getdate

Last updated: Sun, 25 Nov 2007

date

(PHP 4, PHP 5)

date — 格式化一个本地时间／日期

说明

string date ( string $format [, int $timestamp ] )

返回将整数 timestamp 按照给定的格式字串而产生的字符串。如果没有给出时间戳则使用本地当前时间。换句话说，timestamp 是可选的，默认值为 time()。

Tip

自 PHP 5.1.1 起有几个有用的常量可用作标准的日期／时间格式来指定 format 参数。

Tip

自 PHP 5.1 起在 $_SERVER['REQUEST_TIME'] 中保存了发起该请求时刻的时间戳。

Note: 有效的时间戳典型范围是格林威治时间 1901 年 12 月 13 日 20:45:54 到 2038 年 1 月 19 日 03:14:07。（此范围符合 32 位有符号整数的最小值和最大值）。不过在 PHP 5.1 之前此范围在某些系统（如 Windows）中限制为从 1970 年 1 月 1 日到 2038 年 1 月 19 日。

Note: 要将字符串表达的时间转换成时间戳，应该使用 strtotime()。此外一些数据库有一些函数将其时间格式转换成时间戳（例如 MySQL 的 » UNIX_TIMESTAMP 函数）。

**格式字串可以识别以下 *`format`* 参数的字符串**
`format` 字符	说明	返回值例子
日	---	---
d	月份中的第几天，有前导零的 2 位数字	01 到 31
D	星期中的第几天，文本表示，3 个字母	Mon 到 Sun
j	月份中的第几天，没有前导零	1 到 31
l（“L”的小写字母）	星期几，完整的文本格式	Sunday 到 Saturday
N	ISO-8601 格式数字表示的星期中的第几天（PHP 5.1.0 新加）	1（表示星期一）到 7（表示星期天）
S	每月天数后面的英文后缀，2 个字符	st，nd，rd 或者 th。可以和 j 一起用
w	星期中的第几天，数字表示	0（表示星期天）到 6（表示星期六）
z	年份中的第几天	0 到 366
星期	---	---
W	ISO-8601 格式年份中的第几周，每周从星期一开始（PHP 4.1.0 新加的）	例如：42（当年的第 42 周）
月	---	---
F	月份，完整的文本格式，例如 January 或者 March	January 到 December
m	数字表示的月份，有前导零	01 到 12
M	三个字母缩写表示的月份	Jan 到 Dec
n	数字表示的月份，没有前导零	1 到 12
t	给定月份所应有的天数	28 到 31
年	---	---
L	是否为闰年	如果是闰年为 1，否则为 0
o	ISO-8601 格式年份数字。这和 Y 的值相同，只除了如果 ISO 的星期数（W）属于前一年或下一年，则用那一年。（PHP 5.1.0 新加）	Examples: 1999 or 2003
Y	4 位数字完整表示的年份	例如：1999 或 2003
y	2 位数字表示的年份	例如：99 或 03
时间	---	---
a	小写的上午和下午值	am 或 pm
A	大写的上午和下午值	AM 或 PM
B	Swatch Internet 标准时	000 到 999
g	小时，12 小时格式，没有前导零	1 到 12
G	小时，24 小时格式，没有前导零	0 到 23
h	小时，12 小时格式，有前导零	01 到 12
H	小时，24 小时格式，有前导零	00 到 23
i	有前导零的分钟数	00 到 59>
s	秒数，有前导零	00 到 59>
时区	---	---
e	时区标识（PHP 5.1.0 新加）	例如：UTC，GMT，Atlantic/Azores
I	是否为夏令时	如果是夏令时为 1，否则为 0
O	与格林威治时间相差的小时数	例如：+0200
P	与格林威治时间（GMT）的差别，小时和分钟之间有冒号分隔（PHP 5.1.3 新加）	例如：+02:00
T	本机所在的时区	例如：EST，MDT（【译者注】在 Windows 下为完整文本格式，例如“Eastern Standard Time”，中文版会显示“中国标准时间”）。
Z	时差偏移量的秒数。UTC 西边的时区偏移量总是负的，UTC 东边的时区偏移量总是正的。	-43200 到 43200
完整的日期／时间	---	---
c	ISO 8601 格式的日期（PHP 5 新加）	2004-02-12T15:19:21+00:00
r	RFC 822 格式的日期	例如：Thu, 21 Dec 2000 16:01:07 +0200
U	从 Unix 纪元（January 1 1970 00:00:00 GMT）开始至今的秒数	参见 time()

