[edit] Last updated: Fri, 23 Mar 2012

mktime

(PHP 4, PHP 5)

mktime — Bir tarih için Unix zaman damgasını döndürür

Açıklama

int mktime ([ int $saat = date("H") [, int $dakika = date("i") [, int $saniye = date("s") [, int $ay = date("n") [, int $gün = date("j") [, int $yıl = date("Y") [, int $ysu_var = -1 ]]]]]]] )

Verilen değiştirge düzenine göre Unix zaman damgasını döndürür. Bu zaman damgası, Unix Zaman Başlangıcı (1 Ocak 1970 00:00:00 GMT) ile belirtilen zaman arasında geçen süreyi uzun tamsayı türünde saniye olarak belirtir.

Değiştirgeler sağdan sola sıralıdır; böylece belirtilmeyen bir değiştirge yerine yerel tarih ve zamana göre geçerli değerin kullanılması sağlanmıştır.

Notlar

Bilginize:
PHP 5.1'den itibaren, mktime() değiştirgesiz çağrıldığına bir E_STRICT uyarısı çıktılamaktadır. Böyle durumlarda time() işlevini kullanmalısınız.

Değiştirgeler

saat: Saat sayısı.
dakika: Dakika sayısı.
saniye: Son dakikanın geçen saniye sayısı.
ay: Ay sayısı.
gün: Gün sayısı.
yıl: Yıl sayısı, iki ya da dört hane olabilir. 0-69 değerleri arasında olanlar 2000-2069 ile ve 70-100 arasındaki değerler ise 1970-2000 yıllarıyla eşleşir. Sistemlerdeki time_t türü 32 bit işaretli tamsayı türüyle belirtilmiştir ve günümüzde çok kullanılmaktadır. yıl değiştirgesi için geçerli aralık 1901 ve 2038 arasındadır. Bununla birlikte, PHP 5.1.0 sürümünden önce bu aralık bazı sistemlerde 1970 ve 2038 arasında sınırlıydı (ör. Windows).
ysu_var: Bu değiştirge, yaz saati uygulaması varsa 1'e yoksa 0'a ya da yaz saati uygulması olup olmadığının bilinmediği durumlarda varsayılan değere yani -1'e ayarlanmalıdır. Bilinmeyen durumlarda PHP bunu çözümleyecektir. Bu beklenmeyen sonuçlara (fakat yanlış olmayan) neden olur. Bazı zamanlarda, PHP çalışırken YSU etkinleştirildiğinde ya da ysu_var değiştirgesi 1'e ayarlandığında zaman geçersiz olur. Örneğin, eğer saat 2:00'de YSU etkinleştirilirse, 2:00 ve 3:00 arasındaki tüm zaman geçersiz olacak ve mktime() işlevi anlamsız (genellikle negatif) bir değerle dönecektir. Bazı sistemlerde (ör. Solaris 8) YSU gece yarısında etkinleşir. YSU etkinleştiğinde saat 0:30 ise, saat bir önceki günün 23:30'u olarak değerlendirilecektir.

Bilginize:
PHP 5.1.0 sürümünden beri, bu değiştirgenin kullanılması önerilmemektedir. Sonuç olarak, yerine yeni zaman dilimi özellikleri kullanılmalıdır.

Dönen Değerler

mktime() işlevi verilen değiştirgelerden elde edilen Unix zaman damgası döndürür. Eğer değiştirge geçersiz ise işlev FALSE değeriyle döner (PHP 5.1 sürümünden önce -1 dönerdi).

Hatalar/İstisnalar

Bir tarih/zaman işlevine yapılan her çağrı eğer zaman dilimi ayarı geçerli değilse bir E_NOTICE üretir. Ve/veya eğer sistem ayarları veya TZ ortam değişkeni kullanılıyorsa bir E_STRICT veya bir E_WARNING iletisi üretir. Ayrıca bakınız: date_default_timezone_set()

Sürüm Bilgisi

Sürüm:	Açıklama
5.3.0	Artık mktime() işlevi, `ysu_var` değiştirgesi kullanılırsa `E_DEPRECATED` uyarısı vermektedir.
5.1.0	`ysu_var` değiştirgesinin kullanımı artık önerilmemektedir. İşlev hata durumunda -1 yerine, `FALSE` değeri döndürür olmuştur. İşlev, yıl, ay ve gün değiştirgelerinde sıfır kabul edecek şekilde düzeltilmiştir.
5.1.0	mktime() değiştirgesiz çağrıldığına bir `E_STRICT` uyarısı çıktılamaktadır. Böyle durumlarda time() işlevini kullanmalısınız.
5.1.0	Zaman dilimi hatalarında artık `E_STRICT` ve `E_NOTICE` çıktılanıyor.

