chdir

(PHP 4, PHP 5)

chdir — 改变目录

说明

bool chdir ( string $directory )

将 PHP 的当前目录改为 directory。

参数

directory: 新的当前目录

返回值

成功时返回 TRUE，或者在失败时返回 FALSE.

错误/异常

Throws an error of level E_WARNING on failure.

范例

Example #1 chdir() 例子


<?php

// current directory
echo getcwd() . "\n";

chdir('public_html');

// current directory
echo getcwd() . "\n";

?>

以上例程的输出类似于：

/home/vincent
/home/vincent/public_html

注释

Note: 当启用安全模式时， PHP 会在执行脚本时检查被脚本操作的目录是否与被执行的脚本有相同的 UID（所有者）。

参见

chroot

Directory 函数

[edit] Last updated: Fri, 25 May 2012

add a note User Contributed Notes chdir

php dot duke at qik dot nl 31-Jan-2009 02:16


When changing dir's under windows environments:





<?php


$path="c:\temp"';


chdir($path);


/* getcwd() gives you back "c:\temp" */





$path="c:\temp\"';


chdir($path);


/* getcwd() gives you back "c:\temp\" */


?>





to work around this inconsistency


doing a chdir('.') after the chdir always gives back "c:\temp"

andy dot clark at dial dot pipex dot com 21-Aug-2006 08:10


This only changes the directory for PHP, the output directory stays the same. If you are trying to access images from a relative path and you use the following then it will fail to render the image:



chdir ('images');

if (file_exists('php.gif')) 

{

echo '<html>';

echo '<body>';

echo '<img src="php.gif">';

echo '</body></html>';

}



//However, it is possible to use the <base> tag in the header to change the directory for the resulting HTML, as you can see however this requires you to put the full path in place.



chdir ('images');

if (file_exists('php.gif')) 

{

echo '<html>';

echo '<head><base href = "http://uk.php.net/images/"></head>';

echo '<body>';

echo '<img src="php.gif">';

echo '</body></html>';

}

herwin at snt dot utwente dot nl 17-Aug-2006 11:58


When using PHP safe mode and trying to change to a dir that is not accessible due to the safe mode restrictions, the function simply fails without generating any kind of error message.



(Tested in PHP 4.3.10-16, Debian Sarge default)

jeprubio _At_ gmail dot com 27-May-2005 12:25


If you run this script when $sym_dir is a symbolic link to a directory:

  echo getcwd()."\n";

  chdir ($sym_dir);

  chdir ('../');

  echo getcwd()."\n";



It returns for example:

  /dades/loc/real/mapes/navteq/anloc

  /mapes/anloc



It will not return to the previous directory, it returns to the parent of the real directory where it links the symbolic link.



It's not necessary a bug but I think it's important to have present this.



It could be solved saving the current directory and then returning to it. For example:

  $cwd = getcwd();

  echo getcwd()."\n";

  chdir ($sym_dir);

  chdir ($cwd);

  echo getcwd()."\n";



It returns:

  /dades/loc/real/mapes/navteq/anloc

  /dades/loc/real/mapes/navteq/anloc



Have fun :)

-------

   Josep Rubio (Anloc S.L. www.anloc.net)

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