It should be mentioned that the function returns the name of the directory if "filename" is of type "directory". Hence
<?php
$info = new SplFileInfo('/path/to/');
var_dump($info->getFilename());
?>
should return "to"
The function name is kind of misleading here and I am glad to have it tried.
SplFileInfo::getFilename
(PHP 5 >= 5.1.2)
SplFileInfo::getFilename — Gets the filename
Descrierea
public string SplFileInfo::getFilename
( void
)
Gets the filename without any path information.
Parametri
Această funcție nu are parametri.
Valorile întoarse
The filename.
Exemple
Example #1 SplFileInfo::getFilename() example
<?php
$info = new SplFileInfo('foo.txt');
var_dump($info->getFilename());
$info = new SplFileInfo('/path/to/foo.txt');
var_dump($info->getFilename());
$info = new SplFileInfo('http://www.php.net/');
var_dump($info->getFilename());
$info = new SplFileInfo('http://www.php.net/svn.php');
var_dump($info->getFilename());
?>
Exemplul de mai sus va afișa ceva similar cu:
string(7) "foo.txt" string(7) "foo.txt" string(0) "" string(7) "svn.php"
wloske at yahoo dot de
19-Oct-2009 09:12
