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getdate> <date_timezone_set
Last updated: Sun, 25 Nov 2007

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date

(PHP 4, PHP 5)

date — Sformátovať miestny čas/dátum

Popis

string date ( string $format [, int $ timestamp ] )

Vracia reťazec sformátovaný podľa daného formátového reťazca pomocou daného integeru timestamp alebo ak nie je daný žiadny timestamp, podľa aktuálneho miestneho času. Inými slovami, timestamp je voliteľný a jeho východzou hodnotou je time().

Note: Platný rozsah timestampu je typicky od Fri, 13 Dec 1901 20:45:54 GMT do Tue, 19 Jan 2038 03:14:07 GMT. (Toto sú dátumy, ktoré zodpovedajú minimálnym a maximálnym hodnotám pre 32-bitový signed integer). Na windowse je tento rozsah ohraničený od 01-01-1970 do 19-01-2038.
Na vygenerovanie timestampu z reťazcovej reprezentácie dátumu môžete použiť strtotime(). Niektoré databázy majú funkcie na konvertovanie svojich formátov dátumu na timestampy (ako je MySQL funkcia » UNIX_TIMESTAMP).

Následujúce znaky sa rozpoznávajú v reťazcovom parametri format
format znak Popis Príklad vrátenych hodnôt
a Lowercase Ante meridiem a Post meridiem am alebo pm
A Uppercase Ante meridiem a Post meridiem AM alebo PM
B Swatch Internet čas 000999
d Deň mesiaca, 2 číslice s úvodnými nulami 01 do 31
D Textová reprezentácia dňa, tri písmená MonSun
F Plná textová reprezentácia mesiaca, ako je January alebo March JanuaryDecember
g 12-hodinový formát hodiny bez úvodných núl 112
G 24-hodinový formát hodiny bez úvodných núl 0 do 23
h 12-hodinový formát hodiny s úvodnými nulami 0112
H 24-hodinový formát hodiny s úvodnými nulami 00 do 23
i Minúty s úvodnými nulami 00 do 59
I (velké i) Buď dátum je alebo nie je v letnom čase 1 ak je Letný Čas, inak 0.
j Deň v miesiaci bez úvodných núl 1 do 31
l (malé 'L') Plná textová reprezentácia dňa v týždni SundaySaturday
L Či je priestupný rok 1 ak je pristupný rok, inak 0.
m Číselná reprezentácia mesiaca s úvodnými nulami 0112
M Krátka textová reprezentácia mesiaca, tri písmená JanDec
n Číselná reprezentácia mesiaca bez úvodných núl 112
O Rozdiel od Greenwichského času (GMT) v hodinách Príklad: +0200
r RFC 822 formátovný dátum Príkled: Thu, 21 Dec 2000 16:01:07 +0200
s Sekundy s úvodnými nulami 0059
S Anglická radová prípona pre deň v miesiaci, 2 znaky st, nd, rd alebo th. Dobre funguje s j
t Počet dní v dahom mesiaci 2831
T Nastavenie časovej zóny tohto stroja Príklad: EST, MDT ...
U Sekundy od Unixovej Epochy (1. Január 1970 00:00:00 GMT) Tiež pozri time()
w Časová reprezentácia dňa v týždni 0 (pre Nedeľu) až 6 (pre Sobotu)
W ISO-8601 číslo týždňa v roku, týždne začínajú Pondelkom (pridané v PHP 4.1.0) Príklad: 42 (42. týždeň v roku)
Y Plná číselná reprezentácia roku, 4 číslice Príklady: 1999 alebo 2003
y Dvoj-číslicová reprezentácia roku Príklady: 99 alebo 03
z Deň v roku 0366
Z Offset časovej zóny v sekundách. Offset pre časové zóny západne od UTC sú vždy záporné a pre tie na východ od UTC sú vždy kladné. -4320043200

Nerozpoznané znaky vo formátovanom reťazci budú vytlačené tak ako-sú. Formát Z vráti vždy 0 pri používaní gmdate().

Example#1 date() príklady

<?php
// Vypisuje nieco ako: Wednesday
echo date("l");

// Vypisuje nieco ako: Wednesday 15th of January 2003 05:51:38 AM
echo date ("l dS of F Y h:i:s A");

// Vypisuje: July 1, 2000 is on a Saturday
echo "July 1, 2000 is on a " date ("l"mktime(0,0,0,7,1,2000));
?>

Pred rozpoznávané znaky môžete napísať opačné lomítko (backslash), aby nedošlo k formátovaniu. Ak už znak s opačným lomítkom je špeciálnou sekvenciou, budete ju tiež musieť zaopatriť lomítkom.

