get_included_files

(PHP 4, PHP 5)

get_included_files返回被 include 和 require 文件名的 array

说明

array get_included_files ( void )

返回所有被 includeinclude_oncerequirerequire_once 的文件名。

返回值

返回所有文件名称的 array。

脚本最初被称为”被包含的文件“,所以脚本自身也会和 include 系列函数引用的脚本列在一起。

被多次 include 和 require 的文件在返回的 array 里只会列出一次。

更新日志

版本 说明
4.0.1 在 PHP 4.0.1 和之前的版本,本函数会假设所有被 required 的文件以 .php 结尾; 其他扩展名结尾的文件不会被返回。get_included_files() 返回的 array 仅仅列出被 includeinclude_once 所包含的文件。

范例

Example #1 get_included_files() 范例

<?php
// 本文件是 abc.php

include 'test1.php';
include_once 
'test2.php';
require 
'test3.php';
require_once 
'test4.php';

$included_files get_included_files();

foreach (
$included_files as $filename) {
    echo 
"$filename\n";
}

?>

以上例程会输出:

abc.php
test1.php
test2.php
test3.php
test4.php

注释

Note:

使用 auto_prepend_file 配置指令所包含的文件不会包含在返回的数组里。

参见

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User Contributed Notes 5 notes

up
1
RPaseur at NationalPres dot org
8 years ago
As is often the case, YMMV.  I tried the __FILE__ and SCRIPT_FILENAME comparison and found this:

SCRIPT_FILENAME: /var/www/cgi-bin/php441
__FILE__: /raid/home/natpresch/natpresch/RAY_included.php

As an alternative:

count(get_included_files());

Gives one when the script is standalone and always more than one when the script is included.
up
1
donikuntoro at integraasp dot com
2 years ago
This function aims to perform filtering of files that have been included :

<?php
function setIncludeFiles($arrayInc = array()){
   
$incFiles = get_included_files();
    if((
count($arrayInc)>0)&&(count($incFiles)>0)){
       
$aInt = array_intersect($arrayInc,$incFiles);
        if(
count($aInt)>0){
            return
false;
       }elseif(
count($aInt)<1) {
        foreach(
$arrayInc as $inc){
            if(
is_file($inc))
                include(
$inc);
            else{
                return
false;
            }
        }
       }   
    }else{
        return
false;
    }
}
?>

Usage :

<?php
$toBeInclude
= array('/data/your_include_files_1.php',
'/data/your_include_files_2.php',
'/data/your_include_files_3.php',
);
setIncludeFiles($toBeInclude);
?>

Return false if something goes wrong.
up
1
yarco dot w at gmail dot com
6 years ago
If you have a MAIN php script which you don't want to be included by other scripts, you could use this function. For example:

main.php:
<?php
function blockit()
{
 
$buf = get_included_files();
  return
$buf[0] != __FILE__;
}

blockit() and exit("You can not include a MAIN file as a part of your script.");

print
"OK";
?>

So other script couldn't include main.php to modify its internal global vars.
up
1
indigohaze at gmail dot com
7 years ago
Something that's not noted in the docs, if a file is included remotely and you do a get_included_files() in the include itself it will *not* return the document that included it.

ie:
test2.php (server 192.168.1.14):
<?php

include("http://192.168.1.11/test/test3.php");

?>

test3.php (server 192.168.1.11):

<?php

$files
= get_included_files();

print_r($files);
?>

returns:

Array ( [0] => /var/www/localhost/htdocs/test/test3.php )

Which means you can use get_included_files() to help intercept and prevent XSS-style attacks against your code.
up
0
keystorm :at: gmail dotcom
9 years ago
As of PHP5, this function seems to return an array with the first index being the script all subsequent scripts are included to.
If index.php includes b.php and c.php and calls get_included_files(), the returned array looks as follows:

index.php
a.php
b.php

while in PHP<5 the array would be:

a.php
b.php

If you want to know which is the script that is including current script you can use $_SERVER['SCRIPT_FILENAME'] or any other similar server global.

If you also want to ensure current script is being included and not run independently you should evaluate following expression:

__FILE__ != $_SERVER['SCRIPT_FILENAME']

If this expression returns TRUE, current script is being included or required.
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