date_timezone_set
I have written a little Date Class Library for PHP that supports timestamps for dates greater than 2038 and lesser than 1970.
This library can be used in both PHP4 and PHP5.
Check it out here:
http://xwisdomhtml.com/dateclass.html
date
(PHP 4, PHP 5)
date — Форматирует системную дату/время
Описание
string date
( string $format
[, int $
timestamp
] )
Возвращает время, отформатированное в соответствии с аргументом format , используя метку времени, заданную аргументом timestamp или текущее системное время, если timestamp не задан. Другими словами, timestamp является необязательным и по умолчанию равен значению, возвращаемому функцией time().
Замечание: Для большинства систем допустимыми являются даты с 13 декабря 1901, 20:45:54 GMT по 19 января 2038, 03:14:07 GMT. (Эти даты соответствуют минимальному и максимальному значению 32-битового целого со знаком). Для Windows допустимы даты с 01-01-1970 по 19-01-2038.
Замечание: Для получения метки времени из строкового представления даты можно использовать функцию strtotime(). Кроме того, некоторые базы данных имеют собственные функции для преобразования внутреннего представления даты в метку времени (напрмер, функция MySQL » UNIX_TIMESTAMP).
| Символ в строке format | Описание | Пример возвращаемого значения |
|---|---|---|
| a | Ante meridiem или Post meridiem в нижнем регистре | am или pm |
| A | Ante meridiem или Post meridiem в верхнем регистре | AM или PM |
| B | Время в стадарте Swatch Internet | От 000 до 999 |
| c | Дата в формате ISO 8601 (добавлено в PHP 5) | 2004-02-12T15:19:21+00:00 |
| d | День месяца, 2 цифры с ведущими нулями | от 01 до 31 |
| D | Сокращенное наименование дня недели, 3 символа | от Mon до Sun |
| F | Полное наименование месяца, например January или March | от January до December |
| g | Часы в 12-часовом формате без ведущих нулей | От 1 до 12 |
| G | Часы в 24-часовом формате без ведущих нулей | От 0 до 23 |
| h | Часы в 12-часовом формате с ведущими нулями | От 01 до 12 |
| H | Часы в 24-часовом формате с ведущими нулями | От 00 до 23 |
| i | Минуты с ведущими нулями | 00 to 59 |
| I (заглавная i) | Признак летнего времени | 1, если дата соответствует летнему времени, иначе 0 otherwise. |
| j | День месяца без ведущих нулей | От 1 до 31 |
| l (строчная 'L') | Полное наименование дня недели | От Sunday до Saturday |
| L | Признак високосного года | 1, если год високосный, иначе 0. |
| m | Порядковый номер месяца с ведущими нулями | От 01 до 12 |
| M | Сокращенное наименование месяца, 3 символа | От Jan до Dec |
| n | Порядковый номер месяца без ведущих нулей | От 1 до 12 |
| O | Разница с временем по Гринвичу в часах | Например: +0200 |
| r | Дата в формате » RFC 2822 | Например: Thu, 21 Dec 2000 16:01:07 +0200 |
| s | Секунды с ведущими нулями | От 00 до 59 |
| S | Английский суффикс порядкового числительного дня месяца, 2 символа | st, nd, rd или th. Применяется совместно с j |
| t | Количество дней в месяце | От 28 до 31 |
| T | Временная зона на сервере | Примеры: EST, MDT ... |
| U | Количество секунд, прошедших с начала Эпохи Unix (The Unix Epoch, 1 января 1970, 00:00:00 GMT) | См. также time() |
| w | Порядковый номер дня недели | От 0 (воскресенье) до 6 (суббота) |
| W | Порядковый номер недели года по ISO-8601, первый день недели - понедельник (добавлено в PHP 4.1.0) | Например: 42 (42-я неделя года) |
| Y | Порядковый номер года, 4 цифры | Примеры: 1999, 2003 |
| y | Номер года, 2 цифры | Примеры: 99, 03 |
| z | Порядковый номер дня в году (нумерация с 0) | От 0 до 365 |
| Z | Смещение временной зоны в секундах. Для временных зон западнее UTC это отрицательное число, восточнее UTC - положительное. | От -43200 до 43200 |
Любые другие символы, встреченные в строке format , будут выведены в результирующую строку без изменений. Z всегда возвращает 0 при использовании gmdate().
