In example #1 above, the variable $bg is set but not used. Set the background to anything but black ,and it won't take effect. The example needs
imagefill($image, 0, 0, $bg);
Some other image function examples have the same issue.
imageellipse
(PHP 4 >= 4.0.6, PHP 5)
imageellipse — Desenha um elipse
Descrição
int imageellipse
( resource
$image
, int $cx
, int $cy
, int $w
, int $h
, int $color
)
imageellipse() desenha um elipse centrado na posição
cx, cy (em cima a esquerda é
0, 0) na imagem representada por image.
W e h especifica a
largura e altura do elipse, respectivamente. A cor do elipse é
especificada por color.
Nota:
Esta função foi adicionada no PHP 4.0.6 e requer GD 2.0.2 ou posterior que pode ser obtida em » http://www.libgd.org/
Exemplo #1 Exemplo imageellipse()
<?php
// cria uma imagem em branco
$image = imagecreate(400, 300);
// prenche a cor do fundo
$bg = imagecolorallocate($image, 0, 0, 0);
// escolhe uma cor para o elipse
$col_ellipse = imagecolorallocate($image, 255, 255, 255);
// desenha o elipse
imageellipse($image, 200, 150, 300, 200, $col_ellipse);
// mostra a imagem
header("Content-type: image/png");
imagepng($image);
?>
Veja também imagefilledellipse() e imagearc().
themountainlion at gmail dot com ¶
4 years ago
simon_nuttall at hotmail dot com ¶
6 years ago
This is an optimised and bug fixed version of nojer at yahoo dot com's rotatedellipse function. I've changed it so that the arguments are compatible with imageellipse. See notes on imagearc for original version.
<?php
function rotatedellipse($im, $cx, $cy, $width, $height, $rotateangle, $colour, $filled=false) {
// modified here from nojer's version
// Rotates from the three o-clock position clockwise with increasing angle.
// Arguments are compatible with imageellipse.
$width=$width/2;
$height=$height/2;
// This affects how coarse the ellipse is drawn.
$step=3;
$cosangle=cos(deg2rad($rotateangle));
$sinangle=sin(deg2rad($rotateangle));
// $px and $py are initialised to values corresponding to $angle=0.
$px=$width * $cosangle;
$py=$width * $sinangle;
for ($angle=$step; $angle<=(180+$step); $angle+=$step) {
$ox = $width * cos(deg2rad($angle));
$oy = $height * sin(deg2rad($angle));
$x = ($ox * $cosangle) - ($oy * $sinangle);
$y = ($ox * $sinangle) + ($oy * $cosangle);
if ($filled) {
triangle($im, $cx, $cy, $cx+$px, $cy+$py, $cx+$x, $cy+$y, $colour);
triangle($im, $cx, $cy, $cx-$px, $cy-$py, $cx-$x, $cy-$y, $colour);
} else {
imageline($im, $cx+$px, $cy+$py, $cx+$x, $cy+$y, $colour);
imageline($im, $cx-$px, $cy-$py, $cx-$x, $cy-$y, $colour);
}
$px=$x;
$py=$y;
}
}
function triangle($im, $x1,$y1, $x2,$y2, $x3,$y3, $colour) {
$coords = array($x1,$y1, $x2,$y2, $x3,$y3);
imagefilledpolygon($im, $coords, 3, $colour);
}
?>
julian ¶
8 years ago
if you want to display an ellipse in the upper left corner of an image, you can easily calculate the corresponding cx and cy values. this example will draw an ellipse having the same width and height as the image.
<?php
$ellipse_width = 100;
$ellipse_height = 200;
$ellipse_cx = ($ellipse_width / 2);
$ellipse_cy = ($ellipse_height / 2);
$img_x = $ellipse_width;
$img_y = $ellipse_height;
$img = imagecreate($img_x, $img_y);
$bg = imagecolorallocate($img, 255,255,255);
$ellipse_color = imagecolorallocate($img, 0, 0, 0);
imageellipse($img, $ellipse_cx, $ellipse_cy, $ellipse_width, $ellipse_height, $ellipse_color);
header("Content-type: image/png");
imagepng($img);
imagedestroy($img);
?>
agentyoungsoo at hanmail dot net ¶
10 years ago
When you wana use "ImageEllipse" function
in under GD 2.0.2 version, you can use "ImageArc" like bellow
----------------------------------------------------
$file_name = "test.png";
$screen_x = 300;
$screen_y = 200;
$x1 = $screen_x / 2;
$y1 = $screen_y / 2;
$radius = 30;
$image = ImageCreate($screen_x, $screen_y);
$black = ImageColorAllocate($image, 0,0,0);
ImageArc($image, $x1, $y1, $radius , $radius , 0, 360, $black);
ImagePng($image, $file_name);
ImageDestroy($image);
----------------------------------------------------
