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func_num_args> <func_get_arg
Last updated: Fri, 11 Apr 2008

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func_get_args

(PHP 4, PHP 5)

func_get_args — Liefert Funktionsargumente als Array

Beschreibung

array func_get_args ( void )

Liefert die der aufrufenden Funktion übergebenen Argumente als Array.

Die Funktion kann zusammen mit func_get_arg() und func_get_args() genutzt werden um Funktionen mit einer variablen Anzahl von Argumenten zu implementieren.

Rückgabewerte

Liefert ein Array mit Kopien aller Argumente mit denen die aufrufende Funktion aufgerufen wurde.

Fehler/Exceptions

Die Funktion generiert eine Warnung wenn sie außerhalb einer benutzerdefinierten Funktion aufgerufen wird.

Beispiele

Beispiel #1 func_get_args() Beispiel

<?php
function foo()
{
    
$numargs func_num_args();
    echo 
"Anzahl der Argumente: $numargs<br />\n";
    if (
$numargs >= 2) {
        echo 
"Das zweite Argument ist: " func_get_arg(1) . "<br />\n";
    }
    
$arg_list func_get_args();
    for (
$i 0$i $numargs$i++) {
        echo 
"Argument $i ist: " $arg_list[$i] . "<br />\n";
    }
}

foo(123);
?>

Anmerkungen

Hinweis: Da diese Funktion bei der Ermittlung der Parameterdetails von dem aktuellen Ausführungskontext abhängt kann sie selbst nicht als Funktionsparameter genutzt werden. Wenn Sie ihre Ergebnisse tatsächlich weitergeben müssen so müssen Sie diese zunächst an eine Variable zuweisen und dann diese Variable übergeben

Hinweis: This function returns a copy of the passed arguments only, and does not account for default (non-passed) arguments.



func_num_args> <func_get_arg
Last updated: Fri, 11 Apr 2008
 
add a note add a note User Contributed Notes
func_get_args
Anonymous
28-Jan-2008 08:11
I use the following concept for quick "plugin" of multiple argument support.

<?php

function increment($n) {
 
$p = func_get_args();
  if (
count($p) > 1) {
    return
array_map(__FUNCTION__, $p);
  }
 
$n =& $p[0];
 
  return ++
$n;
}

list(
$two, $three, $four) = increment(1,2,3);

?>
tristan dot colombo at laposte dot net
18-Oct-2007 01:03
In order to use the function 'func_get_args()' to instanciate differents type of objects, you must use the Reflection API.
By example, we have two different classes and we want to have an unique function (using an unfixed number of parameters) to create the objects. We create two classes 'a' and 'b' where constructors accept different numbers of arguments.
Class a (class/a.class.php):
<?php
 
include_once 'a.class.php';

  class
b extends a
 
{
    private
$param3;

    public function
__construct($a, $b, $c)
    {
     
$this->param1 = $a;
     
$this->param2 = $b;
     
$this->param3 = $c;
    }

    public function
display()
    {
      echo
$this->param1 . ', ' . $this->param2 . ' and ' . $this->param3 . '!<br />';
    }
  }
?>

Class b (class/b.class.php):
<?php

 
class a
 
{
    private
$param1;
    private
$param2;

    public function
__construct($a, $b)
    {
     
$this->param1 = $a;
     
$this->param2 = $b;
    }

    public function
display()
    {
      echo
$this->param1 . ' and ' . $this->param2 . '<br />';
    }
  }
?>

Main program :
<?php

 
function classFactory()
  {
   
// Retrieve arguments list
   
$_args = func_get_args();
   
// Delete the first argument which is the class name
   
$_className = array_shift($_args);

   
// Include the requested class
   
include_once 'class/' . $_className . '.class.php';

   
// Create Reflection object
    // See : http://www.php.net/manual/en/language.oop5.reflection.php
   
$_reflection = new ReflectionClass($_className);

   
// Use the Reflection API
   
return $_reflection->newInstanceArgs($_args);
  }

 
$a = classFactory('a', 'hello', 'world');
 
$b = classFactory('b', 'that\'s', 'all', 'folks');

 
$a->display();
 
$b->display();

?>
gerry+phpnet at buzka dot com
19-Sep-2007 07:40
If you were having trouble understanding the func_get_default_args() function below, this example should make things more clear. The author of the function could have written it like func_get_expected_default_args() but that doesn't account for args which were passed but not specified in the param list.

example:

<?php
   
function func_get_expected_default_args($a) {
       
// Grab the list of expected arguments.
       
return func_get_args();
    }

    function
func_get_default_args($a) {
       
// Grab the list of expected arguments.
       