Пример #1 Примеры использования функции date()
<?php
// вывод дня недели, например Wednesday
echo date("l");
// вывод даты в формате: Wednesday 15th of January 2003 05:51:38 AM
echo date("l dS of F Y h:i:s A");
// вывод: July 1, 2000 is on a Saturday
echo "July 1, 2000 is on a " . date("l", mktime(0, 0, 0, 7, 1, 2000));
?>
Избежать распознавания символа как форматирующего можно, если экранировать этот символ с помощью \ Если в сочетании с \ символ являееся специальным (например, \t), следует добавлять еще один \.
Пример #2 Экранирование символов в функции date()
<?php
// вывод: Wednesday the 15th
echo date("l \\t\h\e jS");
?>
Функции date() и mktime() для вывода прошедших и будущих дат.
Пример #3 date() и mktime() example
<?php
$tomorrow = mktime(0, 0, 0, date("m") , date("d")+1, date("Y"));
$lastmonth = mktime(0, 0, 0, date("m")-1, date("d"), date("Y"));
$nextyear = mktime(0, 0, 0, date("m"), date("d"), date("Y")+1);
?>
Замечание: Этот метод более надежен, чем вычитание и прибавление секунд к метке времени, так как mktime() учитывает любые неоднозначности в датах (переход на летнее/зимнее время и др.).
Приведем еще несколько примеров использования функции date(). Помните, что следует экранировать все символы, которые вы хотите видеть в результате работы функции без изменений. Это относится и к символам, которые в текущей версии PHP не распознаются как специальные, так как этим символам может быть назначено значение в следующих версиях. Используйте одинарные кавычки для предотвращения преобразования \n в перевод строки.
Пример #4 Форматирование с использованием date()
<?php
// Предположим, что текущая дата March 10th, 2001, 5:16:18 pm
$today = date("F j, Y, g:i a"); // March 10, 2001, 5:16 pm
$today = date("m.d.y"); // 03.10.01
$today = date("j, n, Y"); // 10, 3, 2001
$today = date("Ymd"); // 20010310
$today = date('h-i-s, j-m-y, it is w Day z '); // 05-16-17, 10-03-01, 1631 1618 6 Fripm01
$today = date('\i\t \i\s \t\h\e jS \d\a\y.'); // It is the 10th day.
$today = date("D M j G:i:s T Y"); // Sat Mar 10 15:16:08 MST 2001
$today = date('H:m:s \m \i\s\ \m\o\n\t\h'); // 17:03:17 m is month
$today = date("H:i:s"); // 17:16:17
?>
Для форматирования дат на других языках используйте функции setlocale() и strftime().
См. также описание функций getlastmod(), gmdate(), mktime(), strftime() и time().
add a note
User Contributed Notesdate
Raymond Irving
25-Mar-2008 08:44
25-Mar-2008 08:44
boyfilhote at yahoo dot com dot br
21-Mar-2008 02:29
21-Mar-2008 02:29
Find out how many days a month has (including leap-years) in one single line command:
$numberOfDays = date("d", mktime(0, 0, 0, $month + 1, 0, $year));
This is possible because if you set the field "day" as ZERO in MKTIME, it will consider the last day of month-1.
ash at atomic-network dot co dot uk
20-Mar-2008 09:26
20-Mar-2008 09:26
in regards to: [takzik at ebanat dot com]
simplest way of displaying / formatting dates. strtotime()
<?php
# Date: y-m-d => d-m-y
$time =explode("-","2008-01-01");
krsort($time);
print implode("-",$time);
?>
<p>Will return: 01-01-2008.
<?php
# Date: d-m-y => y-m-d
$time =explode("-","01-01-2008");
krsort($time);
print "<p>".implode("-",$time);
?>
<p>Will return: 2008-01-01.
<?php
# Quickest: Y-m-d => American Format
print date("m-d-Y",strtotime("2008-02-01"));
?>
<p>Will return: 02-01-2008.
<?php
# Quickest: Y-m-d => Brittish Format
print date("d.m.Y",strtotime("2008-01-01"));
?>
<p>Will return: 01.01.2008.
Anonymous
17-Mar-2008 10:56
17-Mar-2008 10:56
Useful tool for creating DATE() specs without having to run 35 tests to get it right: http://www.bitbybit.dk/mysql/date_format/ (says mysql, but covers PHP as well)
Dave Schlaegel
17-Mar-2008 09:09
17-Mar-2008 09:09
Here is an easy MySQL way of getting the difference in dates. For me it is more logical to do this on the select than running it though an additional PHP function after selecting the date. But depends on what your doing of course. I hope it helps.