Örnekler

Örnek 1 - Basit bir mktime() örneği


<?php
// Öntanımlı zaman dilimini belirtelim. PHP 5.1'den beri kullanılabiliyor.
date_default_timezone_set('UTC');

echo "July 1, 2000 is on a " . date("l", mktime(0, 0, 0, 7, 1, 2000));
// Çıktısı: July 1, 2000 is on a Saturday

echo date('c', mktime(1, 2, 3, 4, 5, 2006));
// Şöyle bir şey basar: 2006-04-05T01:02:03+00:00
?>

Örnek 2 - mktime() örneği

mktime() işlevi tarih hesaplamaları ve geçerlilik denetimi için kullanışlıdır. Aralık dışına çıkan değerleri (ayın 32'si gibi) özdevinimli olarak doğru hesaplar. Örneğin, aşağıdaki satırların üreteceği dizge "Jan-01-1998" olacaktır.


<?php
echo date("M-d-Y", mktime(0, 0, 0, 12, 32, 1997));
echo date("M-d-Y", mktime(0, 0, 0, 13, 1, 1997));
echo date("M-d-Y", mktime(0, 0, 0, 1, 1, 1998));
echo date("M-d-Y", mktime(0, 0, 0, 1, 1, 98));
?>

Örnek 3 - Gelecek ayın son günü

Verilen herhangi bir ayın son günü, gelecek ayın -1'inci değil 0'ıncı günü olarak ifade edilebilir. Aşağıdaki iki örnek de "2000 Şubat'ının son günü: 29" dizgesi üretilecektir.


<?php
$songün = mktime(0, 0, 0, 3, 0, 2000);
echo strftime("2000 Şubat'ının son günü: %d", $songün);
$songün = mktime(0, 0, 0, 4, -31, 2000);
echo strftime("2000 Şubat'ının son günü: %d", $songün);
?>

Notlar

Dikkat

PHP 5.1.0 sürümünden önce, negatif zaman damgaları bilinen Windows sürümleri altında ve diğer benzer sistemlerde desteklemiyordu. Bundan dolayı, geçerli yılların aralığı 1970 ile 2038 arasında sınırlıydı.

Ayrıca Bakınız

gmmktime() - Bir GMT tarihi için Unix zaman damgasını döndürür
date() - Yerel tarihi/saati biçimlendirir
time() - Geçerli Unix zaman damgasını döndürür

strftime

microtime

[edit] Last updated: Fri, 23 Mar 2012

add a note User Contributed Notes mktime

tothpeter at fbi dot hu 20-Mar-2012 01:52


using on mac with MAMP



$a=mktime(0,0,0,07,01,2012);

echo date('Y-m-d',$a); // 2012-07-01



$a=mktime(0,0,0,08,01,2012);

echo date('Y-m-d',$a); // 2011-12-01 WTF



$a=mktime(0,0,0,09,01,2012);

echo date('Y-m-d',$a); // 2011-12-01 WTF



$a=mktime(0,0,0,10,01,2012);

echo date('Y-m-d',$a); // 2012-10-01



$a=mktime(0,0,0,07,31,2012);

echo date('Y-m-d',$a); // 2012-07-31



WTF?

gustavo at ci dot eel dot usp dot br 24-Feb-2012 12:23


Number of the weeks in a determined month





<?php





$lastDay = date("d",mktime (0,0,0,9+1,0,$year));


 $firstWeekDay = @date("w", @mktime(0,0,0,9,1,2012));


 $weekNumber = ($lastDay == 30 && $firstWeekDay == 6 || $lastDay == 31 && $firstWeekDay >= 5) ? 6 : (($lastDay == "28" && $firstWeekDay == "0") ? 4 : 5);





?>

info at microweb dot lt 03-Nov-2010 07:42


Function to generate array of dates between two dates (date range array)





<?php


function dates_range($date1, $date2)


{


   if ($date1<$date2)


   {


       $dates_range[]=$date1;


       $date1=strtotime($date1);


       $date2=strtotime($date2);


       while ($date1!=$date2)


       {


           $date1=mktime(0, 0, 0, date("m", $date1), date("d", $date1)+1, date("Y", $date1));


           $dates_range[]=date('Y-m-d', $date1);


       }


   }


   return $dates_range;


}





echo '<pre>';


print_r(dates_range('2009-12-25', '2010-01-05'));


echo '</pre>';


?>





[EDIT BY danbrown AT php DOT net: Contains a bugfix submitted by (carlosbuz2 AT gmail DOT com) on 04-MAR-2011, with the following note: The first date in array is incorrect.]

php at wirnhier dot de 02-Nov-2010 09:17


warning: mktime expects parameter 1 to be long



It could be a string that is given to mktime, so it has to be converted into an int.



mktime((int)$h, (int)$m, (int)$s, (int)$m, (int)$d, (int)$y);

xr714 at yahoo dot com 07-Oct-2010 08:58


One of the many problems with Daylight Saving Time / Summer Time is the ambiguity when a specified local time value can refer to two different actual times!  This happens when the local time value is within the relapse range caused by the clocks being set back to proper time.  (eg. if the DST/ST bias is +1 hour, and DST/ST terminates at 02:00 local time, a local time value of 01:30 occurs twice in the same day!)



Because the mktime() function only returns one value, it silently chooses whether to return the time-stamp for the first iteration or the second iteration of a specified local time within this critical range.