格式字串中不能被识别的字符将原样显示。Z 格式在使用 gmdate() 时总是返回 0。

Example#1 date() 例子


<?php
// 设定要用的默认时区。自 PHP 5.1 可用
date_default_timezone_set('UTC');


// 输出类似：Monday
echo date("l");

// 输出类似：Monday 15th of August 2005 03:12:46 PM
echo date('l dS \of F Y h:i:s A');

// 输出：July 1, 2000 is on a Saturday
echo "July 1, 2000 is on a " . date("l", mktime(0, 0, 0, 7, 1, 2000));

/* 在格式参数中使用常量 */
// 输出类似：Mon, 15 Aug 2005 15:12:46 UTC
echo date(DATE_RFC822);

// 输出类似：2000-07-01T00:00:00+00:00
echo date(DATE_ATOM, mktime(0, 0, 0, 7, 1, 2000));
?>

在格式字串中的字符前加上反斜线来转义可以避免它被按照上表解释。如果加上反斜线后的字符本身就是一个特殊序列，那还要转义反斜线。

Example#2 在 date() 中转义字符


<?php
// prints something like: Wednesday the 15th
echo date("l \\t\h\e jS");
?>

可以把 date() 和 mktime() 结合使用来得到未来或过去的日期。

Example#3 date() 和 mktime() 例子


<?php
$tomorrow  = mktime(0, 0, 0, date("m")  , date("d")+1, date("Y"));
$lastmonth = mktime(0, 0, 0, date("m")-1, date("d"),   date("Y"));
$nextyear  = mktime(0, 0, 0, date("m"),   date("d"),   date("Y")+1);
?>

Note: 由于夏令时的缘故，这种方法比简单地在时间戳上加减一天或者一个月的秒数更可靠。

一些使用 date() 格式化日期的例子。注意要转义所有其它的字符，因为目前有特殊含义的字符会产生不需要的结果，而其余字符在 PHP 将来的版本中可能会被用上。当转义时，注意用单引号以避免类似 \n 的字符变成了换行符。

Example#4 date() 格式举例


<?php
// 假定今天是：March 10th, 2001, 5:16:18 pm
$today = date("F j, Y, g:i a");                 // March 10, 2001, 5:16 pm
$today = date("m.d.y");                         // 03.10.01
$today = date("j, n, Y");                       // 10, 3, 2001
$today = date("Ymd");                           // 20010310
$today = date('h-i-s, j-m-y, it is w Day z ');  // 05-16-17, 10-03-01, 1631 1618 6 Fripm01
$today = date('\i\t \i\s \t\h\e jS \d\a\y.');   // It is the 10th day.
$today = date("D M j G:i:s T Y");               // Sat Mar 10 15:16:08 MST 2001
$today = date('H:m:s \m \i\s\ \m\o\n\t\h');     // 17:03:17 m is month
$today = date("H:i:s");                         // 17:16:17
?>

要格式化其它语种的日期，应该用 setlocale() 和 strftime() 函数来代替 date()。

参见 getlastmod()，gmdate()，mktime()，strftime() 和 time()。

getdate

date_timezone_set

Last updated: Sun, 25 Nov 2007

add a note User Contributed Notes
date

sourabhshankar AT gmail DOT com
14-Nov-2008 12:43


<?php

/*

Find out start and end date of current week.

I am assuming that week starts at sunday and ends at saturday.

so a typical week will look like this: sun,mon,tue,wed,thu,fri,sat

if you find any bug/error, please email me.

*/



//sunday = start of week

$sat = 6; //saturday = end of week

$current_day=date('w');

$days_remaining_until_sat = $sat - $current_day;



$ts_start = strtotime("-$current_day days");

$ts_end = strtotime("+$days_remaining_until_sat days");



echo date('m-d-Y',$ts_start); //start date

echo '<br>';

echo date('m-d-Y',$ts_end); //end date



/*

OUTPUT (m-d-y):

11-09-2008

11-15-2008

*/

?>

tchapin at gmail dot com
09-Nov-2008 10:26


<?php


    // Function used to take two date strings, and returns an associative array


    // with different formats for the difference between the dates.