SELECT ABS(DATEDIFF(NOW(),yourdateField)) as dateDiff
Anonymous
29-Feb-2008 01:05
29-Feb-2008 01:05
## This will produce the first day of last month and the last day of last month
## 2008-01-01 2008-01-31
<?php
echo date("Y-m-01", strtotime("-1 month", strtotime(date("Y-m-d"))))." ".date("Y-m-d", strtotime("-1 day", strtotime(date("Y-m-01")))) ?>
jwagner dot DO at NOT dot SPAM dot digilog dot de
21-Feb-2008 02:06
21-Feb-2008 02:06
The PHP4 replacement for ISO8601 posted by fokeyjoe has a little flaw:
The time in ISO is in 24 hour format, so an uppercase H must be used.
Correct format is:
$sISO8601=date('Y-m-d\TH:i:s',$nTimestamp). substr_replace(date('O',$nTimestamp),':',3,0);
Short version for NOW:
$sISO8601=date('Y-m-d\TH:i:s'). substr_replace(date('O'),':',3,0);
Juan Paredes
25-Jan-2008 11:59
25-Jan-2008 11:59
Complementing the information by ZZigc on 28-Dec-2007 07:38, if you want to calculate the number of weeks in a given year, according to the week definition by ISO 8601, the following should be enough:
date('W', mktime(0,0,0,12,28,$year) );
(the last week on a give year always contains 28-Dec)
jc
31-Dec-2007 06:28
31-Dec-2007 06:28
date("W") returns the iso8601 week number, while date("Y") returns the _current_ year. This can lead to odd results. For example today (dec 31, 2007) it returns 1 for the week and of course 2007 for the year. This is not wrong in a strict sense because iso defines this week as the first of 2008 while we still have 2007.
So, if you don't have another way to safely retrieve the year according to the iso8061 week-date - strftime("%G") doesn't work on some systems -, you should be careful when working with date("W").
For most cases strftime("%W") should be a safe replacement.
[edit: Much easier is to use "o" (lower case O) instead of "Y"]
ZZigc
28-Dec-2007 10:38
28-Dec-2007 10:38
I wanted to get the number of weeks for particular year.
Example with date():
<?php
$weeks_in_year = date("W", strtotime("12/31/2007"));
?>
It works for years smaller than current year, but returns '01' when year was the same or bigger as current year.
Not sure if I missed something or maybe misused this function but I couldn't get it to work even with different date representations.
So the workaround was using different function.
Example with strftime():
<?php
$weeks_in_year = strftime("%W",strtotime("12/31/2007"));
?>
Now it works as a charm.
PHP v.4.4.7
june at overlie dot no
19-Dec-2007 06:54
19-Dec-2007 06:54
re: marius at svr dot ro
to anyone using marius' function, it needs some minor fixes (look for a ---->)
<?php
//The function returns the no. of business days between two dates and it skeeps the holidays
function getWorkingDays($startDate,$endDate,$holidays){
//The total number of days between the two dates. We compute the no. of seconds and divide it to 60*60*24
//We add one to inlude both dates in the interval.
$days = (strtotime($endDate) - strtotime($startDate)) / 86400 + 1;
$no_full_weeks = floor($days / 7);
$no_remaining_days = fmod($days, 7);
//It will return 1 if it's Monday,.. ,7 for Sunday
$the_first_day_of_week = date("N",strtotime($startDate));
$the_last_day_of_week = date("N",strtotime($endDate));
//---->The two can be equal in leap years when february has 29 days, the equal sign is added here
//In the first case the whole interval is within a week, in the second case the interval falls in two weeks.
if ($the_first_day_of_week <= $the_last_day_of_week){
if ($the_first_day_of_week <= 6 && 6 <= $the_last_day_of_week) $no_remaining_days--;
if ($the_first_day_of_week <= 7 && 7 <= $the_last_day_of_week) $no_remaining_days--;
}
else{
if ($the_first_day_of_week <= 6) $no_remaining_days--;
//In the case when the interval falls in two weeks, there will be a Sunday for sure
$no_remaining_days--;
}
//The no. of business days is: (number of weeks between the two dates) * (5 working days) + the remainder
//---->february in none leap years gave a remainder of 0 but still calculated weekends between first and last day, this is one way to fix it
$workingDays = $no_full_weeks * 5;
if ($no_remaining_days > 0 )
{
$workingDays += $no_remaining_days;
}
//We subtract the holidays
foreach($holidays as $holiday){
$time_stamp=strtotime($holiday);
//If the holiday doesn't fall in weekend
if (strtotime($startDate) <= $time_stamp && $time_stamp <= strtotime($endDate) && date("N",$time_stamp) != 6 && date("N",$time_stamp) != 7)
$workingDays--;
}
return $workingDays;
}
//Example:
$holidays=array("2006-12-25","2006-12-26","2007-01-01");
echo getWorkingDays("2006-12-22","2007-01-06",$holidays)
// => will return 8
?>
Otherwise, I found this very useful, thanks marius:)
Bill at wLathrop com
13-Dec-2007 04:56
13-Dec-2007 04:56
For JasonLFunk
I did some testing on the occurrence for a given date within the month (i.e 1st Monday, 2nd Wednesday, 3rd Friday, etc.).
