JDDayOfWeek

(PHP 4, PHP 5)

JDDayOfWeek — Returns the day of the week

Description

mixed jddayofweek ( int $julianday [, int $mode = CAL_DOW_DAYNO ] )

Returns the day of the week. Can return a string or an integer depending on the mode.

Parameters

julianday

A julian day number as integer

mode

**Calendar week modes**
Mode	Meaning
0 (Default)	Return the day number as an int (0=Sunday, 1=Monday, etc)
1	Returns string containing the day of week (English-Gregorian)
2	Return a string containing the abbreviated day of week (English-Gregorian)

Return Values

The gregorian weekday as either an integer or string.

add a note User Contributed Notes JDDayOfWeek - [2 notes]

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php at xtramicro dot com ¶

8 years ago


Be aware that date() and mktime() only work as long as you move within the UNIX era (1970 - 2038 / 0x0 - 0x7FFFFFFF in seconds). Outside that era those functions are only generating errors.





In other words: mktime(0, 0, 0, 12, 31, 1969) *DOES NOT* work (and so doesn't date() fed with with mktime()'s result from above). But cal_to_jd(CAL_GREGORIAN, 12, 11, 1969) *DOES WORK*.





And please note that the calendar-extension's functions arguments follow the US date order: month - day - year.

down

nrkkalyan at rediffmail dot com ¶

8 years ago


You can get todays day time and date using this code





<?php


echo date("d")." "; 


echo date("m")." ";


echo date("Y")." ";


echo date("h:i:s A");





ECHO ' <br/>';


echo jddayofweek ( cal_to_jd(CAL_GREGORIAN, date("m"),date("d"), date("Y")) , 1 );


?>

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