Example#2 Vyskočenie znakov v date()

<?php
// vypisuje nieco ako: Wednesday the 15th
echo date("l \\t\h\e jS");
?>

Je možné použiť date() spolu s mktime() na zistinie dátumov v budúcnosti alebo v minulosti.

Example#3 date() a mktime() príklad

<?php
$zajtra  
mktime (0,0,0,date("m")  ,date("d")+1,date("Y"));
$minulymesiac mktime (0,0,0,date("m")-1,date("d"),  date("Y"));
$buducirok  mktime (0,0,0,date("m"),  date("d"),  date("Y")+1);
?>

Note: Toto môže byť spoľahlivejšie než jednoduché pridanie alebo odobranie počtu sekúnd v dni alebo miesiaci do timestampu, kvôli letnému času.

Nejaké príklady date() formátovania. Všetky ostatné znaky by ste mali 'vyskočiť', pretože tie, ktoré už majú špeciálny význam budú spôsobovať nežiadúce výsledky a iným znakom môže byť nejaký význam priradený v budúcich verziách PHP. Uistite sa, že pri vyskakovaní používate jednoduché apostrofy, aby ste predišli tomu, že sa znaky ako \n nestanú novými riadkami.

Example#4 date() Formátovanie

<?php
// Predpokladame, ze dnes je: March 10th, 2001, 5:16:18 pm

$today date("F j, Y, g:i a");                 // March 10, 2001, 5:16 pm
$today date("m.d.y");                         // 03.10.01
$today date("j, n, Y");                       // 10, 3, 2001
$today date("Ymd");                           // 20010310
$today date('h-i-s, j-m-y, it is w Day z ');  // 05-16-17, 10-03-01, 1631 1618 6 Fripm01
$today date('\i\t \i\s \t\h\e jS \d\a\y.');   // It is the 10th day.
$today date("D M j G:i:s T Y");               // Sat Mar 10 15:16:08 MST 2001
$today date('H:m:s \m \i\s\ \m\o\n\t\h');     // 17:03:17 m is month
$today date("H:i:s");                         // 17:16:17
?>

Na formátovanie dátumov v iných jazykoch by ste mali používať funkcie setlocale() a strftime().

Tiež pozri getlastmod(), gmdate(), mktime(), strftime() a time().



getdate> <date_timezone_set
Last updated: Sun, 25 Nov 2007
 
add a note add a note User Contributed Notes
date
sourabhshankar AT gmail DOT com
14-Nov-2008 12:43
<?php
/*
Find out start and end date of current week.
I am assuming that week starts at sunday and ends at saturday.
so a typical week will look like this: sun,mon,tue,wed,thu,fri,sat
if you find any bug/error, please email me.
*/

//sunday = start of week
$sat = 6; //saturday = end of week
$current_day=date('w');
$days_remaining_until_sat = $sat - $current_day;

$ts_start = strtotime("-$current_day days");
$ts_end = strtotime("+$days_remaining_until_sat days");

echo
date('m-d-Y',$ts_start); //start date
echo '<br>';
echo
date('m-d-Y',$ts_end); //end date

/*
OUTPUT (m-d-y):
11-09-2008
11-15-2008
*/
?>
tchapin at gmail dot com
09-Nov-2008 10:26
<?php
   
// Function used to take two date strings, and returns an associative array
    // with different formats for the difference between the dates.
    // --------------------
    // Variables:
    // StartDateString (String - MM/DD/YYYY)
    // EndDateString (String - MM/DD/YYYY)
    // --------------------
    // Example: $DateDiffAry = GetDateDifference('01/09/2008', '02/11/2009');
    // print_r($DateDiffAry);
    // --------------------
    // Returns Something Like:
    /*   
    Array
    (
        [YearsSince] => 1.0931506849315
        [MonthsSince] => 13.117808219178
        [DaysSince] => 399
        [HoursSince] => 9576
        [MinutesSince] => 574560
        [SecondsSince] => 34473600
        [NiceString] => 1 year, 1 month, and 2 days
        [NiceString2] => Years: 1, Months: 1, Days: 2
    )
    */

   
function GetDateDifference($StartDateString=NULL, $EndDateString=NULL) {
       
$ReturnArray = array();
       