where $dDate is a getdate() array
intval(($dDate['mday']-1)/7)+1
Returns an integer representing the week for a given date. I tested on a complete calendar month and it seems to work well.
I then convert to a string and compare to a string list of values to see if it is in the list. If it is - it qualifies. So, my list of values might be '2,4' representing every 2nd and 4th occurrence.
bikinyboy at example dot com
11-Dec-2007 07:44
11-Dec-2007 07:44
This function is like date, but it "speaks" Hungarian (or an other language)
<?php
/*
these are the hungarian additional format characters
ö: full textual representation of the day of the week
Ö: full textual representation of the day of the week (first character is uppercase),
ő: short textual representation of the day of the week,
Ő: short textual representation of the day of the week (first character is uppercase),
ü: full textual representation of a month
Ü: full textual representation of a month (first character is uppercase),
ű: short textual representation of a month
Ű: short textual representation of a month (first character is uppercase),
*/
function date_hu($formatum, $timestamp=0) {
if (($timestamp <= -1) || !is_numeric($timestamp)) return '';
$q['ö'] = array(-1 => 'w', 'vasárnap', 'hétfő', 'kedd', 'szerda', 'csütörtök', 'péntek', 'szombat');
$q['Ö'] = array(-1 => 'w', 'Vasárnap', 'Hétfő', 'Kedd', 'Szerda', 'Csütörtök', 'Péntek', 'Szombat');
$q['ő'] = array(-1 => 'w', 'va', 'hé', 'ke', 'sze', 'csü', 'pé', 'szo');
$q['Ő'] = array(-1 => 'w', 'Va', 'Hé', 'Ke', 'Sze', 'Csü', 'Pé', 'Szo');
$q['ü'] = array(-1 => 'n', '', 'január', 'február', 'március', 'április', 'május', 'június', 'július', 'augusztus', 'szeptember', 'október', 'november', 'december');
$q['Ü'] = array(-1 => 'n', '', 'Január', 'Február', 'Március', 'Április', 'Május', 'Június', 'Július', 'Augusztus', 'Szeptember', 'Október', 'November', 'December');
$q['ű'] = array(-1 => 'n', '', 'jan', 'febr', 'márc', 'ápr', 'máj', 'júni', 'júli', 'aug', 'szept', 'okt', 'nov', 'dec');
$q['Ű'] = array(-1 => 'n', '', 'Jan', 'Febr', 'Márc', 'Ápr', 'Máj', 'Júni', 'Júli', 'Aug', 'Szept', 'Okt', 'Nov', 'Dec');
if ($timestamp == 0)
$timestamp = time();
$temp = '';
$i = 0;
while ( (strpos($formatum, 'ö', $i) !== FALSE) || (strpos($formatum, 'Ö', $i) !== FALSE) ||
(strpos($formatum, 'ő', $i) !== FALSE) || (strpos($formatum, 'Ő', $i) !== FALSE) ||
(strpos($formatum, 'ü', $i) !== FALSE) || (strpos($formatum, 'Ü', $i) !== FALSE) ||
(strpos($formatum, 'ű', $i) !== FALSE) || (strpos($formatum, 'Ű', $i) !== FALSE)) {
$ch['ö']=strpos($formatum, 'ö', $i);
$ch['Ö']=strpos($formatum, 'Ö', $i);
$ch['ő']=strpos($formatum, 'ő', $i);
$ch['Ő']=strpos($formatum, 'Ő', $i);
$ch['ü']=strpos($formatum, 'ü', $i);
$ch['Ü']=strpos($formatum, 'Ü', $i);
$ch['ű']=strpos($formatum, 'ű', $i);
$ch['Ű']=strpos($formatum, 'Ű', $i);
foreach ($ch as $k=>$v)
if ($v === FALSE)
unset($ch[$k]);
$a = min($ch);
$temp .= date(substr($formatum, $i, $a-$i), $timestamp) . $q[$formatum[$a]][date($q[$formatum[$a]][-1], $timestamp)];
$i = $a+1;
}
$temp .= date(substr($formatum, $i), $timestamp);
return $temp;
}
echo date_hu('Y. ü j. (ö) G:i');
?>
redcore at gmail dot com
19-Nov-2007 05:24
19-Nov-2007 05:24
For those of us who don't have 5.x installed (that puts a colon in the time zone)...