To get both possible time-stamps for a local time, compatible with any system locale, time zone, and applicable DST/ST rules, the following function can be used:



<?php /*><!--*/

function LocalToUT($LocalYear, $LocalMonth, $LocalMonthDay, $LocalHour24, $LocalMinute, $LocalSecond) {

/* Converts local date/time to Universal Time values.  Returns both

possible UT values when local time value is within relapse range

(due to Daylight Saving Time / Summer Time termination).

Notes:

    Conversion based on TZ and DST/ST rules used by mktime() function.

    UT time-stamps are number of UT seconds since midnight Jan 1, 1970 UTC.

    UT does not have leap seconds; a UT second is "stretched" by 2x duration

to maintain synchronization with UTC when a UTC leap second elapses.

Inputs:    All inputs are numeric; $LocalHour24 is in 24-hour format.

Returns: Array:

    'initial' = UT time-stamp of first occurrence of specified local date/time

    'relapse' = UT time-stamp of second occurrence, when local time relapses upon DST/ST termination

*/

    $UTValue = mktime($LocalHour24, $LocalMinute, $LocalSecond, $LocalMonth, $LocalMonthDay, $LocalYear);

    $ReturnData = array('initial' => $UTValue, 'relapse' => $UTValue);

    //Test for DST/ST transition since prev day

    $Bias = $UTValue - mktime($LocalHour24, $LocalMinute, $LocalSecond, $LocalMonth, $LocalMonthDay - 1, $LocalYear) - 86400;    //(-) = DST/ST commence, (+) = DST/ST terminate

    if ($Bias == 0) {    //No DST/ST transition detected since prev day

        //Test for DST/ST transition up to next day

        $Bias = mktime($LocalHour24, $LocalMinute, $LocalSecond, $LocalMonth, $LocalMonthDay + 1, $LocalYear) - $UTValue - 86400;    //(-) = DST/ST commence, (+) = DST/ST terminate

    }

    if ($Bias > 0) {    //DST/ST termination detected

        if (date('Z', $UTValue) !== date('Z', $UTValue + $Bias)) {    //Local time occurred in relapse range; System assumed 1st iteration

            $ReturnData['relapse'] = $UTValue + $Bias;

        }

        if (date('Z', $UTValue - $Bias) !== date('Z', $UTValue)) {    //Local time occurred in relapse range; System assumed 2nd iteration

            $ReturnData['initial'] = $UTValue - $Bias;

        }

        //Else local time is outside of relapse range

    }    //Else no DST/ST transition, or transition is commencement

    return $ReturnData;

}

/*--></?php */?>



Do not be confused by the start and end tags; The interleaved PHP-comment and HTML-comment delimiters prevent PHP code containing ">" from appearing as literal text when viewing or editing an HTML file with embedded PHP code.

enVide neFelibata 26-Sep-2010 06:34


I've had this query for an event organizer.



<?php

   $query = "SELECT MAX(dt_atfrom) FROM tb_date LIMIT 1";

   $raw_data = mysql_query($query);

   $maxdate = mysql_result($raw_data,0,0);

?>

It would fetch the 'bigger' date of all of those events.

The problem started when having events in the future.



I'll start to explain.

Imagine you're in '2010' and the biggest event date is '2011-06-05'.

$maxdate will return me the correct data '2011-06-05', yet since I was only needing the year i passed this date through the following function:



<?php

   maxyear = date("Y", mktime($maxdate));

?>



mktime was returning me the actual year for every future event instead of the future year.



I ended up doing the following:



<?php

   $maxyear = substr($maxdate,0,4);

?>



Probably there's a better solution...

tom at chegg dot com 31-Aug-2010 02:01


I was using the following to get a list of month names.



for ($i=1; $i<13; $i++) {

  echo date('F', mktime(0,0,0,$i) . ",";

}



Normally this outputs -

January,February,March,April,May,June,July,August,

September,October,November,December



However if today's date is the 31st you get instead:

January,March,March,May,May,July,July,August,October,

October,December,December



Why? Because Feb,Apr,June,Sept, and Nov don't have 31 days!



The fix, add the 5th parameter, don't let the day of month default to today's date:



  echo date('F', mktime(0,0,0,$i,1) . ",";

zfowler at unomaha dot edu 16-Mar-2010 02:18


Proper way to convert Excel dates into PHP-friendly timestamps using mktime():





<?php


// The date 6/30/2009 is stored as 39994 in Excel


$days = 39994;





// But you must subtract 1 to get the correct timestamp


$ts = mktime(0,0,0,1,$days-1,1900);





// So, this would then match Excel's representation:


echo date("m/d/Y",$ts);


?>





Excel uses "number of days since Jan. 1, 1900" to store its dates.  It also treats 1900 as a leap year when it wasn't, thus there is an extra day which must be accounted for in PHP (and the rest of the world).  Subtracting 1 from Excel's number will fix this problem.

contact at phpmember dot com 19-Jan-2010 04:45


How many days have  passed since the beginning of the year.... regardless of what year it is...