       
$SDSplit = explode('/',$StartDateString);
       
$StartDate = mktime(0,0,0,$SDSplit[0],$SDSplit[1],$SDSplit[2]);
       
       
$EDSplit = explode('/',$EndDateString);
       
$EndDate = mktime(0,0,0,$EDSplit[0],$EDSplit[1],$EDSplit[2]);
       
       
$DateDifference = $EndDate-$StartDate;
       
       
$ReturnArray['YearsSince'] = $DateDifference/60/60/24/365;
       
$ReturnArray['MonthsSince'] = $DateDifference/60/60/24/365*12;
       
$ReturnArray['DaysSince'] = $DateDifference/60/60/24;
       
$ReturnArray['HoursSince'] = $DateDifference/60/60;
       
$ReturnArray['MinutesSince'] = $DateDifference/60;
       
$ReturnArray['SecondsSince'] = $DateDifference;

       
$y1 = date("Y", $StartDate);
       
$m1 = date("m", $StartDate);
       
$d1 = date("d", $StartDate);
       
$y2 = date("Y", $EndDate);
       
$m2 = date("m", $EndDate);
       
$d2 = date("d", $EndDate);
       
       
$diff = '';
       
$diff2 = '';
        if ((
$EndDate - $StartDate)<=0) {
           
// Start date is before or equal to end date!
           
$diff = "0 days";
           
$diff2 = "Days: 0";
        } else {

           
$y = $y2 - $y1;
           
$m = $m2 - $m1;
           
$d = $d2 - $d1;
           
$daysInMonth = date("t",$StartDate);
            if (
$d<0) {$m--;$d=$daysInMonth+$d;}
            if (
$m<0) {$y--;$m=12+$m;}
           
$daysInMonth = date("t",$m2);
           
           
// Nicestring ("1 year, 1 month, and 5 days")
           
if ($y>0) $diff .= $y==1 ? "1 year" : "$y years";
            if (
$y>0 && $m>0) $diff .= ", ";
            if (
$m>0) $diff .= $m==1? "1 month" : "$m months";
            if ((
$m>0||$y>0) && $d>0) $diff .= ", and ";
            if (
$d>0) $diff .= $d==1 ? "1 day" : "$d days";
           
           
// Nicestring 2 ("Years: 1, Months: 1, Days: 1")
           
if ($y>0) $diff2 .= $y==1 ? "Years: 1" : "Years: $y";
            if (
$y>0 && $m>0) $diff2 .= ", ";
            if (
$m>0) $diff2 .= $m==1? "Months: 1" : "Months: $m";
            if ((
$m>0||$y>0) && $d>0) $diff2 .= ", ";
            if (
$d>0) $diff2 .= $d==1 ? "Days: 1" : "Days: $d";
           
        }
       
$ReturnArray['NiceString'] = $diff;
       
$ReturnArray['NiceString2'] = $diff2;
        return
$ReturnArray;
    }
   
   
// Example:
   
$DateDiffAry = GetDateDifference('01/09/2008', '02/11/2009');
   
print_r($DateDiffAry);
   
?>
Grapsus
02-Nov-2008 03:38
Here's a small function which returns TRUE if European Summer Time is used (now or at a given date) :

<?php
if(!function_exists('estdst'))
{
  function
estdst($ts=false)
  {
   
$ts = $ts?$ts:time();
   
$year = gmdate('Y', $ts);
   
$end = gmmktime(1, 0, 0, 3, 31 - ((5 * $year) / 4 + 4)%7, $year);
   
$start = gmmktime(1, 0, 0, 10, 31 - ((5 * $year) / 4 + 1)%7, $year);
    return
$ts < $end || $ts > $start;
  }
}
?>

Calculation formula taken from here : http://en.wikipedia.org/wiki/European_Summer_Time
robertk113 at comcast dot net
31-Oct-2008 01:46
I need to display graphic-A during hours 1-9 and graphic-B during hours 10-24. Anybody know of a simple way to do this? Better yet, if we can select times based upon the day of the week, it would be even better!

I tried searching, but didn't inf anything resembling this. The coding will be added to a product description in osCommerce, which accepts html coding easily but other scripting types may or may not work. I want an OPEN graphic to display during normal business hours, and CLOSED when outside these hours.