    // --------------------


    // Variables:


    // StartDateString (String - MM/DD/YYYY)


    // EndDateString (String - MM/DD/YYYY)


    // --------------------


    // Example: $DateDiffAry = GetDateDifference('01/09/2008', '02/11/2009');


    // print_r($DateDiffAry);


    // --------------------


    // Returns Something Like:


    /*    


    Array


    (


        [YearsSince] => 1.0931506849315


        [MonthsSince] => 13.117808219178


        [DaysSince] => 399


        [HoursSince] => 9576


        [MinutesSince] => 574560


        [SecondsSince] => 34473600


        [NiceString] => 1 year, 1 month, and 2 days


        [NiceString2] => Years: 1, Months: 1, Days: 2


    )


    */





    function GetDateDifference($StartDateString=NULL, $EndDateString=NULL) {


        $ReturnArray = array();


        


        $SDSplit = explode('/',$StartDateString);


        $StartDate = mktime(0,0,0,$SDSplit[0],$SDSplit[1],$SDSplit[2]);


        


        $EDSplit = explode('/',$EndDateString);


        $EndDate = mktime(0,0,0,$EDSplit[0],$EDSplit[1],$EDSplit[2]);


        


        $DateDifference = $EndDate-$StartDate;


        


        $ReturnArray['YearsSince'] = $DateDifference/60/60/24/365;


        $ReturnArray['MonthsSince'] = $DateDifference/60/60/24/365*12;


        $ReturnArray['DaysSince'] = $DateDifference/60/60/24;


        $ReturnArray['HoursSince'] = $DateDifference/60/60;


        $ReturnArray['MinutesSince'] = $DateDifference/60;


        $ReturnArray['SecondsSince'] = $DateDifference;





        $y1 = date("Y", $StartDate);


        $m1 = date("m", $StartDate);


        $d1 = date("d", $StartDate);


        $y2 = date("Y", $EndDate);


        $m2 = date("m", $EndDate);


        $d2 = date("d", $EndDate);


        


        $diff = '';


        $diff2 = '';


        if (($EndDate - $StartDate)<=0) {


            // Start date is before or equal to end date!


            $diff = "0 days";


            $diff2 = "Days: 0";


        } else {





            $y = $y2 - $y1;


            $m = $m2 - $m1;


            $d = $d2 - $d1;


            $daysInMonth = date("t",$StartDate);


            if ($d<0) {$m--;$d=$daysInMonth+$d;}


            if ($m<0) {$y--;$m=12+$m;}


            $daysInMonth = date("t",$m2);


            


            // Nicestring ("1 year, 1 month, and 5 days")


            if ($y>0) $diff .= $y==1 ? "1 year" : "$y years";


            if ($y>0 && $m>0) $diff .= ", ";


            if ($m>0) $diff .= $m==1? "1 month" : "$m months";


            if (($m>0||$y>0) && $d>0) $diff .= ", and ";


            if ($d>0) $diff .= $d==1 ? "1 day" : "$d days";


            


            // Nicestring 2 ("Years: 1, Months: 1, Days: 1")


            if ($y>0) $diff2 .= $y==1 ? "Years: 1" : "Years: $y";


            if ($y>0 && $m>0) $diff2 .= ", ";


            if ($m>0) $diff2 .= $m==1? "Months: 1" : "Months: $m";


            if (($m>0||$y>0) && $d>0) $diff2 .= ", ";


            if ($d>0) $diff2 .= $d==1 ? "Days: 1" : "Days: $d";


            


        }


        $ReturnArray['NiceString'] = $diff;


        $ReturnArray['NiceString2'] = $diff2;


        return $ReturnArray;


    }


    


    // Example:


    $DateDiffAry = GetDateDifference('01/09/2008', '02/11/2009');


    print_r($DateDiffAry);


    