<?php


//Carlos Galindo


//phpmember.com





$days = floor((time()-mktime(null,null,null,1,0,date("Y")))/86400);


            


echo "$days days have passed";





//Good Luck


?>

davix 06-Oct-2009 12:39


I couldn't find any correct date differentiate function anywhere so I wrote this one which works correctly. It's fully resistant to all troubles with different day count of the month or leap year.

Input must be two timestamps and output is associative array with year, month, day, hour, minute, second items.

It can be used for exact age or similar issues.



<?php

function date_diff($d1, $d2){

/* compares two timestamps and returns array with differencies (year, month, day, hour, minute, second)

*/

  //check higher timestamp and switch if neccessary

  if ($d1 < $d2){

    $temp = $d2;

    $d2 = $d1;

    $d1 = $temp;

  }

  else {

    $temp = $d1; //temp can be used for day count if required

  }

  $d1 = date_parse(date("Y-m-d H:i:s",$d1));

  $d2 = date_parse(date("Y-m-d H:i:s",$d2));

  //seconds

  if ($d1['second'] >= $d2['second']){

    $diff['second'] = $d1['second'] - $d2['second'];

  }

  else {

    $d1['minute']--;

    $diff['second'] = 60-$d2['second']+$d1['second'];

  }

  //minutes

  if ($d1['minute'] >= $d2['minute']){

    $diff['minute'] = $d1['minute'] - $d2['minute'];

  }

  else {

    $d1['hour']--;

    $diff['minute'] = 60-$d2['minute']+$d1['minute'];

  }

  //hours

  if ($d1['hour'] >= $d2['hour']){

    $diff['hour'] = $d1['hour'] - $d2['hour'];

  }

  else {

    $d1['day']--;

    $diff['hour'] = 24-$d2['hour']+$d1['hour'];

  }

  //days

  if ($d1['day'] >= $d2['day']){

    $diff['day'] = $d1['day'] - $d2['day'];

  }

  else {

    $d1['month']--;

    $diff['day'] = date("t",$temp)-$d2['day']+$d1['day'];

  }

  //months

  if ($d1['month'] >= $d2['month']){

    $diff['month'] = $d1['month'] - $d2['month'];

  }

  else {

    $d1['year']--;

    $diff['month'] = 12-$d2['month']+$d1['month'];

  }

  //years

  $diff['year'] = $d1['year'] - $d2['year'];

  return $diff;    

}



$born_date = mktime(6,30,0,7,24,2008);

$date_diff_array = date_diff($born_date, time());

print_r($date_diff_array);

?>

cebleo at n-trance dot net 08-Sep-2009 11:36


to ADD or SUBSTRACT times NOTE that if you dont specify the UTC zone your result is the difference +- your server UTC delay.





if you are ina utc/GMT +1





<?php


$hours_diff = strtotime("20:00:00")-strtotime("19:00:00");


echo  date('h:i', $hours_diff)." Hours";


?>





it shows: 02:00 Hours





but if you use a default UTC time:





<?php


date_default_timezone_set('UTC');


$hours_diff = strtotime("20:00:00")-strtotime("19:00:00");


echo "<br>". date('h:i', $hours_diff);


?>





it shows: 01:00 Hours.

p2409 at hotmail dot com 02-Aug-2009 08:49


How to get the first and last dates of the last quarter - useful for things like tax return dates etc.  by Justin



<?php

function getLastQuarter() {

    // Returns an array with a start and end date for the last quarter from todays date

    // eg. If today is 23 Feb 2009, returns $x['start'] = 1 Oct 2008, $x[end] = 31 Dec 2008

    $year = date("Y",mktime());

    $month = date("m",mktime());

    // Formula to get a quarter in the year from a month

    $startmth = $month - 3 - (($month-1) % 3 );

    // Fix up Jan - Feb to get LAST year's quarter dates (Oct - Dec)

    if ($startmth == -2) {

        $startmth+=12;

        $year-=1;

    }

    $endmth = $startmth+2;

    $last_quarter['start'] = mktime(0,0,0,$startmth,1,$year);

    $last_quarter['end'] = mktime(0,0,0,$endmth,date("t",mktime(0,0,0,$endmth,1,$year)),$year);

    return $last_quarter;    

}



// Example - print first and last dates of last quarter.

echo "First day of last quarter was : " . date("d-M-Y",$lastquarter['start']) . "\n";

echo "Last day of last quarter was : " . date("d-M-Y",$lastquarter['end']) . "\n";



// For 2 August 2009, returns:

//    First day of last quarter was : 01-Apr-2009

//    Last day of last quarter was : 30-Jun-2009

//

?>

lucianoiw at hotmail dot com 13-Mar-2009 05:48


Convert timestamp to time();





<?php


function wp_mktime($_timestamp = ''){


    if($_timestamp){


        $_split_datehour = explode(' ',$_timestamp);


        $_split_data = explode("-", $_split_datehour[0]);


        $_split_hour = explode(":", $_split_datehour[1]);





        return mktime ($_split_hour[0], $_split_hour[1], $_split_hour[2], $_split_data[1], $_split_data[2], $_split_data[0]);


    }


}


?>





[NOTE BY danbrown AT php DOT net: See also (http://php.net/strtotime)]

admin at stipe dot info 16-Feb-2009 02:12


With combination of mktime and getDate and date() you can add hours / seconds / days / months / years to ANY timestamp. Use strtotime() function to convert any type of dates to timestamp



<?php

    public function addMonthToDate($timeStamp, $totalMonths=1){

        // You can add as many months as you want. mktime will accumulate to the next year.

