downloads | documentation | faq | getting help | mailing lists | licenses | wiki | reporting bugs | php.net sites | links | conferences | my php.net

search for in the

imagechar> <imageantialias
[edit] Last updated: Fri, 25 May 2012

view this page in

imagearc

(PHP 4, PHP 5)

imagearcDibujar un arco

Descripción

bool imagearc ( resource $image , int $cx , int $cy , int $width , int $height , int $start , int $end , int $color )

imagearc() dibuja un arco de circunferencia con centro en las coordenadas dadas.

Parámetros

image

Un recurso image, es devuelto por una de las funciones de creación de imágenes, como imagecreatetruecolor().

cx

Coordenada x del centro.

cy

Coordenada y del centro

width

El ancho del arco.

height

El alto del arco.

start

El ángulo de inicio del arco, en grados.

end

El ángulo de finalización del arco, en grados. 0° está localizado en la posición que marca la aguja horaria a las tres en punto, y el arco se dibuja en el sentido de las agujas del reloj.

color

Un identificador de color creado con imagecolorallocate().

Valores devueltos

Devuelve TRUE en caso de éxito o FALSE en caso de error.

Ejemplos

Ejemplo #1 Dibujar un círculo con imagearc()

<?php

// crear una imagen de 200*200
$img imagecreatetruecolor(200200);

// asignar algunos colores
$blanco imagecolorallocate($img255255255);
$rojo   imagecolorallocate($img255,   0,   0);
$verde imagecolorallocate($img,   0255,   0);
$azul  imagecolorallocate($img,   0,   0255);

// dibujar la cabeza
imagearc($img100100200200,  0360$blanco);
// la boca
imagearc($img10010015015025155$rojo);
// el ojo izquierdo y después el ojo derecho
imagearc($img,  60,  75,  50,  50,  0360$verde);
imagearc($img140,  75,  50,  50,  0360$azul);

// imprimir la imagen en el navegador
header("Content-type: image/png");
imagepng($img);

// liberar memoria
imagedestroy($img);

?>

El resultado del ejemplo sería algo similar a:

Salida del ejemplo : Dibujar un círculo con imagearc()

Ver también



imagechar> <imageantialias
[edit] Last updated: Fri, 25 May 2012
 
add a note add a note User Contributed Notes imagearc
chandlerklebs at gmail dot com 07-Jan-2012 10:24
This is an example script I wrote for myself to help me learn how to used the imagearc functions. Maybe if will also help others.

<?php
//example PHP script of imagearc functions
$image_width=360;$image_height=360;
$img = imagecreatetruecolor($image_width,$image_height); //make image variable

//create a background color by making a filled rectangle
$color = imagecolorallocate($img,255,255,255);
imagefilledrectangle($img,0,0,$image_width,$image_height,$color);

$r=$image_width/2 - $image_width/32 ; //radius
$cx=$image_width/2;
$cy=$image_height/2;

$color = imagecolorallocate($img,0,0,0);
imagearc($img, $cx, $cy, $r*2, $r*20, 360, $color); //regular outlines arc

imagefilledarc($img, $cx, $cy, $r*1, $r*10, 90, $color,IMG_ARC_CHORD); //filled triangle with chord of circle
imagefilledarc($img, $cx, $cy, $r*1, $r*1180, 270, $color,IMG_ARC_PIE); //pie slice

$font_number=5; //can use built in fonts numbered 1 to 5
$string="Hello world!";
imagestring($img, $font_number, $cx-(imagefontwidth($font_number)*strlen($string))/2, $cy-120, $string, $color);

header("Content-type: image/png");
imagepng($img);// output image in the browser

$filename="imagearc";
imagepng($img,"./frames/$filename.png",9); //make highly compressed png

imagedestroy($img);
?>
Michael 04-Mar-2011 02:56
Hi, this is a function that replaces "imagearc" to solve the thickness-problem. it does not use the global value set by imagesetthickness, so you have to pass it along.

