ArrayObject::offsetExists
Speaking of offsetGet() method overloading, be advised, that if you're iterating through Object via foreach, this method wouldn't be called. Iterator's current() method will be called instead.
ArrayObject::offsetGet
(PHP 5 >= 5.1.0)
ArrayObject::offsetGet — 指定したインデックスの値を返す
パラメータ
- index
-
値のインデックス。
返り値
指定したインデックスの値、あるいは FALSE を返します。
例
例1 ArrayObject::offsetget の例
<?php
$arrayobj = new ArrayObject(array('zero', 7, 'example'=>'e.g.'));
var_dump($arrayobj->offsetget(1));
var_dump($arrayobj->offsetget('example'));
var_dump($arrayobj->offsetexists('notfound'));
?>
上の例の出力は以下となります。
int(7) string(4) "e.g." bool(false)
add a note
User Contributed NotesArrayObject::offsetGet
Alex Andrienko
20-Jan-2009 11:58
20-Jan-2009 11:58
Sam
30-Nov-2007 11:01
30-Nov-2007 11:01
If you're overloading ArrayObject, it's worth noting that while this method (when implemented by the parent) will return a reference, so code like $fakeArray['foobar']['hello'] = 1; will work like you expect.
However, when you overload the offsetGet method, you CANNOT define it as &offsetGet, so the above code falls out (because it returns the 'foobar' variable before you actually work with it).
This is something that the developers broke between 5.0 and 5.1, and was closed as bogus (http://bugs.php.net/bug.php?id=34783). So this is not a big, or question, or request, but just something worth noting.