        $thePHPDate = getdate($timeStamp); // Covert to Array    

        $thePHPDate['mon'] = $thePHPDate['mon']+$totalMonths; // Add to Month    

        $timeStamp = mktime($thePHPDate['hours'], $thePHPDate['minutes'], $thePHPDate['seconds'], $thePHPDate['mon'], $thePHPDate['mday'], $thePHPDate['year']); // Convert back to timestamp

        return $timeStamp;

    }

    

    public function addDayToDate($timeStamp, $totalDays=1){

        // You can add as many days as you want. mktime will accumulate to the next month / year.

        $thePHPDate = getdate($timeStamp);

        $thePHPDate['mday'] = $thePHPDate['mday']+$totalDays;

        $timeStamp = mktime($thePHPDate['hours'], $thePHPDate['minutes'], $thePHPDate['seconds'], $thePHPDate['mon'], $thePHPDate['mday'], $thePHPDate['year']);

        return $timeStamp;

    }



    public function addYearToDate($timeStamp, $totalYears=1){

        $thePHPDate = getdate($timeStamp);

        $thePHPDate['year'] = $thePHPDate['year']+$totalYears;

        $timeStamp = mktime($thePHPDate['hours'], $thePHPDate['minutes'], $thePHPDate['seconds'], $thePHPDate['mon'], $thePHPDate['mday'], $thePHPDate['year']);

        return $timeStamp;

    }

?>

ronnie dot kurniawan at gmail dot com 16-Jan-2009 09:49


Add (and subtract) unixtime:





<?php


function utime_add($unixtime, $hr=0, $min=0, $sec=0, $mon=0, $day=0, $yr=0) {


  $dt = localtime($unixtime, true);


  $unixnewtime = mktime(


      $dt['tm_hour']+$hr, $dt['tm_min']+$min, $dt['tm_sec']+$sec,


      $dt['tm_mon']+1+$mon, $dt['tm_mday']+$day, $dt['tm_year']+1900+$yr);


  return $unixnewtime;


}


?>

electriic ink 17-Dec-2008 11:30


Days until Christmas:



<?php

     $time = mktime(0, 0, 0, 12, 25, 2008, 1) - time();



     $days = floor($time/86400);

     $hours = floor(($time-($days*86400))/3600);

     $mins = floor (($time-($days*86400)-($hours*3600))/60);

     $secs = floor ($time-($days*86400)-($hours*3600)-($mins*60));



     $tsecs = $time;

     $thours = round($time/3600);



     

     if ($tsecs <= 600) {



      echo '<html> <head> <title> ' . $tsecs . ' seconds left until 12am Christmas Day </title> <meta http-equiv="refresh" content="1;url=""></head> <body><span 



style="font-size:10pt">Christmas day in ' . $days . ' days ' . $hours . ' hours ' .  $mins . ' mins ' . $secs . ' seconds!<br><br>(There are ' . $tsecs . ' seconds in 



total)</span></body></html>';

    

     } else {



      echo '<html> <head> <title> ' . $thours . ' hours left until 12am Christmas Day </title> <meta http-equiv="refresh" content="10;url=""></head> <body><span 



style="font-size:10pt">Christmas day in ' . $days . ' days ' . $hours . ' hours ' .  $mins . ' mins ' . $secs . ' seconds!<br><br>(There are ' . number_format($thours) 



. ' hours in total and ' . number_format($tsecs) . ' seconds in total)</span></body></html>';



     }



?>

Alan 18-Nov-2008 07:52


Do remember that, counter-intuitively enough, the arguments for month and day are inversed (or middle-endian). A common mistake for Europeans seems to be to feed the date arguments in the expected order (big endian or little endian).



It's clear to see where this weird order comes from (even with the date being big endian the order for all arguments would still be mixed - it's obviously based on the American date format with the time "prefixed" to allow an easier shorthand) and why this wasn't changed (passing the values in the wrong order produces a valid, though unexpected, result in most cases), but it continues to be a source of confusion for me whenever I come back to PHP from other languages or libraries.