Thanks in advance!
kyle renfrow
22-Oct-2008 06:41
i figured i would post this, it's only useful for systems dealing with UTC and EST, but could easily be modified to support multiple timezones. this function will tell you whether it's daylight saving time for the eastern timezone using UTC localtime:

<?php
//checks whether DST in EST using UTC
//can pass $time in unix timestamp, otherwise uses time()
function est_isdst($time=NULL){
  if(!
$time) { $now = time(); }else { $now = $time; }
  if (
      
$now > strtotime(date('Y-m-d 6:59:59', strtotime('next Sunday', strtotime(date('Y', $now).'-3-7')))) &&
      
$now < strtotime(date('Y-m-d 6:00', strtotime('first Sunday', strtotime(date('Y', $now).'-11-0'))))
     ) { return
true; }else { return false; }
}
?>

USAGE:
<?php
if(est_isdst()) { echo 'Its DST in EST Timezone!'; }
?>
adityabhai [at] gmail [dot] com
07-Oct-2008 02:56
Aditya Bhatt (adityabhai [at] gmail [dot] com):

I have one date, and i want the next day of that date:

<?php

echo date("D F d Y",strtotime("+1 days")); // Same applies for months e.g. "+1 months"

?>

I have one date, and i want the previous day of that date:

<?php

echo date("D F d Y",strtotime("-1 days")); // Same applies for months e.g. "-1 months"

?>
Kenneth Kin Lum
02-Oct-2008 03:52
date(DATE_RFC822) and date(DATE_RFC2822) both work.  note that RFC 822 is obsoleted by RFC 2822.  The main difference is the year being 08 in RFC 822 and is 2008 in RFC 2822.

To use date(DATE_RFC2822), a short form is date('r').
nick at nick-web dot co dot uk
25-Sep-2008 08:48
RE: wulf dot kaiser at mpimf-heidelberg dot mpg dot de code to work out fridays in a month. I noticed one small error. It looks like the
<?php
if ($givenMonth != '12') {

   
$nextGivenMonth = "1";
   
$nextGivenYear = $givenYear + 1;}
?>
block was setting every month to 1 because it was not equal to 12. I changed that to <?php if ($givenMonth == '12') { ?>and now all is fine!

Now - to refine it so that it only shows Fridays on the 5th or after, until the 4th of the next month.. Damm UK tax stuff!

=)
N
Anonymous
24-Sep-2008 04:35
MySQL 5 will accept ISO_8601 encoded time, so it is acceptable to use date(ISO_8601)
Anonymous
12-Sep-2008 06:01
Correct format for a MySQL DATETIME column is
<?php $mysqltime = date ("Y-m-d H:i:s", $phptime); ?>
Cortexd
27-Aug-2008 11:47
a date function supporting the milliseconds format character

<?php
function udate($format, $utimestamp = null)
{
    if (
is_null($utimestamp))
       
$utimestamp = microtime(true);

   
$timestamp = floor($utimestamp);
   
$milliseconds = round(($utimestamp - $timestamp) * 1000000);

    return
date(preg_replace('`(?<!\\\\)u`', $milliseconds, $format), $timestamp);
}

echo
udate('H:i:s.u'); // 19:40:56.78128
echo udate('H:i:s.u', 654532123.04546); // 16:28:43.45460
?>
pdubbb1 at gmail dot com
26-Aug-2008 05:32
here is the simpliest way to get the start and end date of the week;

<?php
$sdate
=date('c',strtotime(date('Y')."W".date('W')."0"));

$edate=date('c',strtotime(date('Y')."W".date('W')."7"));
?>

the format is for the string in strtotime is;
 
     2008W200

this stands for year - 2008, constant never changes - W, week number of the year - 20, day of the week - 0 for sunday, 1 for monday, etc....

so 2008W200 stands for the sunday of the 20th week of 2008. 

This will only work in php 5 or better
abazaba.ru
14-Aug-2008 03:53
All novices must be very carefull when working with timestamps as second values.
From first glance it looks like date("Y-m-d H:i:s",TIMESTAMP) will return correct date, based on "how much seconds gone from 1970".
But here is the feature, it'll be corrected time, according to LOCAL timezone.