<?php
$timezone = date("O"); // get timezone
$timezone_end = substr($timezone, -2, 2); // get last two numbers
$timezone= substr($timezone, 0, -2); // get first half
echo $timezone = $timezone . ":" . $timezone_end; // add colon
?>
info at NOSPAM dot ogmatter dot com
29-Oct-2007 07:30
29-Oct-2007 07:30
Hello, these notes have been very helpful and help me solve the following problem.
I have a db with scheduled items that contain a start date, a day to occur on and how many weeks from the next closest day to happen again. I wrote the following script to do the following
1. Accept : starting date, the current date, the number of weeks between occurances and the day of the week it is to occur on.
2. Find the closest future day of the week argument from the start date.
3. Find out when the next time the item should happen via the weeks inbetween and the closest day of the week to the start date.
The result could be compared with your current date to trigger your periodical item or simply to find out when the next occurances will happen.
// $startDate:Date
// $todayDate:Date
// $weeks:Int - number of weeks in between
// $wantDay:String - full day of the week
function getWeekPeriodDate($startDate,$todayDate,$weeks,$wantDay){
$startDate = date("Y-m-d", strtotime("next $wantDay" ,strtotime($startDate)));
$dayDiff = round((strtotime($startDate)-strtotime($todayDate))/(24*60*60),0);
$weekPeriodDiff = abs(round($dayDiff/7/$weeks)*$weeks);
return date("Y-m-d",strtotime($startDate . " + " . $weekPeriodDiff . " weeks"));
}
Usage :getWeekPeriodDate("2006-July-1","2007-Nov-5",8,"Tuesday")
returns : 2007-11-20 (which is the next Tuesday based on 8 week periods since the next Tuesday closest to the start date)
snobord787 at msn dot com
29-Aug-2007 09:06
29-Aug-2007 09:06
I modified (erenezgu at gmail.com)'s code so you don't have to redirect but is stored in cookies.
<?php
if(empty($_COOKIE['offset'])) {
// Javascript is our friend!
$header='
<script type="text/javascript">
document.cookie="offset=" + ( (new Date()).getTimezoneOffset()*60)*(-1)-'.abs(date('Z')).';
</script>
';
}
// Example Usage
echo date('d/m/Y H:i:s', time()+$_COOKIE['offset'] );
?>
jasonlfunk (at) gmail dot com
10-Aug-2007 12:39
10-Aug-2007 12:39
If there is an easier way to find the week of the month, let me know. Here is how I figured out how to do it;
date("W") - date("W",strtotime(date("F") . " 1st " . date("Y"))) + 1;
luis dot sv at gmail dot com
20-Jul-2007 11:00
20-Jul-2007 11:00
In relation to soreenpk at yahoo dot com's message:
That code doesn't work for two dates with a difference larger than a year, for example:
$digest_date = "2006-04-14";
$date2="2007-04-15";
$date_diff = date("d",strtotime($date2)) - date("d",strtotime($digest_date));//$date_diff = 1
samuel at islabinaria dot com
15-Jul-2007 07:18
15-Jul-2007 07:18
Here is a backward compatible version of dates_interconv
http://www.php.net/manual/en/function.date.php#71397
which also works with time (hours, minutes and seconds) and months in "M" format (three letters):
<?php
/**
mod of
http://www.php.net/manual/en/function.date.php#71397
* Converts a date and time string from one format to another (e.g. d/m/Y => Y-m-d, d.m.Y => Y/d/m, ...)