Anonymous 14-Nov-2008 08:34


<?php


//example of functions to know if a date/time value is in summer hour or in winter hour





//====================


function getChgWinDate($dt){


 $y=substr($dt,0,4);


 for($i=31;$i>20;$i--){


  $ts=mktime(3,0,0,10,$i,$y);


  $dy=date('D',$ts);


  if($dy=='Sun') return($y.'/10/'.$i.' 03:00:00');


 }


}


//====================


function getChgSumDate($dt){


 $y=substr($dt,0,4);


 for($i=31;$i>20;$i--){


  $ts=mktime(2,0,0,10,$i,$y);


  $dy=date('D',$ts);


  if($dy=='Sun') return($y.'/03/'.$i.' 02:00:00');


 }


}


//====================


function isSummerDate($dt){


 $b1=getChgWinDate($dt);


 $b2=getChgSumDate($dt);


 if($dt>=$b2&&$dt<$b1) return(true);


 return(false);


}


//====================


function isWinterDate($dt){


 return(!isSummerDate($dt));


}





//====================


$dt = '2008/10/26 03:15:16';


if( isSummerDate($dt) ){


 echo $dt . " is summer hour in france";


}else{


 echo $dt . " is winter hour in france";


}


?>

thebloodyharry at gmail dot com 10-Nov-2008 06:04


here simple sample for timestamps.(using malaysia GMT 8)



$mkendtimep=mktime(date("H")+8, date("i"), date("s"), date("m"), date("d"), date("Y"));



$todaydate=date("(d/m/y) H:i:s", $mkendtimep);

if (date("l")=="Monday") { $mday=Monday; } else

    if (date("l")=="Tuesday") { $mday=Tuesday; } else

    if (date("l")=="Wednesday") { $mday=Wednesday; } else

    if (date("l")=="Thursday") { $mday=Thursday; } else

    if (date("l")=="Friday") { $mday=Friday; } else

    if (date("l")=="Saturday") { $mday=Saturday; } else

    if (date("l")=="Sunday"){  $mday=Sunday; } 



$realtime="$mday$todaydate (GMT +8)";



..hope it will help you out....

yan 10-Nov-2008 05:50


caculate days between two date



<?php

  // end date is 2008 Oct. 11 00:00:00

  $_endDate = mktime(0,0,0,11,10,2008);

  // begin date is 2007 May 31 13:26:26

  $_beginDate = mktime(13,26,26,05,31,2007);



  $timestamp_diff= $_endDate-$_beginDate +1 ;

  // how many days between those two date

  $days_diff = $timestamp_diff/86400;



?>

Maffu 29-Oct-2008 03:05


When calling mktime(), be sure that you use values without leading zeros.  The date comes out wrong in the following example:



$endts = mktime(12, 00, 00, 12, 08, 2008, 0);



(note the 08 instead of just 8)



C's scanf() has a format specification where leading 0's can indicate an octal value - perhaps this is related?

mark at markfiend dot com 15-Oct-2008 04:52


zola at zolaweb:



Your expression date('U', strtotime($mydate)) evaluates to strtotime($mydate). Converting to a UNIX timestamp is what strtotime() does.

ionut dot bodea at eydos dot ro 02-Oct-2008 08:29


Here is what I use to calculate age. It took me 30 minutes to write and it's quite accurate. What it has special is that it's calculating the number of days a year has (float number), by testing if a year is a leap one or not. This number is used to compute the age.





<?php


function get_age($date_start, $date_end) {


    $t_lived = get_timestamp($date_end) - get_timestamp($date_start);


    $seconds_one_year = get_days_per_year($date_start, $date_end) * 24 * 60 * 60;


    $age = array();


    $age['years_exact'] = $t_lived / $seconds_one_year;


    $age['years'] = floor($t_lived / $seconds_one_year);


    $seconds_remaining = $t_lived % $seconds_one_year;


    $age['days'] = round($seconds_remaining / (24 * 60 * 60));


    return $age;


}


function get_timestamp($date) {


    list($y, $m, $d) = explode('-', $date);


    return mktime(0, 0, 0, $m, $d, $y);


}


function get_days_per_year($date_start, $date_end) {


    list($y1) = explode('-', $date_start);


    list($y2) = explode('-', $date_end);


    $years_days = array();


    for($y = $y1; $y <= $y2; $y++) {


        $years_days[] = date('L', mktime(0, 0, 0, 1, 1, $y)) ? 366 : 365;


    }


    return round(array_sum($years_days) / count($years_days), 2);


}





$date_birth = '1979-10-12';


$date_now = date('Y-m-d');





$age = get_age($date_birth, $date_now);


echo '<pre>';


print_r($age);


echo '</pre>';


?>








It will display something like this:


Array


(


    [years_exact] => 28.972974329491


    [years] => 28


    [days] => 355


)

ooogla at hotmail dot com 01-Sep-2008 03:56


If you want to increment the day based on a variable when using a loop you can use this when you submit a form



1. Establish a start date and end date in two different variables



2. Get the number of days between a date



$ndays = (strtotime($_POST['edate']) - strtotime($_POST['sdate'])) / (60 * 60 * 24);



Then here is the string you slip in your loop



$nextday  = date('Y-m-d', mktime(0, 0, 0, date("m", strtotime($_POST['sdate']))  , date("d", strtotime($_POST['sdate']))+ $count, date("Y", strtotime($_POST['sdate']))));



$count is incremented by the loop.

thomas_corthals at hotmail dot com 13-May-2008 07:34


It seems mktime() doesn't return negative timestamps on Linux systems with a version of glibc <= 2.3.3.

joseph dot andrew dot hughes at gmail dot com 30-Jan-2008 12:58


Just a small thing to think about if you are only trying to pull the month out using mktime and date.  Make sure you place a 1 into day field.  Otherwise you will get incorrect dates when a month is followed by a month with less days when the day of the current month is higher then the max day of the month you are trying to find.. (Such as today being Jan 30th and trying to find the month Feb.)