"connecting" the arc to lines is still a problem, it sometimes shifts by 1px, but so does the original function.

Theres still alot to improve ...

<?php
function myimagearc($im,$mid_x,$mid_y,$rad,$w1,$w2,$col,$thickness){
        global
$cols;
       
$rad+=$thickness/2;    // to calculate outer edge
       
$th_fact = 1-((($thickness-1)/$rad));       
       
       
$pts = 36*$rad;    // adjust density
       
$fact = $pts/360;
       
$w1 = $w1*$fact;
       
$w2 = $w2*$fact;
        if(
$thickness > 2)    // to make sure we have neither gaps nor ugly looking artefacts
           
imagesetthickness($handle,2);
        else
           
imagesetthickness($handle,1);   
       
$winkel = (2*pi())/$pts;
        for(
$i=$w1+1;$i< $w2;$i++){
           
$x = (cos($i*$winkel)*($rad));
           
$y = (sin($i*$winkel)*($rad));
           
$x1 = $x+$mid_x;
           
$y1 = $y+$mid_y;
           
$x2 = $th_fact*$x+$mid_x;
           
$y2 = $th_fact*$y+$mid_y;
           
imageline($im, $x1,$y1,$x2,$y2,$col);
        }
       
imagesetthickness($handle,1); // just to reset
   
}
?>
ajim1417 at gmail dot com 28-Jan-2010 07:42
I wrote a simple function that can draws an arc counter-clockwisekly. Here it is :

<?php

function imagearcCC(&$im, $cx, $cy, $w, $h, $s, $e, $c) {
$start = 360 - $e;
$end = 360 - $s;
return
imagearc($im, $cx, $cy, $w, $h, $start, $end, $c);
}

?>

The params of this function is exactly the same as the usual imagearc function.
anton dot vandeghinste at telenet dot be 13-Dec-2009 07:27
I needed an arc with a thick border and i didn't like to use 359.9 as end angle so i made a function that works pretty well:

<?php
function imagearcthick($image, $x, $y, $w, $h, $s, $e, $color, $thick = 1)
{
    if(
$thick == 1)
    {
        return
imagearc($image, $x, $y, $w, $h, $s, $e, $color);
    }
    for(
$i = 1;$i<($thick+1);$i++)
    {
       
imagearc($image, $x, $y, $w-($i/5), $h-($i/5),$s,$e,$color);
       
imagearc($image, $x, $y, $w+($i/5), $h+($i/5), $s, $e, $color);
    }
}
?>
mojiro at awmn dot net 13-Dec-2005 12:28
A previous for the Rotated (Filled)Ellipse note from(nojer2 at yahoo dot com, 02-Apr-2001 12:06) has a mistake, at the second arc. Replace them with the following listing.

if ($filled) {
    triangle($im, $cx, $cy, $cx+$px, $cy+$py, $cx+$x, $cy+$y, $colour);
    triangle($im, $cx, $cy, $cx-$px, $cy-$py, $cx-$x, $cy-$y, $colour);
} else {
    imageline($im, $cx+$px, $cy+$py, $cx+$x, $cy+$y, $colour);
    imageline($im, $cx-$px, $cy-$py, $cx-$x, $cy-$y, $colour);
}
ruturaj_v at yahoo dot com 17-May-2004 06:32
this is another piechart eg. very simple ...

