get_parent_class
A little note on namespaces that may be obvious to some, but was not obvious to me.
Although you can make the below statement when the statement is in the same namespace as the interface/class declaration MyInterface...
<?php
$foo instanceof MyInterface
?>
Making use of the interface_exists, or class_exists functions, you must enter the full namespaced interface name like so (even if the function call is from the same namespace.)
<?php
interface_exists(__NAMESPACE__ . '\MyInterface', false);
?>
interface_exists
(PHP 5 >= 5.0.2)
interface_exists — 인터페이스가 정의되었는지 확인
설명
bool interface_exists
( string $interface_name
[, bool $autoload = true
] )
주어진 인터페이스가 정의되었는지 확인합니다.
반환값
주어진 interface_name이 정의되었으면 TRUE, 아니면 FALSE를 반환합니다.
예제
Example #1 interface_exists() 예제
<?php
// 사용하기 전에 인터페이스가 존재하는지 확인
if (interface_exists('MyInterface')) {
class MyClass implements MyInterface
{
// 메쏘드
}
}
?>
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User Contributed Notes
interface_exists
nils dot rocine at gmail dot com
26-Oct-2011 06:35
andrey at php dot net
24-Oct-2004 04:40
As far as I remember interface_exists() was added in 5.0.2 . In 5.0.0 and 5.0.1 class_exists() used to return TRUE when asked for a existing interface. Starting 5.0.2 class_exists() doesn't do that anymore.