PHPcoder at freemail dot ig3 dot net 06-Sep-2007 10:58


The maximum possible date accepted by mktime() and gmmktime() is dependent on the current location time zone.



For example, the 32-bit timestamp overflow occurs at 2038-01-19T03:14:08+0000Z.  But if you're in a UTC -0500 time zone (such as EST in North America), the maximum accepted time before overflow (for older PHP versions on Windows) is 2038-01-18T22:14:07-0500Z, regardless of whether you're passing it to mktime() or gmmktime().

Jonathan Woodard 31-Aug-2007 07:31


NB: one 'gotcha' with the implementation of mktime()'s parameters:



<?php

for( $i = 1 ;  $i <= 12 ; $i++ )

{

    echo "Month '$i' is: " . date( "F" , mktime( 0 , 0 , 0 , $i ) ) . "\n";

}

?>

Will output:

Month '1' is: January

Month '2' is: March

Month '3' is: March

Month '4' is: May

Month '5' is: May

Month '6' is: July

Month '7' is: July

Month '8' is: August

Month '9' is: October

Month '10' is: October

Month '11' is: December

Month '12' is: December

on the 31st day of every month.



Why? Because the 5th parameter "day" defaults to "right now," which will not work reliably for days after the 28th.



To make sure this doesn't happen, specify the first day of the month:

<?php

mktime( 0 , 0 , 0 , $i , 1 )

?>

rlz 16-Jul-2007 09:52


Finding out the number of days in a given month and year, accounting for leap years when February has more than 28 days.





<?php


function days_in_month($year, $month) {


    return( date( "t", mktime( 0, 0, 0, $month, 1, $year) ) );


}


?>





Hope it helps a soul out there.

mike at mike-griffiths dot co dot uk 11-Jul-2007 06:04


It may be useful to note that no E_WARNINGS or E_NOTICES are give if you specify a date <1901 or >2038 on systems where time_t is a 32bit signed integer.



If a date is specified outside of the allowed range you may get some unexpected results as no timestamp will be returned.

rga at merchantpal dot com 31-Mar-2007 08:46


You cannot simply subtract or add month VARs using mktime to obtain previous or next months as suggested in previous user comments (at least not with a DD > 28 anyway).



If the date is 03-31-2007, the following yeilds March as a previous month. Not what you wanted.



<?php

$dateMinusOneMonth = mktime(0, 0, 0, (3-1), 31,  2007 );

$lastmonth = date("n | F", $dateMinusOneMonth);

echo $lastmonth;    //---> 3 | March

?>



mktime correctly gives you back the 3rd of March if you subtract 1 month from March 31 (there are only 28 days in Feb 07).



If you are just looking to do month and year arithmetic using mktime, you can use general days like 1 or 28 to do stuff like this:



<?php

$d_daysinmonth = date('t', mktime(0,0,0,$myMonth,1,$myYear));     // how many days in month

$d_year = date('Y', mktime(0,0,0,$myMonth,1,$myYear));        // year

$d_isleapyear = date('L', mktime(0,0,0,$myMonth,1,$myYear));    // is YYYY a leapyear?



$d_firstdow = date('w', mktime(0,0,0,$myMonth,'1',$myYear));     // FIRST falls on what day of week (0-6)

$d_firstname = date('l', mktime(0,0,0,$myMonth,'1',$myYear));     // FIRST falls on what day of week Full Name



$d_month = date('n', mktime(0,0,0,$myMonth,28,$myYear));         // month of year (1-12)

$d_monthname = date('F', mktime(0,0,0,$myMonth,28,$myYear));         // Month Long name (July)

$d_month_previous = date('n', mktime(0,0,0,($myMonth-1),28,$myYear));         // PREVIOUS month of year (1-12)

$d_monthname_previous = date('F', mktime(0,0,0,($myMonth-1),28,$myYear));     // PREVIOUS Month Long name (July)

$d_month_next = date('n', mktime(0,0,0,($myMonth+1),28,$myYear));         // NEXT month of year (1-12)

$d_monthname_next = date('F', mktime(0,0,0,($myMonth+1),28,$myYear));         // NEXT Month Long name (July)

$d_year_previous = date('Y', mktime(0,0,0,$myMonth,28,($myYear-1)));        // PREVIOUS year

$d_year_next = date('Y', mktime(0,0,0,$myMonth,28,($myYear+1)));        // NEXT year



$d_weeksleft = (52 - $d_weekofyear);                     // how many weeks left in year

$d_daysinyear = $d_isleapyear ? 366 : 365;                // set correct days in year for leap years

$d_daysleft = ($d_daysinyear - $d_dayofyear);                // how many days left in year

?>

Stephen 08-Jan-2007 02:43


There are several warnings here about using mktime() to determine a date difference because of daylight savings time. However, nobody seems to have mentioned the other obvious problem, which is leap years.





