filename;
$url = apache_request_headers();
if ($target == '')
{
// Print Dirs with link
print ("<a href=\"http://$url[Host]/$path/$dir\">$dir</a> <br>\n");
}
else
{
// Print Dirs with link
print ("<a href=\"http://$url[Host]$dir\" target=\"$target\">$dir</a> <br>\n");
}
}
}
}
?>
1.- List current directory's directories with no target property.
<?php
list_dirs('.','')
?>
2.- List "libraries" in "pma2" located at my dir with a "_blank" target set
<?php
list_dirs('pma2/libraries','_blank');
?>
or
<?php
list_dirs('/var/www/html/pma2/libraries','_blank');
?>
3.- List all the directories located at the "/Home" dir with "_me" as target.
<?php
list_dirs('/home', ''_me');
?>
I hope you all like it!
Note:
Obviously, the links will now work if the're not in the apache dir... ("htdocs", "html", "www", whatever)
dusted19 at hotmail dot com
19-Mar-2005 10:38
19-Mar-2005 10:38
While working on a php project (my first one =( ). I ran into a bug using is_dir() on my winxp w/ servicepack 2 system. I'm using php 4.3.10.. the problem is whenever i pass is_dir() a pathname that is longer then 256 characters long it will ALWAYS return true.
CODE:
<?php
// Path to multimedia files
$mpath = "E:\\armoury\\";
ls($mpath);
//echo "MP3 Listing:<br/><br/>";
function ls ($curpath) {
$dir = dir($curpath);
echo("<b>$curpath</b>");
echo "<blockquote>";
while ($file = $dir->read()) {
echo(" <b>");
echo(strlen($curpath.$file));
echo("</b> ");
if($file != "." && $file != "..") {
if (is_dir($curpath.$file)) {
ls($curpath.$file."\\");
} else {
echo(" $file<br>");
}
}
// }
}
$dir->close();
echo "</blockquote>";
return;
}
?>
This is the output.. the number preceding the file/directory is the number of characters in it's full path name. You can see where it trips up at:
257 E:\armoury\[ hiphop - dub - reggae - soul ]\A Tribe Called Quest - 1990 - People's Instinctive Travels And The Paths Of Rhythm\A Tribe Called Quest - People's Instinctive Travels And The Paths Of Rhythm - 10 - Rhythm (Devoted To The Art Of Moving Butts).mp3
The pathname is greater then 256 characters.
229 A Tribe Called Quest - People's Instinctive Travels And The Paths Of Rhythm - 07 - Bonita Applebum.mp3
227 A Tribe Called Quest - People's Instinctive Travels And The Paths Of Rhythm - 08 - Can I Kick It.mp3
233 A Tribe Called Quest - People's Instinctive Travels And The Paths Of Rhythm - 09 - Youthful Expression.mp3
257 E:\armoury\[ hiphop - dub - reggae - soul ]\A Tribe Called Quest - 1990 - People's Instinctive Travels And The Paths Of Rhythm\A Tribe Called Quest - People's Instinctive Travels And The Paths Of Rhythm - 10 - Rhythm (Devoted To The Art Of Moving Butts).mp3\
259 260 267 E:\armoury\[ hiphop - dub - reggae - soul ]\A Tribe Called Quest - 1990 - People's Instinctive Travels And The Paths Of Rhythm\A Tribe Called Quest - People's Instinctive Travels And The Paths Of Rhythm - 10 - Rhythm (Devoted To The Art Of Moving Butts).mp3\index.php\
269 270 277 E:\armoury\[ hiphop - dub - reggae - soul ]\A Tribe Called Quest - 1990 - People's Instinctive Travels And The Paths Of Rhythm\A Tribe Called Quest - People's Instinctive Travels And The Paths Of Rhythm - 10 - Rhythm (Devoted To The Art Of Moving Butts).mp3\index.php\index.php\
Try it yourself on a large directory structure.
flobee
14-Mar-2005 02:13
14-Mar-2005 02:13
note: like the main example already shows. tooks me houres to understand und using chdir() to get a full dir scann (especilly on windows and "mounted" network drives)
never forget the tailing slash to find out if you have a directory or not.
<?php
function parse_dir($dir) {
if ($dh = @opendir($dir)) {
while(($file = readdir($dh)) !== false) {
if( !preg_match('/^\./s', $file) ) {
if(is_dir($dir.$file)) {
$newdir = $dir.$file.'/'; // <- tailing slash
chdir($newdir);
echo "IS DIR: $newdir\n";
echo parse_dir($newdir);
} else {
echo $dir.$file."\n";
}
}
}
chdir('..');
}
}
parse_dir('z:/myfolder/mysubfolder/');
?>
puremango dot co dot uk at gmail dot com
08-Feb-2005 07:55
08-Feb-2005 07:55
this function bypasses open_basedir restrictions.
