If you need to quote everything but a wildcard, maybe this function will come handy to you:
<?php
protected function _ruleOptionIsMatched($option, $subject)
{
$option = preg_quote($option, '#');
$option = str_replace('\*', '.*', $option);
if(preg_match("#^$option$#", $subject))
{
return true;
}
else
{
return false;
}
}
?>
preg_quote
(PHP 4, PHP 5)
preg_quote — 정규 표현식 문자를 인용
설명
string preg_quote
( string $str
[, string $delimiter
] )
preg_quote()는 str에서 정규 표현식 문법에 포함되는 모든 문자의 앞에 백슬래시를 덧붙입니다. 어떠한 텍스트에 특수 정규 표현식 문자를 포함하는 런타임 문자열을 처리할 때 유용합니다.
정규 표현식 특수 문자는: . \ + * ? [ ^ ] $ ( ) { } = ! < > | :
인수
- str
-
입력 문자열.
- delimiter
-
delimiter를 정의하면, 그 문자들도 이스케이프합니다. PCRE 함수에서 요구하는 구분자를 이스케이프 할 때 유용합니다. /는 가장 널리 사용되는 구분자입니다.
반환값
인용한 문자열을 반환합니다.
예제
Example #1 preg_quote() 예제
<?php
$keywords = '$40 for a g3/400';
$keywords = preg_quote($keywords, '/');
echo $keywords; // \$40 for a g3\/400 를 반환합니다.
?>
Example #2 텍스트 안의 단어를 기울임꼴로
<?php
// 이 예제에서, preg_quote($word)는 정규 표현식에서
// 특별한 의미를 지니는 애스터라이크(*)의 처리에 사용됩니다.
$textbody = "This book is *very* difficult to find.";
$word = "*very*";
$textbody = preg_replace("/" . preg_quote($word) . "/",
"<i>" . $word . "</i>",
$textbody);
?>
주의
Note: 이 함수는 바이너리 안전입니다.
billadoid at gmail dot com
12-Jan-2012 05:11
admin at nilamo dot com
04-Aug-2010 08:21
@zooly:
And what if $myvar = 'te\\E.t'? It will match, when it shouldn't. That's why you should use preg_quote().
zooly
21-Jul-2009 01:07
To escape characters with special meaning, like: .-[]() and so on, use \Q and \E.
For example:
<?php echo ( preg_match('/^'.( $myvar = 'te.t' ).'$/i', 'test') ? 'match' : 'nomatch' ); ?>
Will result in: match
But:
<?php echo ( preg_match('/^\Q'.( $myvar = 'te.t' ).'\E$/i', 'test') ? 'match' : 'nomatch' ); ?>
Will result in: nomatch
alexc223 at NOSPAM dot googlemail dot com
15-Jun-2009 12:41
Not sure why this note got deleted, but hey lets try again:
As of PHP 5.3, bug #47229 has been fixed and preg_quote *will* escape a hyphen (-). This may effect your code so ensure this is one thing you check when moving to 5.3.
frostschutz
20-Mar-2009 02:01
I wanted to escape a string of characters so I could match them in [], i.e. [.,-!"§$%\\\[\]\^].
Unfortunately preg_quote does not escape the - character which has a special meaning in [], i.e. [a-z].
So I used this hack: make - the delimiter of the expression, i.e.
preg_quote(userinput, "-")
preg_replace("-[$userinput]-u", "", $str)
Apparently using a special char as a delimiter of a regular expression disables this character, i.e. even if it's escaped it's not understood as special character for the expression anymore.
so the pattern "-[a\\-z]-u" matches the characters a, - and z, and not abc...xyz.
It would be nice if preg_quote also escaped characters that have special meanings even if they have this meaning only under certain conditions, such as inside [].
krishoog at gmail dot com
13-Oct-2008 07:51
To bizzigul at hotmail dot fr:
It's not a good practice to make somthing work *almost* all of the time. If the input contains a '`' you will still get an error. I recommend using the default delimiter ('/') and also feed this to preg_quote as second argument.
bizzigul at hotmail dot fr
30-Jul-2008 09:10
To prevent any problems, try to always use a delimiter that will *almost* not be used inside the regex, such as ` (back quote)
for example: instead of
<?php preg_match('/foo\/bar\//',$somevar); ?>
use
<?php preg_match('`foo/bar/`',$somevar); ?>
it's that simple! like this, you won't have to bother with delimiters anymore...
Anonymous
26-Dec-2007 03:13
Wondering why your preg_replace fails, even if you have used preg_quote?
Try adding the delimiter / - preg_quote($string, '/');
