<?php
class abc{
function func($argument) {
$argument="It works";
}
}
$obj=new abc;
$argument_to_be_changed="No it doesn't work";
call_user_method("func", $obj, &$argument_to_be_changed);
echo "Result : ".$argument_to_be_changed;
?>
This code is working. But will through some warning message which you can hide by configuring php.ini
call_user_method
(PHP 4, PHP 5)
call_user_method — Вызывает метод указанного объекта [устаревшее]
Описание
Внимание
Функция call_user_method_array() устарела с выходом 4.1.0: используйте функцию call_user_func() с array(&$obj, "method_name") в качестве параметра имени функции.
Вызываем метод method_name объекта obj . Ниже приведен пример использования функции, в которой мы определяем класс, создаём его объект и используем call_user_method() для вызова метода print_info.
<?php
class Country {
var $NAME;
var $TLD;
function Country($name, $tld)
{
$this->NAME = $name;
$this->TLD = $tld;
}
function print_info($prestr = "")
{
echo $prestr . "Country: " . $this->NAME . "\n";
echo $prestr . "Top Level Domain: " . $this->TLD . "\n";
}
}
$cntry = new Country("Peru", "pe");
echo "* Calling the object method directly\n";
$cntry->print_info();
echo "\n* Calling the same method indirectly\n";
call_user_method("print_info", $cntry, "\t");
?>
См. также call_user_func_array() и call_user_func().
call_user_method
ravichandran_11 at yahoo dot co dot in
10-Mar-2008 05:32
10-Mar-2008 05:32
j dot h at h-elektro dot de
05-Feb-2007 12:11
05-Feb-2007 12:11
It does not work to use Pointers as Arguments:
<?php
class abc{
function func(&$argument) {
$argument="It works";
}
}
$obj=new abc;
$argument_to_be_changed="No it doesnt";
call_user_method("func", $obj, $argument_to_be_changed);
echo "Result".$argument_to_be_changed;
?>
The result is: "No it doesnt".
Regards
der Jan
paulo at emd dot com dot br
18-Sep-2000 05:12
18-Sep-2000 05:12
This function is very similar to this:
$method="Print";
$object->$method($param1,$param2);
Note the extra $ after the ->
jmcastagnetto at php dot net
21-Aug-2000 05:04
21-Aug-2000 05:04
You can pass a variable number of parameters to a function, use a definition like:
function mymethod ($v1, $v2, $v3="", $v4="")
and then you can pass 2, 3 or 4 parameters. This is explained in the "Functions" section of the manual.
See also the PHP4 functions: func_num_args(), func_get_arg(), and func_get_args(), and examples therein