<?php
global $deg;

function
get_polar($xrel, $yrel, $ang, $radius) {
   
$i = $ang;
   
$ang = ($ang * pi())/ 180;
   
   
$ix = abs($radius*cos($ang));
   
$iy = abs($radius*sin($ang));
   
    if (
$i>=0 && $i<=90) {
       
$ix = $xrel + $ix;
       
$iy = $yrel - $iy;
    }
    if (
$i>90 && $i<=180) {
       
$ix = $xrel - $ix;
       
$iy = $yrel - $iy;
    }
    if (
$i>180 && $i<=270) {
       
$ix = $xrel - $ix;
       
$iy = $yrel + $iy;
    }
    if (
$i>270 && $i<=360) {
       
$ix = $xrel + $ix;
       
$iy = $yrel + $iy;
    }

   
$ix = floor($ix);
   
$iy = floor($iy);
   
//echo ($ix . " $iy<br>");
   
$returnvals = array (
                       
'x1' => $xrel,
                       
'y1' => $yrel,
                       
'x2' => $ix,
                       
'y2' => $iy
                       
);
    return
$returnvals;
}

function
get_degtotal($degindex)
{
    global
$deg;
    if (
$degindex == 0 ) {
       return ( 
$deg[$degindex] );
    }
    else {       
        return (
$deg[$degindex] + get_degtotal($degindex-1) );
    }   
}

$im  = imagecreate (400, 400);
$w   = imagecolorallocate ($im, 255, 255, 255);
$black   = imagecolorallocate ($im, 0, 0, 0);
$red = imagecolorallocate ($im, 255, 0, 0);
$green = imagecolorallocate ($im, 0, 180, 0);

$randcolor[0] = imagecolorallocate($im, 243, 54, 163);
$randcolor[1] = imagecolorallocate($im, 179, 51, 247);
$randcolor[2] = imagecolorallocate($im, 103, 48, 250);
$randcolor[3] = imagecolorallocate($im, 53, 145, 244);
$randcolor[4] = imagecolorallocate($im, 54, 243, 243);
$randcolor[5] = imagecolorallocate($im, 107, 245, 180);
$randcolor[6] = imagecolorallocate($im, 203, 242, 111);
$randcolor[7] = imagecolorallocate($im, 248, 201, 105);

$data[0] = 30;
$data[1] = 20;
$data[2] = 15;
$data[3] = 10;
$data[4] = 8;
$data[5] = 7;
$data[6] = 5;
$data[7] = 5;

$datasum = array_sum($data);

$deg[0] = number_format((30 / $datasum * 360), 2, ".", "");
$deg[1] = number_format((20 / $datasum * 360), 2, ".", "");
$deg[2] = number_format((15 / $datasum * 360), 2, ".", "");
$deg[3] = number_format((10 / $datasum * 360), 2, ".", "");
$deg[4] = number_format((8 / $datasum * 360), 2, ".", "");
$deg[5] = number_format((7 / $datasum * 360), 2, ".", "");
$deg[6] = number_format((5 / $datasum * 360), 2, ".", "");
$deg[7] = number_format((5 / $datasum * 360), 2, ".", "");
echo (
'<pre>');

//print_r($deg);

$datadeg = array();
$datapol = array();
$degbetween = array();
$databetweenpol = array();

for (
$i=0; $i < count($deg) ; $i++) {
   
$datadeg[$i] = get_degtotal($i);
   
$datapol[$i] = get_polar(200, 200, $datadeg[$i], 100);
}

for (
$i=0; $i < count($datadeg) ; $i++) {
   
/*this is a trick where you take 2deg angle before
    and get the smaller radius so that you can have a pt to
    `imagefill` the chartboundary
    */
   
$degbetween[$i] = ($datadeg[$i]-2);
   
$databetweenpol[$i] = get_polar(200, 200, $degbetween[$i], 50);
}

print_r($datadeg);
print_r($degbetween);
print_r($databetweenpol);
//exit;

for ($i=0; $i<count($deg); $i++) {
   
imageline ($im, 200, 200, $datapol[$i]['x2'], $datapol[$i]['y2'], $black);
}
imagearc($im, 200, 200, 200, 200, 0, 360, $black);

for (
$i=0; $i<count($deg); $i++) {
   
imagefill ($im, $databetweenpol[$i]['x2'], $databetweenpol[$i]['y2'], $randcolor[$i]);

}

//header ("Content-type: image/png");
imagepng($im, 'piechart.png');
?>
<img src='piechart.png'>
jerryscript at aol dot com 26-Dec-2003 02:05
[note-Apache/1.3.29 (Win32) PHP/4.3.4]

The imagearc (and imageellipse) functions do not accept line thicknesses when drawn from 0 to 360 degrees.

