mysqli_stmt::num_rows
This parameter (and presumably any other parameter in mysqli_stmt) will raise an error with the message "Property access is not allowed yet" if the statement was not prepared properly, or not prepared at all.
To prevent this, always ensure that the return value of the "prepare" statement is true before accessing these properties.
mysqli_stmt::param_count
mysqli_stmt_param_count
(PHP 5)
mysqli_stmt::param_count -- mysqli_stmt_param_count — Returns the number of parameter for the given statement
설명
객체 기반 형식
int $mysqli_stmt->param_count;
절차식 형식
int mysqli_stmt_param_count
( mysqli_stmt $stmt
)
Returns the number of parameter markers present in the prepared statement.
반환값
Returns an integer representing the number of parameters.
예제
Example #1 객체 기반 형식
<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
if ($stmt = $mysqli->prepare("SELECT Name FROM Country WHERE Name=? OR Code=?")) {
$marker = $stmt->param_count;
printf("Statement has %d markers.\n", $marker);
/* close statement */
$stmt->close();
}
/* close connection */
$mysqli->close();
?>
Example #2 절차식 형식
<?php
$link = mysqli_connect("localhost", "my_user", "my_password", "world");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
if ($stmt = mysqli_prepare($link, "SELECT Name FROM Country WHERE Name=? OR Code=?")) {
$marker = mysqli_stmt_param_count($stmt);
printf("Statement has %d markers.\n", $marker);
/* close statement */
mysqli_stmt_close($stmt);
}
/* close connection */
mysqli_close($link);
?>
위 예제들의 출력:
Statement has 2 markers.
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User Contributed Notes
mysqli_stmt::param_count
Senthryl
10-Mar-2009 11:47