sqlite_num_rows

SQLiteResult::numRows

(PHP 5 < 5.4.0, PECL sqlite >= 1.0.0)

sqlite_num_rows -- SQLiteResult::numRowsReturns the number of rows in a buffered result set

Description

sqlite_num_rows ( resource $result ) : int

Object oriented style (method):

SQLiteResult::numRows ( void ) : int

Returns the number of rows in the buffered result set.

Parameters

result

The SQLite result resource. This parameter is not required when using the object-oriented method.

Note:

This function cannot be used with unbuffered result handles.

Return Values

Returns the number of rows, as an integer.

Examples

Example #1 Procedural example

<?php
$db 
sqlite_open('mysqlitedb');
$result sqlite_query($db"SELECT * FROM mytable WHERE name='John Doe'");
$rows sqlite_num_rows($result);

echo 
"Number of rows: $rows";
?>

Example #2 Object-oriented example

<?php
$db 
= new SQLiteDatabase('mysqlitedb');
$result $db->query("SELECT * FROM mytable WHERE name='John Doe'");
$rows $result->numRows();

echo 
"Number of rows: $rows";
?>

See Also

  • sqlite_changes() - Returns the number of rows that were changed by the most recent SQL statement
  • sqlite_query() - Executes a query against a given database and returns a result handle
  • sqlite_num_fields() - Returns the number of fields in a result set

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User Contributed Notes 3 notes

up
0
Dylan
2 months ago
//I don't know about you. But for me this is what I had to do

$db = new SQLite3('databasename.db');
$result = $db->query("SELECT * FROM table_name");
$number_of_rows = 0;//for now

while($row = $result->fetchArray()) {
    $number_of_rows += 1;
}

echo "Number of rows: $number_of_rows";
up
-1
be {a} t {dawt} pl
3 years ago
@rezaamya

$db = new SQLite3('databasename.db');
$result = $db->query("SELECT * FROM users");
$rows = count ($result);
echo "Number of rows: $rows";

$rows value should always be 1
... even if the query is invalid
I tested that on
SQLite Library 3.7.7.1
up
-10
rezaamya at gmail dot com
5 years ago
neither of "sqlite_num_rows($result)" and "$result->numRows()" is not working on SQLite3 !
you should use this way:

$db = new SQLite3('databasename.db');
$result = $db->query("SELECT * FROM users");
$rows = count ($result);
echo "Number of rows: $rows";
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