Drawing from 0 to 359 and again from 359 to 360 does create an ellipse with the current line thickness.

Jerry
eamon at hostelworld dot com 17-Dec-2003 07:24
Right...
possibly the easiest way of drawing a filled circle:
Loop through the imagearc function incrementing the diameter by one pixel:
<?
 // --- code fragment --- //

for($i=1; $i<$Diameter; $i++){
  imagearc($Image, $CenterX, $CenterY, $i, $i, $Start, $End, $Color);
}

// --------------------- //

?>

This works great for circles with diameters up to about 60 or 70 pixels wide. After that, you start to get pixle gaps.
logang at deltatee dot com 04-Aug-2003 08:19
Heres a function to make a curve between two points... This will be a downward curve but it wouldn't be hard to make a similar function to make an upward curve. The first point has to be to the left of the second point ($x1 < $x2), and height is actually backwards. The larger height is the less of a crest the curve has. I imagine with a few modifications this functions could make upward curves as well.

function ImageCurveDown ($image, $x1, $y1, $x2, $y2, $height, $color) {
    $presicion = 1;

    for ($left = ($x1-$x2); $left < 0; $left++){
        if ($y1 < $y2) {
            $cy = $y2 + $height;
            $cx = $x1 - $left;
        } else {
            $cy = $y1 + $height;
            $cx = $x2 + $left;
        }
        $nx1 = abs($x1 - $cx);
        $ny1 = abs($y1 - $cy);
        $nx2 = abs($x2 - $cx);
        $ny2 = abs($y2 - $cy);

        if ($y1 < $y2) {
            if ($nx2 == 0 || $ny1 == 0) continue;
            $angle1 = atan($height/$nx2);
            $A1 = $nx2/cos ($angle1);
            $B1 = $ny2/sin ($angle1);
            $angle2 = pi()/2 +atan($left/$ny1);
            $A2 = $nx1/cos ($angle2);
            $B2 = $ny1/sin ($angle2);
        } else {
            if ($ny2 == 0 || $nx1 == 0) continue;
            $angle1 = atan($ny2/$nx2);
            $A1 = abs($nx2/cos ($angle1));
            $B1 = abs($ny2/sin ($angle1));
            $angle2 = atan($height/$nx1);
            $A2 = abs ($nx1/cos ($angle2));
            $B2 = abs($ny1/sin ($angle2));
        }

        if (abs($A1 - $A2) < $presicion && abs ($B1 - $B2) < $presicion) {
            ImageArc($image, $cx, $cy, $A1*2, $B1*2, 180+rad2deg($angle2), 360-rad2deg($angle1), $color);
        }
    }
}
23-Jan-2003 08:55
Please note that in order to draw a complete circle or ellipse (without using the imageellipse) you mustn't use 0° for both s and e. If you do this you will get, umm, nothing. Instead set s to 0° and e to 360° to get a complete circle or ellipse.
jinny at 263 dot net 13-May-2002 10:27
imagesetstyle() sets the style to be used by all line drawing functions when drawing with the special color .

Here goes a example of drawing a dashed-line circle.enjoy!