So if you take a 25200 as timestamp (10 hours),
then on one server you'll get
1970-01-01 08:00:00
and on other server you'll get
1970-01-01 09:00:00
and so on.
Though you could expect 1970-01-01 10:00:00 in all cases, because if 25200 seconds gone from 1970-01-01 00:00:00 it obviously have to be 1970-01-01 10:00:00

I spend today 3 hours to correct scripts which were created with such error by previous programmer, so please, guys, don't make me work like this and remember about conversation to LOCAL time.
phprocks at aol dot com
06-Aug-2008 11:25
Try this for finding the difference in days between 2 dates/datetimes... take note though, date_parse requires PHP version 5.1.3 or higher.

<?php
/**
 * Finds the difference in days between two calendar dates.
 *
 * @param Date $startDate
 * @param Date $endDate
 * @return Int
 */
function dateDiff($startDate, $endDate)
{
   
// Parse dates for conversion
   
$startArry = date_parse($startDate);
   
$endArry = date_parse($endDate);

   
// Convert dates to Julian Days
   
$start_date = gregoriantojd($startArry["month"], $startArry["day"], $startArry["year"]);
   
$end_date = gregoriantojd($endArry["month"], $endArry["day"], $endArry["year"]);

   
// Return difference
   
return round(($end_date - $start_date), 0);
}
?>
JonathanCross.com
25-Jul-2008 01:22
<?php
// A demonstration of the new DateTime class for those
// trying to use dates before 1970 or after 2038.
?>
<h2>PHP 2038 date bug demo (php version <?php echo phpversion(); ?>)</h1>
<div style='float:left;margin-right:3em;'>
<h3>OLD Buggy date()</h3>
<?php
  $format
='F j, Y';
  for (
$i = 1900; $i < 2050; $i++) {
   
$datep = "$i-01-01";
   
?>
    Trying: <?php echo $datep; ?> = <?php echo date($format, strtotime($datep)); ?><br>
    <?
  }
?></div>
<div style='float:left;'>
  <h3>NEW DateTime Class (v 5.2+)</h3><?php
 
for ( $i = 1900; $i < 2050; $i++) {
   
$datep = "$i-01-01";
   
$date = new DateTime($datep);
   
?>
    Trying: <?php echo $datep; ?> = <?php echo $date->format($format); ?><br>
    <?
  }
?></div>
Rob A.
10-Jul-2008 09:38
Quick function for returning the names of the next 7 days of the week starting with today.

Returns an array that can be formatted to your liking.

<?php
/**
* Returns array of next 7 days starting with today
*
*/

function next_7_days() {
       
// create array of day names. You can change these to whatever you want
   
$days = array(
                           
'Monday',
                           
'Tuesday',
                           
'Wednesday',
                           
'Thursday',
                           
'Friday',
                           
'Saturday',
                           
'Sunday');
   
$today = date('N');
    for (
$i=1;$i<$today;$i++) {

               
// take the first element off the array
       
$shift = array_shift($days);

               
// ... and add it to the end of the array
       
array_push($days,$shift);
    }
       
// returns the sorted array
   
return $days;
}
?>

It basically takes an array starting with Monday and shifts each day to the end of the array until the first element in the array is today.
con_tobe at yahoo dot com
09-Jul-2008 08:46
Doing $w-- for months ending on Sat won't hurt (i.e. if you're counting weeks as is the case below), but halocastle's code is perfectly fine as is and quite fast.  He/she uses $w as a key for the $weeks array.  "Halo" does this BEFORE $w++, so $w-- is superfluous as the loop has already ended.  For May, 2008, I get 5 weeks as expected...

Array
(
    [1] => Array
        (
            [4] => 1
            [5] => 2
            [6] => 3
        )

    [2] => Array
        (
            [0] => 4
            [1] => 5

------------OMITTED-----------------

            [4] => 22
            [5] => 23
            [6] => 24
        )

    [5] => Array
        (
            [0] => 25
            [1] => 26
            [2] => 27
            [3] => 28
            [4] => 29
            [5] => 30
            [6] => 31
        )

)

I guess the one pit-fall of the code is if you overlap months, say the following year, then $m-- makes perfect since...I think (haven't gotten that far...yet).

I modified "Halo's" code to include months, too (this is from a snippet that produces a three month calendar, hence the outer $months loop, omitted here).