?>

Grapsus
02-Nov-2008 03:38


Here's a small function which returns TRUE if European Summer Time is used (now or at a given date) :





<?php


if(!function_exists('estdst'))


{


  function estdst($ts=false)


  {


    $ts = $ts?$ts:time();


    $year = gmdate('Y', $ts);


    $end = gmmktime(1, 0, 0, 3, 31 - ((5 * $year) / 4 + 4)%7, $year);


    $start = gmmktime(1, 0, 0, 10, 31 - ((5 * $year) / 4 + 1)%7, $year);


    return $ts < $end || $ts > $start;


  }


}


?>





Calculation formula taken from here : http://en.wikipedia.org/wiki/European_Summer_Time

robertk113 at comcast dot net
31-Oct-2008 01:46


I need to display graphic-A during hours 1-9 and graphic-B during hours 10-24. Anybody know of a simple way to do this? Better yet, if we can select times based upon the day of the week, it would be even better!



I tried searching, but didn't inf anything resembling this. The coding will be added to a product description in osCommerce, which accepts html coding easily but other scripting types may or may not work. I want an OPEN graphic to display during normal business hours, and CLOSED when outside these hours.



Thanks in advance!

kyle renfrow
22-Oct-2008 06:41


i figured i would post this, it's only useful for systems dealing with UTC and EST, but could easily be modified to support multiple timezones. this function will tell you whether it's daylight saving time for the eastern timezone using UTC localtime:





<?php


//checks whether DST in EST using UTC


//can pass $time in unix timestamp, otherwise uses time()


function est_isdst($time=NULL){


  if(!$time) { $now = time(); }else { $now = $time; }


  if (


       $now > strtotime(date('Y-m-d 6:59:59', strtotime('next Sunday', strtotime(date('Y', $now).'-3-7')))) &&


       $now < strtotime(date('Y-m-d 6:00', strtotime('first Sunday', strtotime(date('Y', $now).'-11-0'))))


     ) { return true; }else { return false; }


}


?>





USAGE:


<?php


if(est_isdst()) { echo 'Its DST in EST Timezone!'; }


?>

adityabhai [at] gmail [dot] com
07-Oct-2008 02:56


Aditya Bhatt (adityabhai [at] gmail [dot] com):



I have one date, and i want the next day of that date:



<?php



echo date("D F d Y",strtotime("+1 days")); // Same applies for months e.g. "+1 months"



?>



I have one date, and i want the previous day of that date:



<?php



echo date("D F d Y",strtotime("-1 days")); // Same applies for months e.g. "-1 months"



?>

Kenneth Kin Lum
02-Oct-2008 03:52


date(DATE_RFC822) and date(DATE_RFC2822) both work.  note that RFC 822 is obsoleted by RFC 2822.  The main difference is the year being 08 in RFC 822 and is 2008 in RFC 2822.



To use date(DATE_RFC2822), a short form is date('r').

nick at nick-web dot co dot uk
25-Sep-2008 08:48


RE: wulf dot kaiser at mpimf-heidelberg dot mpg dot de code to work out fridays in a month. I noticed one small error. It looks like the 

<?php

if ($givenMonth != '12') {



    $nextGivenMonth = "1";

    $nextGivenYear = $givenYear + 1;}

?>

block was setting every month to 1 because it was not equal to 12. I changed that to <?php if ($givenMonth == '12') { ?>and now all is fine!



Now - to refine it so that it only shows Fridays on the 5th or after, until the 4th of the next month.. Damm UK tax stuff!



=)

N

Anonymous
24-Sep-2008 04:35


MySQL 5 will accept ISO_8601 encoded time, so it is acceptable to use date(ISO_8601)

Anonymous
12-Sep-2008 06:01


Correct format for a MySQL DATETIME column is

<?php $mysqltime = date ("Y-m-d H:i:s", $phptime); ?>

Cortexd
27-Aug-2008 11:47


a date function supporting the milliseconds format character



<?php

function udate($format, $utimestamp = null)

{

    if (is_null($utimestamp))

        $utimestamp = microtime(true);



    $timestamp = floor($utimestamp);

    $milliseconds = round(($utimestamp - $timestamp) * 1000000);



    return date(preg_replace('`(?<!\\\\)u`', $milliseconds, $format), $timestamp);