<?php

header
("Content-type: image/jpeg");
$im = imagecreate(100,100);

$b   = imagecolorallocate ($im, 0, 0, 0);
$w   = imagecolorallocate ($im, 255, 255, 255);

$style = array ($b,$b,$b,$b,$b,$w,$w,$w,$w,$w);

imagesetstyle ($im, $style);

imagearc($im,50,50,100,100,0,360,IMG_COLOR_STYLED);

imagejpeg($im);
imagedestroy($im);
?>
arve at skogvold dot as 30-Nov-2001 01:04
I found a better way for drawing a pie chart:

header ("Content-type: image/png");
$diameter = 100;
$radius = $diameter / 2;
$centerX = $radius;
$centerY = $radius;

$im = @ImageCreate ($diameter, $diameter)
    or die ("Cannot Initialize new GD image stream");

$background = ImageColorAllocate ($im, 0, 0, 0);
$red = ImageColorAllocate ($im, 176, 0, 0);

function fill_arc($start, $end, $color) {
    global $diameter, $centerX, $centerY, $im, $radius;
    imagearc($im, $centerX, $centerY, $diameter, $diameter, $start, $end, $color);
    imageline($im, $centerX, $centerY, $centerX + cos(deg2rad($start)) * $radius, $centerY + sin(deg2rad($start)) * $radius, $color);
    imageline($im, $centerX, $centerY, $centerX + cos(deg2rad($end)) * $radius, $centerY + sin(deg2rad($end)) * $radius, $color);
    imagefill ($im,$centerX + $radius * 0.5 *cos(deg2rad($start+($end-$start)/2)), $centerY + $radius * 0.5 * sin(deg2rad($start+($end-$start)/2)), $color);
    }


fill_arc(0,30,$red);
// Will make a red filled arc, starting at 0 degrees, ending at 30 degrees

ImagePng ($im);
marc at resiteit dot com 08-Nov-2001 01:04
Round cornered anti-aliased dynamically sized button.

$w=40;
$h=20;
$im = ImageCreate($w,$h);
$white=ImageColorAllocate($im,255,255,255);
ImageFilledRectangle($im,0,0,$w,$h,$white);
imagecolortransparent ($im, $white);
ImageTTFText ($im, $h+ceil($h/3)+1, 0, -1, $h-1, $col1, "arialbd.ttf", "O");
ImageTTFText ($im, $h+ceil($h/3)+1, 0, $w-$h, $h-1, $col1, "arialbd.ttf", "O");
ImageTTFText ($im, $h+ceil($h/3)+1, 0, 1, $h-1, $col1, "arialbd.ttf", "O");
ImageTTFText ($im, $h+ceil($h/3)+1, 0, $w-$h-2, $h-1, $col1, "arialbd.ttf", "O");
$points=array(
    1,round($h/2),
    round($h/4),$h-round($h/4),
    round($h/2),$h,
    $w-(round($h/2)),$h,
    $w-(round($h/4)),$h-round($h/4),
    $w-2,round($h/2),
    $w-round($h/4),round($h/4),
    $w-round($h/2),0,
    round($h/2),0,
    round($h/4),round($h/4)
);
imagefilledpolygon ($im, $points, 10, $col1);

header("content-type: image/gif");
header("Content-Disposition: filename=name.gif");
ImageGif($im);
ImageDestroy($im);
foripepe at yahoo dot com 02-Sep-2001 09:56
To fill an arc (DiameterX != DiameterY):

<?
function imagefilledarc($Image, $CenterX, $CenterY, $DiameterX, $DiameterY, $Start, $End, $Color) {
    // To draw the arc
    imagearc($Image, $CenterX, $CenterY, $DiameterX, $DiameterY, $Start, $End, $Color);
    // To close the arc with 2 lines between the center and the 2 limits of the arc
    $x = $CenterX + (cos(deg2rad($Start))*($DiameterX/2));
    $y = $CenterY + (sin(deg2rad($Start))*($DiameterY/2));
    imageline($Image, $x, $y, $CenterX, $CenterY, $Color);
    $x = $CenterX + (cos(deg2rad($End))*($DiameterX/2));
    $y = $CenterY + (sin(deg2rad($End))*($DiameterY/2));
    imageline($Image, $x, $y, $CenterX, $CenterY, $Color);
    // To fill the arc, the starting point is a point in the middle of the closed space
    $x = $CenterX + (cos(deg2rad(($Start+$End)/2))*($DiameterX/4));
    $y = $CenterY + (sin(deg2rad(($Start+$End)/2))*($DiameterY/4));
    imagefilltoborder($Image, $x, $y, $Color, $Color);
}
?>

