mysql_fetch_object
sry :) note now fixed:
<?php
$esi=mysql_list_tables($db);$ris=mysql_fetch_row($esi);
//example: $db has >= 1 tabs
echo var_dump($ris);
//echoes only array(1). solution:
while($ris=mysql_fetch_row($esi)) echo $ris[0];
/*debug:
$ris=array("1st_tab"); ... $ris=array("n_tab");$ris=false;*/
while ($ris[]=mysql_fetch_row($esi));
//debug:$ris=array(array("1st_tab"), ... array("n_tab"));
echo $ris[n][0];//echo:"n_tab"
echo $ris[0][n];//echo:array | null
?>
hope it helps
mysql_fetch_row
(PHP 4, PHP 5)
mysql_fetch_row — Get a result row as an enumerated array
Descrierea
array mysql_fetch_row
( resource $result
)
Returns a numerical array that corresponds to the fetched row and moves the internal data pointer ahead.
Parametri
- result
-
Rezultatul de tip resource , care este evaluat. Acest rezultat provine de la apelul funcţiei mysql_query().
Valorile întroarse
Returns an numerical array of strings that corresponds to the fetched row, or FALSE if there are no more rows.
mysql_fetch_row() fetches one row of data from the result associated with the specified result identifier. The row is returned as an array. Each result column is stored in an array offset, starting at offset 0.
Exemple
Example #1 Fetching one row with mysql_fetch_row()
<?php
$result = mysql_query("SELECT id,email FROM people WHERE id = '42'");
if (!$result) {
echo 'Could not run query: ' . mysql_error();
exit;
}
$row = mysql_fetch_row($result);
echo $row[0]; // 42
echo $row[1]; // the email value
?>
Note
Notă: Această funcţie stabileşte câmpurile NULL la valoarea PHP NULL.
Vedeţi de asemenea
- mysql_fetch_array() - Fetch a result row as an associative array, a numeric array, or both
- mysql_fetch_assoc() - Fetch a result row as an associative array
- mysql_fetch_object() - Fetch a result row as an object
- mysql_data_seek() - Move internal result pointer
- mysql_fetch_lengths() - Get the length of each output in a result
- mysql_result() - Get result data
add a note
User Contributed Notesmysql_fetch_row
larkitetto at gmail dot com
21-Feb-2008 11:29
21-Feb-2008 11:29
ryhan_balboa at yahoo dot com
16-Nov-2007 05:23
16-Nov-2007 05:23
The following are the basic codes to get a specific row from the mysql db into a $row variable:
$query = "SELECT * FROM table";
$result = mysql_query($query);
$row = mysql_fetch_row($result);
And $row[0], $row[1] ... $row[n] are used to access those field values.
Does anyone know how I can add a new field to $row, so that the field count increases from n to n+1?
I have tried treating $row like an array, and tried array_push function, but didn't work.
Thanks.
m dot s at programmers-online dot net
17-Nov-2005 09:56
17-Nov-2005 09:56
The following function to read all data out of a mysql-resultset, is may be faster than Rafaels solution:
<?
function mysql_fetch_all($result) {
while($row=mysql_fetch_array($result)) {
$return[] = $row;
}
return $return;
}
?>
mysql at polyzing dot com
12-Jul-2003 10:05
12-Jul-2003 10:05
It is probably worth pointing out that the array elements will actually be of type string, OR NULL if the field is null in the database.
Thus, either use a double equal comparison to look for empty or null
Or, use a triple equal comparison to be able to distinguish the two cases
e.g.
if ($field === '') echo "Empty, not NULL\n";
if ($field === NULL) echo "NULL\n";
if ($field == '') echo "Empty or NULL\n";
michael and then an at sign wassupy.com
08-Apr-2003 07:09
08-Apr-2003 07:09
to print an array, simply use print_r(array name)
like this:
$myrow = mysql_fetch_row($result);
echo "<pre>";
print_r($myrow);
echo "</pre>";
this will output the array in a readable form, with the index, too. Don't forget the 'pre' tags or the output will be on a single line.
a at simongrant dot org
06-Feb-2002 01:10
06-Feb-2002 01:10
Maybe worth pointing out that all the fields returned by this (and other?) calls are returned with type string. This had me puzzled for quite some time.