[edit] Last updated: Fri, 17 May 2013

mysqli_result::free

mysqli_free_result

(PHP 5)

mysqli_result::free -- mysqli_free_result — Frees the memory associated with a result

Descrierea

Stil obiect-orientat

void mysqli_result::free ( void )

void mysqli_result::close ( void )

void mysqli_result::free_result ( void )

Stil procedural

void mysqli_free_result ( mysqli_result $result )

Frees the memory associated with the result.

Notă:
You should always free your result with mysqli_free_result(), when your result object is not needed anymore.

Parametri

result: Numai stilul procedural: Un identificator al setului de rezultate întors de mysqli_query(), mysqli_store_result() sau mysqli_use_result ().

Valorile întoarse

Nu este întoarsă nici o valoare.

Vedeți de asemenea

mysqli_query() - Performs a query on the database
mysqli_stmt_store_result() - Transfers a result set from a prepared statement
mysqli_store_result() - Transfers a result set from the last query
mysqli_use_result() - Initiate a result set retrieval

add a note User Contributed Notes mysqli_result::free - [2 notes]

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Vector at ionisis dot com ¶

3 years ago


If you are getting this error:


Internal SQL Bug: 2014, Commands out of sync; you can't run this command now





Then you never called mysqli_result::free(), mysqli_result::free_result(), mysqli_result::close(), or mysqli_free_result() in your script, and must call it before executing another stored procedure.

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Anonymous ¶

3 years ago


Freeing the memory associated with a result means that the references returned by mysqli_fetch_object (or equivalent) are cleared. Thus if you should pass an object pointing to a database row _by reference_, every call of mysqli_free_result will discard the referenced data.

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