To close the arc with 2 lines (DiameterX != DiameterY):

<?
function imagenofilledarc($Image, $CenterX, $CenterY, $DiameterX, $DiameterY, $Start, $End, $Color) {
    // To draw the arc
    imagearc($Image, $CenterX, $CenterY, $DiameterX, $DiameterY, $Start, $End, $Color);
    // To close the arc with 2 lines between the center and the 2 limits of the arc
    $x = $CenterX + (cos(deg2rad($Start))*($DiameterX/2));
    $y = $CenterY + (sin(deg2rad($Start))*($DiameterY/2));
    imageline($Image, $x, $y, $CenterX, $CenterY, $Color);
    $x = $CenterX + (cos(deg2rad($End))*($DiameterX/2));
    $y = $CenterY + (sin(deg2rad($End))*($DiameterY/2));
    imageline($Image, $x, $y, $CenterX, $CenterY, $Color);
}
?>

An example:
<?
    $destImage = imagecreate( 216, 152 );
    $c0 = imagecolorallocate( $destImage, 0, 255, 255 );
    $c1 = imagecolorallocate( $destImage, 0, 0, 0 );
    $c2 = imagecolorallocate( $destImage, 255, 0, 0 );
    ImageFilledRectangle ( $destImage, 0, 0, 216, 152, $c0 );
    imagefilledarc( $destImage, 108, 76, 180, 80, 0, 130, $c1 );
    imagenofilledarc( $destImage, 108, 76, 180, 80, 0, 130, $c2 );
    header("content-type: image/PNG");
    ImagePNG( $destImage );
    ImageDestroy( $destImage );
?>
08-Apr-2001 10:37
The following site contains heaps of different functions to draw graphs with easy to follow code for newbies and heaps of examples with OVER 60 different predefined graphs
http://www.aditus.nu/jpgraph/index.php
nojer2 at yahoo dot com 01-Apr-2001 02:18
Here's a dashed circle function:

<?php
function dashedcircle($im, $cx, $cy, $radius, $colour, $dashsize=5) {

  
$dash=false;
   for (
$angle=0; $angle<=(180+$dashsize); $angle+=$dashsize) {
     
$x = ($radius * cos(deg2rad($angle)));
     
$y = ($radius * sin(deg2rad($angle)));

      if (
$dash) {
        
imageline($im, $cx+$px, $cy+$py, $cx+$x, $cy+$y, $colour);
        
imageline($im, $cx-$px, $cx-$py, $cx-$x, $cy-$y, $colour);
      }
     
$dash=!$dash;
     
$px=$x;
     
$py=$y;
   }
}
?>
nojer2 at yahoo dot com 01-Apr-2001 02:06
Here's the function to draw rotated ellipses again. This time I've optimised it a bit, fixed the no-fill bug, and used a 'squishratio' rather than a 'radiusmodifier', to make the curves perfect, so ignore my previous version.

<?php
function rotatedellipse($im, $cx, $cy, $width, $height, $rotateangle, $colour, $filled=true) {
  
$step=2;
  
$cosangle=cos(deg2rad($rotateangle));
  
$sinangle=sin(deg2rad($rotateangle));

  
$squishratio = $height/$width;
  
$nopreviouspoint = true;
   for (
$angle=0; $angle<=(180+$step); $angle+=$step) {
      
     
$ox = ($width * cos(deg2rad($angle)));
     
$oy = ($width * sin(deg2rad($angle))) * $squishratio;

     
$x =  + (($ox * $cosangle) - ($oy * $sinangle));
     