*
* @param string $date_format1
* @param string $date_format2
* @param string $date_str
* @return string
*/
function dates_interconv($date_format1, $date_format2, $date_str)
{
$base_struc = split('[:/.\ \-]', $date_format1);
$date_str_parts = split('[:/.\ \-]', $date_str );
// print_r( $base_struc ); echo "\n"; // for testing
// print_r( $date_str_parts ); echo "\n"; // for testing
$date_elements = array();
$p_keys = array_keys( $base_struc );
foreach ( $p_keys as $p_key )
{
if ( !empty( $date_str_parts[$p_key] ))
{
$date_elements[$base_struc[$p_key]] = $date_str_parts[$p_key];
}
else
return false;
}
// print_r($date_elements); // for testing
if (array_key_exists('M', $date_elements)) {
$Mtom=array(
"Jan"=>"01",
"Feb"=>"02",
"Mar"=>"03",
"Apr"=>"04",
"May"=>"05",
"Jun"=>"06",
"Jul"=>"07",
"Aug"=>"08",
"Sep"=>"09",
"Oct"=>"10",
"Nov"=>"11",
"Dec"=>"12",
);
$date_elements['m']=$Mtom[$date_elements['M']];
}
// print_r($date_elements); // for testing
$dummy_ts = mktime(
$date_elements['H'],
$date_elements['i'],
$date_elements['s'],
$date_elements['m'],
$date_elements['d'],
$date_elements['Y']
);
return date( $date_format2, $dummy_ts );
}
?>
Usage:
<?php
$df_src = 'd/m/Y H:i:s';
$df_des = 'Y-m-d H:i:s';
echo dates_interconv( $df_src, $df_des, '25/12/2005 23:59:59');
?>
Output:
2005-12-25 23:59:59
pierrotevrard at gmail dot com
03-Jul-2007 04:11
03-Jul-2007 04:11
For people who used "z" format...
The real range of "z" key format is 0 to 365 (instead of 366) and "z" represent the number of spent days in the year.
See this examples :
<?php
define ("\n" , NL );
print '<pre>';
print '"z" format interpretation:' . NL . NL;
print 'On 0 timestamp: "' . date( 'z : Y-m-d' , 0 ) . '"' . NL;
//show: On 0 timestamp: "0 : 1970-01-01"
print 'On second unix day: "' . date( 'z : Y-m-d' , 3600*24 ) . '"' . NL;
//show: On second unix day: "1 : 1970-01-02"
print 'On the last day of a leap year: "' . date( 'z : Y-m-d' , mktime( 23, 59, 59, 12, 31, 2000 ) ) . '"' . NL;
//show: On the last day of a leap year: "365 : 2000-12-31"
print 'On the day after the last day of a leap year: "' . date( 'z : Y-m-d' , mktime( 23, 59, 59, 12, 31+1, 2000 ) ) . '"' . NL;
//show: On the day after the last day of a leap year: "0 : 2001-01-01"
print '</pre>';
?>
jcwebb at dicoe dot com
19-Jun-2007 10:48
19-Jun-2007 10:48
i needed the day (eg. 27th) of the last Monday of a month
<?php
$d=cal_days_in_month(CAL_GREGORIAN,$m,$y); // days in month
if (date('l',mktime(0,0,0,$m,$d,$y))=='Monday'): $finalmonday=$d;
else: $finalmonday=date('d',strtotime('last Monday',mktime(0,0,0,$m,$d,$y))); // day(date) of last monday of month, eg 26
endif;
?>
this also works...
<?php
$finalmonday=date('d',strtotime('last Monday',mktime(0,0,0,$m,($d+1),$y)));
//the '$d+1' is to catch the last day IS a monday (eg. dec 2007)
?>
Hope it helps, BigJonMX
boris at psyonline dot ru
14-Jun-2007 08:05
14-Jun-2007 08:05
<?php
/**
* Get date in RFC3339
* For example used in XML/Atom
*
* @param integer $timestamp
* @return string date in RFC3339
* @author Boris Korobkov
* @see http://tools.ietf.org/html/rfc3339
*/
function date3339($timestamp=0) {
if (!$timestamp) {
$timestamp = time();
}
$date = date('Y-m-d\TH:i:s', $timestamp);
$matches = array();
if (preg_match('/^([\-+])(\d{2})(\d{2})$/', date('O', $timestamp), $matches)) {
$date .= $matches[1].$matches[2].':'.$matches[3];
} else {
$date .= 'Z';
}
return $date;
}
?>
john at hotmail dot com
12-Jun-2007 06:55
12-Jun-2007 06:55
Just a small addition to dmitriy. If the present date is in daylight saving time, and the date in the past is not, the result will not be a whole number by dividing by 86400. It will be something like 48.958333333. This is because the day in which it changes from normal to daylight saving time is one hour longer than normal (90000 secs) and the opposite is true when changing back (the day would be one hour shorter - 82800 secs).