<?php
$m
= date('m');
$Y = date('Y');

// for() {months loop omitted
$var_date = mktime(0, 0, 0, $m, 1, $Y);
$month_name = date('F', $var_date);
$months[$month_name]['DAYS'] = date('t', $var_date);
$months[$month_name]['FIRST_DAY'] = date('w', $var_date);
//}
foreach($months as $month => $key) {
 
$weeks = array();
  for(
$i = 1, $j = $key['FIRST_DAY'], $w = 1;$i <= $key['DAYS'];$i++) {
   
$weeks[$w][$j] = $i;
   
$j++;
    if(
$j == 7) {
     
$j = 0;
     
$w++;
    }
  }
 
$months[$month]['WEEKS'] = $weeks;
}
?>

Enjoy!
dmagick at gmail dot com
02-Jul-2008 07:44
Slight amendment to halocastle at yahoo dot com 's code as it doesn't take into account when a month finishes on a Saturday (eg May 2008).

<?php
$start_date
= mktime(0, 0, 0,$start_month, 1, $start_year);

$days_in_month = date('t', $start_date);
$month_first_day = date('w', $start_date);

$j = $month_first_day;
$num_weeks = 1;

for(
$i = 1; $i <= $days_in_month; $i++) {
   
$j++;
    if(
$j == 7) {
       
$j = 0;
       
$num_weeks++;
    }
}

// if the last day of the month happens to be a Saturday,
// take one off the number of weeks
// because it was being added inside the for loop.
if ($j == 0) {
   
$num_weeks--;
}
?>
halocastle at yahoo dot com
30-Jun-2008 09:20
Weeks and days for any month/year combo:

<?php
$m
= 2; // February
$Y = 2008;

// constants used here for legibility, use $vars for dynamicon...
define('MONTH_DAYS',date('t', strtotime(date($m . '/01/' . $Y))));
// w:0->6 = Sun->Sat
define('MONTH_FIRST_DAY',date('w', strtotime(date($m . '/01/' . $Y))));

for(
$i = 1, $j = MONTH_FIRST_DAY, $w = 1;$i <= MONTH_DAYS;$i++) {
 
$week[$w][$j] = $i;
 
$j++;
  if(
$j == 7) {
   
$j = 0;
   
$w++;
  }
}
?>

print_r($week):
-----------------------
Array
(
    [1] => Array
        (
            [5] => 1
            [6] => 2
        )

    [2] => Array
        (
            [0] => 3
            [1] => 4
            [2] => 5
            [3] => 6
            [4] => 7
            [5] => 8
            [6] => 9
        )

    [3] => Array
        (
            [0] => 10
            [1] => 11
            [2] => 12
            [3] => 13
            [4] => 14
            [5] => 15
            [6] => 16
        )

    [4] => Array
        (
            [0] => 17
            [1] => 18
            [2] => 19
            [3] => 20
            [4] => 21
            [5] => 22
            [6] => 23
        )

    [5] => Array
        (
            [0] => 24
            [1] => 25
            [2] => 26
            [3] => 27
            [4] => 28
            [5] => 29
        )

)
Kavi Siegel
29-Jun-2008 07:18
I wrote the following function to show a series of drop down boxes to select the date. When provided with a timestamp, that date is selected by default, when none is provided, the current date is selected.

<?php
function chooseDate($timestamp = ""){
    if(
$timestamp == ""){
       
$timestamp = time();
    }
   
$months = array(null, 'Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec');
    unset(
$months[0]);
   
print_r($months);
   
$out = '<select name="month">';
    foreach(
$months as $key => $month){
        if(
$month == date('M', $timestamp)){
           
$out .= '<option value="'.$key.'" selected="selected">'.$month.'</option>';
        }else{
           
$out .= '<option value="'.$key.'">'.$month.'</option>';
        }
    }
   
$out .= '</select><select name="days">';
    for(
$i = 1; $i <= 32; $i++){
        if(
$i == date('j', $timestamp)){
           
$out .= '<option value="'.$i.'" selected="selected">'.$i.'</option>';
        }else{
           
$out .= '<option value="'.$i.'">'.$i.'</option>';
        }
    }
   
$out .= "</select><select name='year'>";
    for(
$i = date('Y'); $i >= 1970; $i--){
        if(
$i == date('Y', $timestamp)){
           
$out .= '<option value="'.$i.'" selected="selected">'.$i.'</option>';
        }else{
           
$out .= '<option value="'.$i.'">'.$i.'</option>';
        }
    }
   
$out .= "</select>";
    return
$out;
}
?>

Usage is simple:

<?php
echo chooseDate(); // Will select current date
echo chooseDate(1149566400); // Will select June 6th, 2006
?>
aplarsen
26-Jun-2008 01:12
@anonymous (12-Jun-2008 08:45):
date("t") returns the last day of the month, not the last working day of the month.