$y = $centrey + (($ox * $sinangle) + ($oy * $cosangle));
 
      if (
$nopreviouspoint) {
       
$px=$x;
       
$py=$y;
       
$nopreviouspoint=false;
      }

      if (
$filled) {
        
triangle($im, $cx, $cy, $cx+$px, $cy+$py, $cx+$x, $cy+$y, $colour);
        
triangle($im, $cx, $cy, $cx-$px, $cx-$py, $cx-$x, $cy-$y, $colour);
      } else {
        
imageline($im, $cx+$px, $cy+$py, $cx+$x, $cy+$y, $colour);
        
imageline($im, $cx-$px, $cx-$py, $cx-$x, $cy-$y, $colour);
      }
     
$px=$x;
     
$py=$y;
   }
}

function
triangle($im, $x1,$y1, $x2,$y2, $x3,$y3, $colour) {
  
$coords = array($x1,$y1, $x2,$y2, $x3,$y3);
  
imagefilledpolygon($im, $coords, 3, $colour);
}
?>
ericquil at yahoo dot com 29-Sep-2000 04:30
If circles overlap, a temporary border is needed when filling:
<?php
ImageArc
($im,$x,$y,$w,$h,0,360,$temp_color);
ImageFillToBorder($im,$x,$y,$temp_color,$fill_color);
ImageArc ($im,$x,$y,$w,$h,0,360,$fill_color);
?>
cbriou at orange-art dot fr 17-Sep-2000 07:03
There is another way to fill an arc :

<?php
// To draw the arc
$Color = imagecolorallocate($Image, $Red, $Green, $Blue);
imagearc($Image, $CenterX, $CenterY, $Diameter, $Diameter, $Start, $End, $Color);
// To close the arc with 2 lines between the center and the 2 limits of the arc
$x = $CenterX + (cos(deg2rad($Start))*($Diameter/2));
$y = $CenterY + (sin(deg2rad($Start))*($Diameter/2));
imageline($Image, $x, $y, $CenterX, $CenterY, $Color);
$x = $CenterX + (cos(deg2rad($End))*($Diameter/2));
$y = $CenterY + (sin(deg2rad($End))*($Diameter/2));
imageline($Image, $x, $y, $CenterX, $CenterY, $Color);
// To fill the arc, the starting point is a point in the middle of the closed space
$x = $CenterX + (cos(deg2rad(($Start+$End)/2))*($Diameter/4));
$y = $CenterY + (sin(deg2rad(($Start+$End)/2))*($Diameter/4));
imagefilltoborder($Image, $x, $y, $Color, $Color);
?>
timothyhouck at yahoo dot com 16-Aug-2000 03:58
To do filled arcs, try something like this:

<?php
$diameter
= 50;
imagearc($image, 25, 25, $diameter, $diameter, $start, $end, $color);
while(
$diameter > 0) {
 
imagearc($image, 25, 25, $diameter, $diameter, $start, $start + 1, $color);
 
imagearc($image, 25, 25, $diameter, $diameter, $end - 1, $end, $color);
 
$diameter--;
}
?>

...well you get the point.  It's a kludge, and *very* slow, but it's free.
travis at duluth dot com 22-Dec-1999 06:36
The wierd thing is that the first two integers tell where to place the "circle".
So for example I first create the "pallet" to place the circle on.
$image = imagecreate(500, 500); 
(this makes a huge 500x500 gif :) )
$colorBody = imagecolorallocate($image, 0, 0, 0);
(make the default color of the "pallet" black
$circleColor = imagecolorallocate($image, 255, 0, 255);
(going to make the circle an ugly pink color)
imagearc($image, 250, 250, 300, 300, 0, 360, $circleColor);
Places the image in the center (250,250) and the circle is 300 pixels in diameter.

Hope this helps.
 
Travis Kent Beste

 
show source | credits | stats | sitemap | contact | advertising | mirror sites