If you want a whole number of days use the following instead:
<?php
$digest_date = "2007-01-01";
$date_diff = round( abs(strtotime(date('y-m-d'))-strtotime($digest_date)) / 86400, 0 );
?>
dmitriy dot yakovlev at gmail dot com
11-Jun-2007 08:55
11-Jun-2007 08:55
soreenpk - the code snippet you posted will not find the day difference between two days that are not in the same month. This will:
<?php
$digest_date = "2007-06-01";
$date_diff = abs(strtotime(date('y-m-d'))-strtotime($digest_date)) / 86400;
?>
86400 is the number of seconds in a day, so finding the date difference in seconds and converting to days will give true day difference between dates. Cheers.
pburlandoA_Remove_TgmailDOTcom
20-May-2007 12:30
20-May-2007 12:30
This is an implementation for days360 formula used in financial calc software, this asumes year with 360 days and months with 30 days.
I am looking for a reliable function to add days to a date using 30[E]/360 format.
<?php
/* Calc days between two dates using the financial calendar
30/360 (usa) or 30E/360(european)<-default
$fecha1 and $fecha2 in format: aaaa-mm-dd
return days or -1 in case of error.
based on cost_analysis.py module Ver. 0.1 public domain, no license required by Harm Kirchhoff
*/
function days_360($fecha1,$fecha2,$europeo=true) {
//try switch dates: min to max
if( $fecha1 > $fecha2 ) {
$temf = $fecha1;
$fecha1 = $fecha2;
$fecha2 = $temf;
}
// get day month year...
list($yy1, $mm1, $dd1) = explode('-', $fecha1);
list($yy2, $mm2, $dd2) = explode('-', $fecha2);
if( $dd1==31) { $dd1 = 30; }
//checks according standars: 30E/360 or 30/360.
if(!$europeo) {
if( ($dd1==30) and ($dd2==31) ) {
$dd2=30;
} else {
if( $dd2==31 ) {
$dd2=30;
}
}
}
//check for invalid date
if( ($dd1<1) or ($dd2<1) or ($dd1>30) or ($dd2>31) or
($mm1<1) or ($mm2<1) or ($mm1>12) or ($mm2>12) or
($yy1>$yy2) ) {
return(-1);
}
if( ($yy1==$yy2) and ($mm1>$mm2) ) { return(-1); }
if( ($yy1==$yy2) and ($mm1==$mm2) and ($dd1>$dd2) ) { return(-1); }
//Calc
$yy = $yy2-$yy1;
$mm = $mm2-$mm1;
$dd = $dd2-$dd1;
return( ($yy*360)+($mm*30)+$dd );
}
// usage:
echo days_360("2007-01-13","2007-05-20");
?>
fokeyjoe at themotto dot co dot uk
03-May-2007 09:52
03-May-2007 09:52
Another method for getting close to ISO8601 using PHP4 (should cover all versions). This format gets you compliant RDF/RSS feed dates:
$sISO8601=date('Y-m-d\Th:i:s',$nTimestamp). substr_replace(date('O',$nTimestamp),':',3,0);
The main limitation I'm aware of is the non-compliant year around new year.
jonbarnett at gmail dot com
24-Apr-2007 12:37
24-Apr-2007 12:37
To everyone who is posting functions to parse date strings and turn them into time stamps - please look at the strtotime() function. It probably already does whatever you're writing a function to do.
To the person right below me: while your function might be an extremely small bit more efficient, strtotime() will work just fine.
dmitrid at dont_show dot com
10-Mar-2007 12:14
10-Mar-2007 12:14
Note for wips week limits function:
I had to run it over 52 weeks of the year and it was very slow so I've modified to improve:
function week_limits($weekNumber, $year, $pattern)
{
$pattern = ($pattern) ? $pattern : "m/d";
$stday = 7 * $weekNumber - 7;
$stDayNumber = date("w", mktime(0,0,0,1, 1+$stday, $year));
$stUtime = mktime(0,0,0,1,1+$stday-$stDayNumber, $year);
$start_time = date($pattern, $stUtime);
$end_time = date($pattern, $stUtime+6*24*60*60);
return array($start_time, $end_time);
}//week_limits()
marius at svr dot ro
05-Feb-2007 10:54
05-Feb-2007 10:54
Re: steve at somejunkwelike dot com
I think this is a better function to find the business days between two dates. This function requires PHP 5.1.0.
<?php
//The function returns the no. of business days between two dates and it skeeps the holidays
function getWorkingDays($startDate,$endDate,$holidays){
//The total number of days between the two dates. We compute the no. of seconds and divide it to 60*60*24
//We add one to inlude both dates in the interval.
