zlib://
Now PHP supports data: protocol w/out "//" like data:text/plain, not data://text/plain,
I tried it.
data://
data:// — Data (RFC 2397)
Descrição
The data: (» RFC 2397) stream wrapper is available since PHP 5.2.0.
Usage
- data://text/plain;base64,
Exemplos
Exemplo #1 Print data:// contents
<?php
// prints "I love PHP"
echo file_get_contents('data://text/plain;base64,SSBsb3ZlIFBIUAo=');
?>
Exemplo #2 Fetch the media type
<?php
$fp = fopen('data://text/plain;base64,', 'r');
$meta = stream_get_meta_data($fp);
// prints "text/plain"
echo $meta['mediatype'];
?>
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User Contributed Notes
data:// - [5 notes]
sandaimespaceman at gmail dot com ¶
4 years ago
from dot php dot net at brainbox dot cz ¶
2 years ago
When passing plain string without base64 encoding, do not forget to pass the string through URLENCODE(), because PHP automatically urldecodes all entities inside passed string (and therefore all + get lost, all % entities will be converted to the corresponding characters).
In this case, PHP is strictly compilant with the RFC 2397. Section 3 states that passes data should be either in base64 encoding or urlencoded.
VALID USAGE:
<?php
$fp = fopen('data:text/plain,'.urlencode($data), 'rb'); // urlencoded data
$fp = fopen('data:text/plain;base64,'.base64_encode($data), 'rb'); // base64 encoded data
?>
Demonstration of invalid usage:
<?php
$data = 'Günther says: 1+1 is 2, 10%40 is 20.';
$fp = fopen('data:text/plain,'.$data, 'rb'); // INVALID, never do this
echo stream_get_contents($fp);
// Günther says: 1 1 is 2, 10@ is 20. // ERROR
$fp = fopen('data:text/plain,'.urlencode($data), 'rb'); // urlencoded data
echo stream_get_contents($fp);
// Günther says: 1+1 is 2, 10%40 is 20. // OK
// Valid option 1: base64 encoded data
$fp = fopen('data:text/plain;base64,'.base64_encode($data), 'rb'); // base64 encoded data
echo stream_get_contents($fp);
// Günther says: 1+1 is 2, 10%40 is 20. // OK
?>
senica at gmail dot com ¶
1 year ago
You can use data:// to evaluate php that is stored in mySQL
For example:
If you have code stored that looks like this:
$content = ' //Content from your database or variable
<?php if($var == "something"): ?>
print this html
<?php endif; ?>
';
Trying to evaluate this can prove cumbersome
But you can do something like:
include "data://text/plain;base64,".base64_encode($content);
and it will parse it with no problems.
admin deskbitz net ¶
3 years ago
If you want to create a gd-image directly out of a sql-database-field you might want to use:
<?php
$jpegimage = imagecreatefromjpeg("data://image/jpeg;base64," . base64_encode($sql_result_array['imagedata']));
?>
this goes also for gif, png, etc using the correct "imagecreatefrom$$$"-function and mime-type.
togos00 at gmail dot com ¶
5 years ago
Note that the official data URI scheme does not include a double slash after the colon - that you must include it when making calls to PHP is an artifact of the designers' misunderstanding of URL syntax.
To automatically convert proper data URIs to ones understood by PHP, you can use code such as the following:
<?php
function convertUriForPhp( $uri ) {
if( preg_match('/^data:(?!\\/\\/)(.*)$/',$uri,$bif) ) {
return 'data://' . $bif[1];
} else {
return $uri;
}
}
?>