array_uintersect_uassoc
I want to stress that in the user function, you do need to return either a 1 or a -1 properly; you cannot simply return 0 if the results are equal and 1 if they are not.
The following code is incorrect:
<?php
function myfunction($v1,$v2)
{
if ($v1===$v2)
{
return 0;
}
return 1;
}
$a1=array(1, 2, 4);
$a2=array(1, 3, 4);
print_r(array_uintersect($a1,$a2,"myfunction"));
?>
This code is correct:
<?php
function myfunction($v1,$v2)
{
if ($v1===$v2)
{
return 0;
}
if ($v1 > $v2) return 1;
return -1;
}
$a1=array(1, 2, 4);
$a2=array(1, 3, 4);
print_r(array_uintersect($a1,$a2,"myfunction"));
?>
array_uintersect
(PHP 5)
array_uintersect — Computes the intersection of arrays, compares data by a callback function
Descrierea
array array_uintersect
( array $array1
, array $array2
[, array $ ...
], callback $data_compare_func
)
Computes the intersection of arrays, compares data by a callback function.
Parametri
- array1
-
The first array.
- array2
-
The second array.
- data_compare_func
-
The callback comparison function.
The user supplied callback function is used for comparison. It must return an integer less than, equal to, or greater than zero if the first argument is considered to be respectively less than, equal to, or greater than the second.
Valorile întroarse
Returns an array containing all the values of array1 that are present in all the arguments.
Exemple
Example #1 array_uintersect() example
<?php
$array1 = array("a" => "green", "b" => "brown", "c" => "blue", "red");
$array2 = array("a" => "GREEN", "B" => "brown", "yellow", "red");
print_r(array_uintersect($array1, $array2, "strcasecmp"));
?>
Exemplul de mai sus va afişa:
Array ( [a] => green [b] => brown [0] => red )
add a note
User Contributed Notesarray_uintersect
Nate at RuggFamily dot com
02-Feb-2007 12:03
02-Feb-2007 12:03