$days = (strtotime($endDate) - strtotime($startDate)) / 86400 + 1;
$no_full_weeks = floor($days / 7);
$no_remaining_days = fmod($days, 7);
//It will return 1 if it's Monday,.. ,7 for Sunday
$the_first_day_of_week = date("N",strtotime($startDate));
$the_last_day_of_week = date("N",strtotime($endDate));
//The two can't be equal because the $no_remaining_days (the interval between $the_first_day_of_week and $the_last_day_of_week) is at most 6
//In the first case the whole interval is within a week, in the second case the interval falls in two weeks.
if ($the_first_day_of_week < $the_last_day_of_week){
if ($the_first_day_of_week <= 6 && 6 <= $the_last_day_of_week) $no_remaining_days--;
if ($the_first_day_of_week <= 7 && 7 <= $the_last_day_of_week) $no_remaining_days--;
}
else{
if ($the_first_day_of_week <= 6) $no_remaining_days--;
//In the case when the interval falls in two weeks, there will be a Sunday for sure
$no_remaining_days--;
}
//The no. of business days is: (number of weeks between the two dates) * (5 working days) + the remainder
$workingDays = $no_full_weeks * 5 + $no_remaining_days;
//We subtract the holidays
foreach($holidays as $holiday){
$time_stamp=strtotime($holiday);
//If the holiday doesn't fall in weekend
if (strtotime($startDate) <= $time_stamp && $time_stamp <= strtotime($endDate) && date("N",$time_stamp) != 6 && date("N",$time_stamp) != 7)
$workingDays--;
}
return $workingDays;
}
//Example:
$holidays=array("2006-12-25","2006-12-26","2007-01-01");
echo getWorkingDays("2006-12-22","2007-01-06",$holidays)
// => will return 8
?>
mtphotographer at yahoo dot com
30-Jan-2007 07:37
30-Jan-2007 07:37
Determine what is next month:
I Had the same issue as matt_wbdi at hotmail dot com
Simple solution is use 1 for the day instead of date("d"), it didnt seem to matter if I use "m", or "n" for the month.
// eg:
// if today is 2007-01-30 the following:
$datePlusoneMonth = mktime(0, 0, 0, date("m")+ 1, date("d"), date("Y"));
echo date("Y-m", $datePlusoneMonth);
//returns 2007-03 which is not next month
// this worked for me:
$datePlusoneMonth = mktime(0, 0, 0, date("m")+ 1, 1, date("Y"));
echo date("Y-m", $datePlusoneMonth);
// returns 2007-02, which IS next month
matt_wbdi at hotmail dot com
30-Jan-2007 01:06
30-Jan-2007 01:06
The below code doesn't work. The $next_month variable, for instance, right now, will be March, even though today is January 30th. The reason is because one month from Jan. 30th is March. But that's not the next month. I would suggest using an array of Month names instead, with their respective number as the key.
code at ashleyhunt dot co dot uk
17-Jan-2007 01:22
17-Jan-2007 01:22
I wanted to shift an sql date forward by a set time period.
This is how I achived it... well handy.
<?
function sql_date_shift($date, $shift)
{
return date("Y-m-d H:i:s" , strtotime($shift, strtotime($date)));
}
// example usage
$date = "2006-12-31 21:00";
$shift "+6 hours"; // could be days, weeks... see function strtotime() for usage
echo sql_date_shift($date, $shift);
// will output: 2007-01-01 03:00:00
?>
Hope it is of use,
Ashley
wcc at techmonkeys dot org
22-Dec-2006 11:22
22-Dec-2006 11:22
In example 3, <?php date("m") ?> is passed to mktime() for the month argument. I believe <?php date("n") ?> should be used instead so that the leading 0's don't make PHP think the arguments are octal values. The same goes for <?php date("j") ?> instead off <?php date("d") ?>.
<?php
echo mktime(0, 0, 0, 09, 09, 2006);
echo "\n";
echo mktime(0, 0, 0, 9, 9, 2006);
?>
1133326800
1157774400
28-Nov-2006 11:26
if you are sending your data to a database, you can just send time() and then use strftime() to turn the time() string into readable time format.
check both time() and strftime() functions both offer more or less same functionality as date(). date() can also be used with time() strings to display time in the past.
more or less with something like:
date("j F, Y - g:ia", $data['date_quoted'])
where time() = $data['date_quoted'] and time() is the exact time date when the string is executed. if this is done towards a database, the time() stored is the actual server time upon script