session_start
The advice of ive_insomnia at live dot com should be taken with great care.
First of all, while his use case for session_status is valid, a simpler way to avoid the warning is:
<?php
if (!isset($_SESSION)) { session_start(); }
?>
The example of session_status uses the raw values of constants (2 in this case) created specifically for the purpose of not having to use magic numbers.
Better code would be:
<?php
if (session_status() !== PHP_SESSION_ACTIVE) {session_start();}
?>
The same can be done using
<?
if (session_id() === "") { session_start(); }
?>
The use of this function is lies more towards status management: change the behavior of a script when sessions are disabled altogether, for example.
session_status
(PHP >=5.4.0)
session_status — Returns the current session status
Description
int session_status
( void
)
session_status() is used to return the current session status.
Return Values
-
PHP_SESSION_DISABLEDif sessions are disabled. -
PHP_SESSION_NONEif sessions are enabled, but none exists. -
PHP_SESSION_ACTIVEif sessions are enabled, and one exists.
See Also
- session_start() - Start new or resume existing session
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User Contributed Notes
session_status - [3 notes]
php at pointpro dot nl ¶
2 months ago
ive_insomnia at live dot com ¶
4 months ago
simple session_start() request to avoid warning:
<?php
if (!$_SESSION) {session_start();}
// your code
?>
Or similar code works, but give a warning.
<?php
if(session_status() != 2) {session_start();}
// your code
?>
This option work fine without warning.
0 = PHP_SESSION_DISABLED
1 = PHP_SESSION_NONE
2 = PHP_SESSION_ACTIVE
adrian ¶
7 days ago
>The use of this function is lies more towards status management: change the behavior of a script when sessions are disabled altogether, for example.
On that note:
<?php
if( session_status() === PHP_SESSION_NONE ){ session_start(); }
?>
This way, you won't try to start a session if a) a session already exists, or b) sessions are disabled.