A cleaner example would be as follows:
<?php
function lastworkingday($date)
{   
   for(
$lastday=mktime(0,0,0,date("m",$date),
      
date("t",$date),date("Y",$date));
    
date("w",$lastday)==0 || date("w",$lastday)==6;
    
$lastday-=60*60*24);
   return
date("j",$lastday);
}
?>
kontakt at arthur minus schiwon dot de
18-Jun-2008 03:29
to get the week of the month simply use:
ceil( date("j") / 7 );
diego at diego dot eng dot br
09-Jun-2008 04:27
I made a small code to get the last working day of the month:

<?php

$times
= strtotime(date("Y")."-".date("m")."-".date("t"));
for (
$lastworkingday=0;$lastworkingday==0;$times-=86400)
   if (
date("w",$times)!=0 && date("w",$times)!=6) $lastworkingday = date("j",$times);
print
$lastworkingday;

?>
phil dot taylor at enilsson dot com
25-May-2008 10:37
Found this helpful when converting unix dates for use with the ical file format.

<?php
// Converts a unix timestamp to iCal format (UTC) - if no timezone is
// specified then it presumes the uStamp is already in UTC format.
// tzone must be in decimal such as 1hr 45mins would be 1.75, behind
// times should be represented as negative decimals 10hours behind
// would be -10
       
   
function unixToiCal($uStamp = 0, $tzone = 0.0) {
   
       
$uStampUTC = $uStamp + ($tzone * 3600);       
       
$stamp  = date("Ymd\THis\Z", $uStampUTC);
       
        return
$stamp;       

    }
?>
chubby at chicks dot com
23-May-2008 06:54
<?php
/**
     * Checks wether a date is between an interval
     *
     * Usage:
     *     
     * // check if today is older than 2008/12/31
     * var_dump(currentDayIsInInterval('2008/12/31'));
     * // check if today is younger than 2008/12/31
     * var_dump(currentDayIsInInterval(null,'2008/12/31'));
     * // check if today is between 2008/12/01 and 2008/12/31
     * var_dump(currentDayIsInInterval('2008/12/01','2008/12/31')); 
     *
     * Will trigger errors if date is in wrong format, notices if $begin > $end    
     *         
     * @param string $begin Date string as YYYY/mm/dd
     * @param string $end Date string as YYYY/mm/dd
     * @return bool 
     */
function currentDayIsInInterval($begin = '',$end = '')
{
       
$preg_exp = '"[0-9][0-9][0-9][0-9]/[0-9][0-9]/[0-9][0-9]"';
       
$preg_error = 'Wrong parameter passed to function '.__FUNCTION__.' : Invalide date
format. Please use YYYY/mm/dd.'
;
       
$interval_error = 'First parameter in '.__FUNCTION__.' should be smaller than
second.'
;
        if(empty(
$begin))
        {
               
$begin = 0;
        }
        else
        {
                if(
preg_match($preg_exp,$begin))
                {
                       
$begin = (int)str_replace('/','',$begin);
                }
                else
                {
                       
trigger_error($preg_error,E_USER_ERROR);
                }
        }
        if(empty(
$end))
        {
               
$end = 99999999;
        }
        else
        {
                if(
preg_match($preg_exp,$end))
                {
                       
$end = (int)str_replace('/','',$end);
                }
                else
                {
                       
trigger_error($preg_error,E_USER_ERROR);
                }
        }
        if(
$end < $begin)
        {
               
trigger_error($interval_error,E_USER_WARNING);
        }
       
$time = time();
       
$now = (int)(date('Y',$time).date('m',$time).date('j',$time));
        if(
$now > $end or $now < $begin)
        {
                return
false;
        }
        return
true;
}
?>
wilson dot p dot pereira at itelefonica dot com dot br
21-May-2008 08:37
The function below extracts any date time value basead in the string format.
Returns an associative array with day,month,year,hour,min and seg separated.

<?php
function ExtractDateTimeByFormat($strDateTime, $strFormat="dmYHis")
{
 
//extract the format
 
$i = 0;
 
$aFieldOrder = array();
 
$nFields = 0;
       
$strExtraction = "";
        while(isset(
$strFormat[$i]))
        {
           
$strField = $strFormat[$i];
            switch (
strtolower($strField) )
            {
                case
"D";
                case
"d";
                   
$aFieldOrder[$nFields] =