Leap years mean that any effort to use mktime() and time() to determine the age (positive or negative) of some timestamp in years will be flawed. There are some years that are 366 days long, therefore you cannot say that there is a set number of seconds per year.





Timestamps are good for determining *real* time, which is not the same thing as *human calendar* time. The Gregorian calendar is only an approximation of real time, which is tweaked with daylight savings time and leap years to make it conform more to humans' expectations of how time should or ought to work. Timestamps are not tweaked and therefore are the only authoritative way of recording in computers a proper order of succession of events, but they cannot be integrated with a Gregorian system unless you take both leap years and DST into account. Otherwise, you may get the wrong number of years when you are approaching a value of exactly X years.





As for PHP, you could still use timestamps as a way of determining age if you took into account not only DST but also whether or not each year is a leap year and adjusted your calculations accordingly. However, this could become messy and inefficient. 





There is an alternative approach to calculating days given the day, month and year of the dates to be compared. Compare the years first, and then compare the month and day - if the month and day have already passed (or, if you like, if they match the current month and day), then add 1 to the total for the years. 





This solution works because it stays within the Gregorian system and doesn't venture into the world of timestamps.





There is also the issue of leap seconds, but this will only arise if you literally need to get the *exact* age in seconds. In that case, of course, you would also need to verify that your timestamps are exactly correct and are not delayed by script processing time, plus you would need to determine whether your system conforms to UTC, etc. I expect this will hardly be an issue for anybody using PHP, however if you are interested there is an article on this issue on Wikipedia:





http://en.wikipedia.org/wiki/Leap_second

jsebfranck 07-Nov-2006 04:42


There are several notes for mktime which use the number 86400 to differentiate two days. However this technique may pose a problem in case there is a day where the hour change between the two dates to compare.



Consequently, if you want the timestamp difference between the day where the hour change and the next day, it will not be equals to 86400 but either 82800 in case its the winter change of hour day or 90000 for the summer change of hour day.



For example in 2006 :



<?php

echo mktime(0,0,0,10,29,2006) - mktime(0,0,0,10,30,2006); // -90 000

?>

carlo dot tafuro at poste dot it 08-May-2006 04:40


Negative timestamps give problem also using linux as guest operating system inside WMvare with Windows host operating system.

colin dot horne at gmail dot com 30-Mar-2005 10:48


If the month is greater than 12, it goes into the next year. If it is less than 1, it goes into the previous year. Generally, it behaves as you'd expect it to :-)



Examples:



<?php



// January 1, 2005

print date ("F j, Y", mktime (0,0,0,13,1,2004));



// December 1, 2003

print date ("F j, Y", mktime (0,0,0,0,1,2004));



// February 1, 2005

print date ("F j, Y", mktime (0,0,0,14,1,2004));



// November 1, 2003

print date ("F j, Y", mktime (0,0,0,-1,1,2004));



?>

Romain Sam 25-Mar-2005 07:50


Under Windows, mktime goes until 2038-01-19 (03:14:07 ...)

praas at NOSPAM dot ision dot nl 01-Feb-2004 12:44


Consider skipping months with mktime().



$nextmonth = date("M",mktime(0,0,0,date("n")+1,date("j"),date("Y")));



On any day in Januari you expect to get Feb, right? 

But on January 30th you'll get Mar. It will try Feb 30th, which doesn't exist, and skips another month. Therefore in this case present a day value that will certainly be legal in any month, like day "1".



This will give you next month on any day of the year:

$nextmonth = date("M",mktime(0,0,0,date("n")+1,1,date("Y")));

iain at seatofthepants dot net 08-Dec-2003 07:49


In the above example it should ne boted that if you try to calculate the command at midnight on the 28/04/2004 you will get an erroneous response. This has been driving me to distraction.



$myTime = mktime( 0, 0, 0, 3, 28, 2004);



Solution I found was to create the time at 3am well after the 2am daylight savings problem, viz:



$myTime = mktime( 3, 0, 0, 3, 28, 2004);



Not sure if this is documented anywhere.

trahma 20-Nov-2003 12:06


I think it is important to note that the timestamp returned is based upon the number of seconds from the epoch GMT, and then modified by the time zone settings on the server.



Thus...



mktime(0,0,0,1,1,1970) will not always return 0.  For example with the US eastern time zone (GMT-5) will return 18000 (5 hours past the epoch) and the same function with the time zone set to the US pacific time zone (GMT-8) will return 28800 (8 hours past the epoch).



In an instance where you want time zone independence, you should use the function gmmktime()

laurie at oneuponedown dot com 18-Nov-2003 08:42


With regard to Example 1 and using mktime to correct out-of-range input.





It should be noted that mktime will implement day light saving amends. Consider the following:





<?php


print(date("d/m/Y H:i:s",mktime(0,0,0,3,(27 + 1),2004)));


?>


OUTPUT "28/03/2004 02:00:00"





<?php


print(date("d/m/Y H:i:s",(mktime(0,0,0,3,27,2004) + (((1 * 24) * 60) * 60))));


?>


OUTPUT "28/03/2004 00:00:00"





Dependent on your requirements this may or may be desirable

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