$args = array_slice(func_get_args(), 1);

       
// Append any unexpected agruments that may have been also passed
        // to the function, but were not in the param list.
       
return array_merge($args, array_slice($a, count($args)));
    }

    function
foo($bar=5, $foobar=3){
       
$args = func_get_expected_default_args2($bar, $foobar);
        echo
'expected args: '. print_r($args, true);

       
$args = func_get_default_args(func_get_args(), $bar, $foobar);
        echo
'all args: '. print_r($args, true);
    }
   
   
foo(20);

   
foo(20, 95, 'unexpected', 'variables');

   
/*
        Output:

        expected args: Array
        (
            [0] => 20
            [1] => 3
        )
        all args: Array
        (
            [0] => 20
            [1] => 3
        )
        expected args: Array
        (
            [0] => 20
            [1] => 95
        )
        all args: Array
        (
            [0] => 20
            [1] => 95
            [2] => unexpected
            [3] => variables
        )
    */
?>
Sinured
20-Aug-2007 05:38
It may seem obvious, but if you want your variadic function to at least require one parameter, you can do this instead of checking func_num_args() == 0, which I've seen often:

<?php
function variadic($dummy) {
   
$args = func_get_args();
    foreach (
$args as $arg) {
        echo
"$arg<br />\n";
    }
}
?>

func_get_args() fetches ALL passed parameters, not only those that weren't copied to a local variable.
ario [a] mail [dot] utexas [dot] edu
07-May-2007 02:50
"Because this function depends on the current scope to determine parameter details, it cannot be used as a function parameter. If you must pass this value, assign the results to a variable, and pass the variable."

This means that the following code generates an error:

<?php

function foo($list)
{
  echo
implode(', ', $list);
}

function
foo2()
{
 
foo(func_get_args());
}

foo2(1, 2, 3);

?>

However, you can easily get around this by doing the following:

<?php

function foo($list)
{
  echo
implode(', ', $list);
}

function
foo2()
{
 
foo($args = func_get_args());
}

foo2(1, 2, 3);

?>

This captures the context from foo2(), making this legal.  You get the expected output:

"1, 2, 3"
jmcguire81 [at] gmail.com
21-Mar-2007 03:13
Here is another variation on accepting a variable number of arguments. This allows for a variable number of arguments to be passed to a Class constructor, as well as a customized class version to be used dynamically. Syntax in code is:

$mail = Generator("MailClassName", $db_ref);

function Generator() {

   $numargs = func_num_args();

   $classname = func_get_arg(0);
   $argstring='';
   if ($numargs > 1) {
      $arg_list = func_get_args();

      for ($x=1; $x<$numargs; $x++) {
         $argstring .= '$arg_list['.$x.']';
         if ($x != $numargs-1) $argstring .= ',';
      }
   }

   if (class_exists("Custom{$classname}")) {
      $classname = "Custom{$classname}";
      if ($argstring) return eval("return new $classname($argstring);");
      return new $classname;
   }
  
   if ($argstring) return eval("return new $classname($argstring);");
   return new $classname;
}

Hope this is of use to someone.
rafagd at gmail dot com
13-Feb-2007 08:53
Sometimes, you may need to dynamic set and get of args...

This function merge array args, so you can dynamic set some args by sending an array arg.

<?
  function dynamicArgs(/*$arg1, $arg2...$argN*/) {
    $args = func_get_args(); $num  = func_num_args();
    for ($i = 1; $i < $num; $i++) {
      $args[0] = array_merge((array) $args[0], (array) $args[$i]);
    }
    return $args[0];
  }
 
  var_dump(dynamicArgs('a',array('b','c'),'d',1);
?>

This should output like:

array(5) {
  [0]=>
  string(1) "a"
  [1]=>
  string(1) "b"
  [2]=>
  string(1) "c"
  [3]=>
  string(1) "d"
  [4]=>
  int(1)
}
31-Oct-2006 10:26
Same idea as below, but this:

       foreach( $args as $k => $v ){
           switch($k){
               case 'a':
                   $this->a= $v; break;
               case 'b':
                   $this->b= $v; break;
               case 'c':
                   $this->c= $v; break;
             }
       }

can be shortened to this (as long as all public variables have default values set in their declarations):

       foreach( $args as $k=>$v)
            if(isset($this->$k)) $this->$k = $v;
kidekat
01-Oct-2006 06:02
To pass named arguments in a Perl fashion through class constructors, I use this:

<?php
class Test{

   
// set class defaults for values not assigned by constructor
   
public $a = 0;
    public
$b = 'string';
    public
$c = array();

    public function
__construct( $args = array() ) {

       
// parse tagged arguments in Perl fashion
       
foreach( $args as $k => $v ){
            switch(
$k){
                case
'a':
                   
$this->a= $v; break;
                case
'b':
                   
$this->b= $v; break;
                case
'c':
                   
$this->c= $v; break;
             }
        }
    }

}

$t = new Test(  array( 'b'=>'new value', 'c'=>array(1,'test') ) );
?>

This allows $a to keep its default of 0, while $b gets reassigned to 'new value' and $c becomes the array(1,'test'). The catch is that you add O(n^2) "big-O notation" to the begging of every class constructor which becomes expensive on "larger" classes. While arguments defaults like the following have only O(n) "constant" amount of work.