<?
function my_is_dir($dir)
{
// bypasses open_basedir restrictions of is_dir and fileperms
$tmp_cmd = `ls -dl $dir`;
$dir_flag = $tmp_cmd[0];
if($dir_flag!="d")
{
// not d; use next char (first char might be 's' and is still directory)
$dir_flag = $tmp_cmd[1];
}
return ($dir_flag=="d");
}
?>
example:
<?
....
echo is_dir("/somewhere/i/dont/have/access/to");
?>
output:
Warning: open_basedir restriction in effect
<?
....
echo my_is_dir("/somewhere/i/dont/have/access/to");
?>
output:
true (or false, depending whether it is or not...)
---
visit puremango.co.uk for other such wonders
03-Feb-2005 12:12
Unfortunately, the function posted by p dot marzec at bold-sg dot pl does not work.
The corrected version is:
// returns true if folder is empty or not existing
// false if folde is full
function is_empty_folder($dir) {
if (is_dir($dir)) {
$dl=opendir($dir);
if ($dl) {
while($name = readdir($dl)) {
if (!is_dir("$dir/$name")) { //<--- corrected here
return false;
break;
}
}
closedir($dl);
}
return true;
} else return true;
}
tibard at gmail dot com
01-Feb-2005 08:32
01-Feb-2005 08:32
use this function to get all files inside a directory (including subdirectories)
<?php
function scan_Dir($dir) {
$arrfiles = array();
if (is_dir($dir)) {
if ($handle = opendir($dir)) {
chdir($dir);
while (false !== ($file = readdir($handle))) {
if ($file != "." && $file != "..") {
if (is_dir($file)) {
$arr = scan_Dir($file);
foreach ($arr as $value) {
$arrfiles[] = $dir."/".$value;
}
} else {
$arrfiles[] = $dir."/".$file;
}
}
}
chdir("../");
}
closedir($handle);
}
return $arrfiles;
}
?>
rchavezc at ameritech dot net
12-Dec-2004 04:19
12-Dec-2004 04:19
This is the function that I use to test for an empty directory:
<?php
function is_emtpy_dir($dirname){
// Returns true if $dirname is a directory and it is empty
$result=false; // Assume it is not a directory
if(is_dir($dirname) ){
$result=true; // It is a directory
$handle = opendir($dirname);
while( ( $name = readdir($handle)) !== false){
if ($name!= "." && $name !=".."){
$result=false; // directory not empty
break; // no need to test more
}
}
closedir($handle);
}
return $result;
}
?>
bhuskins at nospam dot christian-horizons dot org
12-Aug-2004 08:51
12-Aug-2004 08:51
'Is_empty_folder' posted by andreas at rueping dot net is a nice function. It did give me some grief, though. I don't beleive that it actually closes the directory when it's done (closedir in the wrong spot). I changed it slightly to be the following:
// returns true if folder is empty or not existing
// false if folde is full
<?
function is_emtpy_folder($folder){
if(is_dir($folder) ){
$handle = opendir($folder);
while( (gettype( $name = readdir($handle)) != "boolean")){
$name_array[] = $name;
}
foreach($name_array as $temp)
$folder_content .= $temp;
closedir($handle);//<--------moved this
if($folder_content == "...") {
return true;
} else {
return false;
}
}
else
return true; // folder doesnt exist
}
?>
sly at noiretblanc dot org
28-May-2004 05:10
28-May-2004 05:10
This is the "is_dir" function I use to solve the problems :
function Another_is_dir ($file)
{
if ((fileperms("$file") & 0x4000) == 0x4000)
return TRUE;
else
return FALSE;
}
or, more simple :
function Another_is_dir ($file)
{
return ((fileperms("$file") & 0x4000) == 0x4000);
}
I can't remember where it comes from, but it works fine.
p dot marzec at bold-sg dot pl
14-Mar-2004 03:33
14-Mar-2004 03:33
Simplest version 'is_empty_folder' posted by andreas at rueping dot net
// returns true if folder is empty or not existing
// false if folde is full
function is_empty_folder($dir) {
if (is_dir($dir)) {
$dl=opendir($dir);
if ($dl) {
while($name = readdir($dl)) {
if (!is_dir($name)) {
return false;
break;
}
}
closedir($dl);
}
return true;
} else return true;
}
andreas at rueping dot net
24-Sep-2003 12:29
24-Sep-2003 12:29
function checks if a folder is empty or not. Retruns "true" if it is empty and "false" if it is full with data. Also if the folder doesnt even exist, function returns "true".
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// returns true if folder is empty or not existing
// false if folde is full
<?
function is_emtpy_folder($folder){
if(is_dir($folder) ){
$handle = opendir($folder);
while( (gettype( $name = readdir($handle)) != "boolean")){
$name_array[] = $name;
}
foreach($name_array as $temp)
$folder_content .= $temp;
if($folder_content == "...")
return true;
else
return false;
closedir($handle);
}
else
return true; // folder doesnt exist
}
?>