<?php
   
public funciton __construct( $a=0, $b='string', $c=array()){ ... }
?>
bew
31-Mar-2006 07:55
A more concise way of expressing my idea from the previous post (I'd forgotten about array_slice()):

<?php
function func_get_default_args($a) {
   
$args = array_slice(func_get_args(), 1);
    return
array_merge($args, array_slice($a, sizeof($args)));
}

function
foo($a = 1, $b = 2, $c = 3) {
   
print_r(func_get_default_args(func_get_args(), $a, $b, $c));
}

// prints: Array ( [0] => a [1] => b [2] => 3 )
foo('a', 'b');
?>
Nathan Ostgard
06-Dec-2005 10:14
If you're using PHP5, the variable number of argument functions all return the objects by reference - and not a copy of the object, as this leads you to believe.
robert at defore dot st
15-Feb-2005 12:47
# Another attempt at named args (perl-inspired):

# list_to_assoc('key', 'value', 'key', 'value', ...) =>
#     pairs[]
function list_to_assoc() {
    $list = func_get_args();
    $assoc = array();

    while ($list and count($list) > 1) {
        $assoc[array_shift($list)] = array_shift($list);
    }

    if ($list) { $assoc[] = $list[0]; }

    return $assoc;
}

# Usage:

function example($required) {
    $args = func_get_args(); array_shift($args); # drop 'required'
    $rest = list_to_assoc($args);
    echo "$required\n" . $rest['comment'];
}

example("This is required...",
        'comment', 'this is not.'); # this is like 'comment' => 'this is not'
T.M.
04-Nov-2004 07:24
Simple function to calculate average value using dynamic arguments:
<?php
function average(){
    return
array_sum(func_get_args())/func_num_args();
}
print
average(10, 15, 20, 25); // 17.5
?>
volte6 at drunkduck dot com
30-Sep-2004 02:54
For those who have a use for a C style enum() function:

//*******************************************
// void enum();
// enumerates constants for unique values guarenteed.
function enum()
{
  $i=0;
  $ARG_ARR = func_get_args();
  if (is_array($ARG_ARR))
  {
    foreach ($ARG_ARR as $CONSTANT)
    {
      define ($CONSTANT, ++$i);
    }
  }
}

// USAGE:
enum(ERR_USER_EXISTS, ERR_OLD_POST);

// etc. etc.
//*******************************************

this can be used for error codes etc.
I deliberately skipped the 0 (zero) define, which could be useful for error checking.
mark at manngo dot net
23-Mar-2003 11:13
You can also fake named arguments using eval:

function test()
{   foreach (func_get_args() as $k=>$arg) eval ("\$$arg;");
    echo "$a plus $b gives ".($a+$b);
}

test("a=3","b=4");
daveNO at ovumSPAMdesign dot com
17-Sep-2001 11:29
<?php
// How to simulate named parameters in PHP.
// By Dave Benjamin <dave@ovumdesign.com>

// Turns the array returned by func_get_args() into an array of name/value
// pairs that can be processed by extract().
function varargs($args) {
   
$count = count($args);
    for (
$i = 0; $i < $count; $i += 2) {
       
$result[$args[$i]] = $args[$i + 1];
    }
   
    return
$result;
}

// Example
function test(&$ref1, &$ref2) {
   
// Default arguments go here.
   
$foo = "oof";
   
   
// Do some magic.
   
extract(varargs(func_get_args()));

    echo
nl2br("\n\$var1 = $var1");
    echo
nl2br("\n\$var2 = $var2");
    echo
nl2br("\n\$foo = $foo\n\n");
   
   
// Modify some variables that were passed by reference.
    // Note that func_get_args() doesn't pass references, so they
    // need to be explicitly declared in the function definition.
   
$ref1 = 42;
   
$ref2 = 84;
}

$a = 5;
$b = 6;

echo
nl2br("Before calling test(): \$a = $a\n");
echo
nl2br("Before calling test(): \$b = $b\n");

// Try removing the 'foo, "bar"' from the following line.
test($a, $b, var1, "abc", var2, "def", foo, "bar");

echo
nl2br("After calling test(): \$a = $a\n");
echo
nl2br("After calling test(): \$b = $b\n");
?>
04-Jun-2001 07:44
You can pass a variable number of arguments to a function whilst keeping references intact by using an array. The disadvantage of course, is that the called function needs to be aware that it's arguments are in an array.
<?
// Prints "hello mutated world"
function mutator($args=null) {
$n=count($args);
while($i<$n) $args[$i++] = "mutated";
}
$a = "hello";
$b = "strange";
$c = "world";
mutator(array($a, &$b, $c));
echo "$a $b $c";
?>

func_num_args> <func_get_arg
Last updated: Fri, 11 Apr 2008
 
 
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