}



echo udate('H:i:s.u'); // 19:40:56.78128

echo udate('H:i:s.u', 654532123.04546); // 16:28:43.45460

?>

pdubbb1 at gmail dot com
26-Aug-2008 05:32


here is the simpliest way to get the start and end date of the week;





<?php


$sdate=date('c',strtotime(date('Y')."W".date('W')."0"));





$edate=date('c',strtotime(date('Y')."W".date('W')."7"));


?>





the format is for the string in strtotime is;


  


     2008W200





this stands for year - 2008, constant never changes - W, week number of the year - 20, day of the week - 0 for sunday, 1 for monday, etc....





so 2008W200 stands for the sunday of the 20th week of 2008.  





This will only work in php 5 or better

abazaba.ru
14-Aug-2008 03:53


All novices must be very carefull when working with timestamps as second values.

From first glance it looks like date("Y-m-d H:i:s",TIMESTAMP) will return correct date, based on "how much seconds gone from 1970".

But here is the feature, it'll be corrected time, according to LOCAL timezone.



So if you take a 25200 as timestamp (10 hours), 

then on one server you'll get 

1970-01-01 08:00:00 

and on other server you'll get 

1970-01-01 09:00:00 

and so on.

Though you could expect 1970-01-01 10:00:00 in all cases, because if 25200 seconds gone from 1970-01-01 00:00:00 it obviously have to be 1970-01-01 10:00:00



I spend today 3 hours to correct scripts which were created with such error by previous programmer, so please, guys, don't make me work like this and remember about conversation to LOCAL time.

phprocks at aol dot com
06-Aug-2008 11:25


Try this for finding the difference in days between 2 dates/datetimes... take note though, date_parse requires PHP version 5.1.3 or higher.





<?php


/**


 * Finds the difference in days between two calendar dates.


 *


 * @param Date $startDate


 * @param Date $endDate


 * @return Int


 */


function dateDiff($startDate, $endDate)


{


    // Parse dates for conversion


    $startArry = date_parse($startDate);


    $endArry = date_parse($endDate);





    // Convert dates to Julian Days


    $start_date = gregoriantojd($startArry["month"], $startArry["day"], $startArry["year"]);


    $end_date = gregoriantojd($endArry["month"], $endArry["day"], $endArry["year"]);





    // Return difference


    return round(($end_date - $start_date), 0);


}


?>

JonathanCross.com
25-Jul-2008 01:22


<?php


// A demonstration of the new DateTime class for those


// trying to use dates before 1970 or after 2038.


?>


<h2>PHP 2038 date bug demo (php version <?php echo phpversion(); ?>)</h1>


<div style='float:left;margin-right:3em;'>


<h3>OLD Buggy date()</h3>


<?php


  $format='F j, Y';


  for ( $i = 1900; $i < 2050; $i++) {


    $datep = "$i-01-01";


    ?>


    Trying: <?php echo $datep; ?> = <?php echo date($format, strtotime($datep)); ?><br>


    <?


  }


?></div>


<div style='float:left;'>


  <h3>NEW DateTime Class (v 5.2+)</h3><?php


  for ( $i = 1900; $i < 2050; $i++) {


    $datep = "$i-01-01";


    $date = new DateTime($datep);


    ?>


    Trying: <?php echo $datep; ?> = <?php echo $date->format($format); ?><br>


    <?


  }


?></div>

Rob A.
10-Jul-2008 09:38


Quick function for returning the names of the next 7 days of the week starting with today.



Returns an array that can be formatted to your liking.



<?php

/**

* Returns array of next 7 days starting with today

*

*/



function next_7_days() {

        // create array of day names. You can change these to whatever you want

    $days = array(

                            'Monday',

                            'Tuesday',

                            'Wednesday',

                            'Thursday',

                            'Friday',

                            'Saturday',

                            'Sunday');

    $today = date('N'); 

    for ($i=1;$i<$today;$i++) {



                // take the first element off the array

        $shift = array_shift($days);



                // ... and add it to the end of the array

        array_push($days,$shift);

    }

        // returns the sorted array

    return $days;

}

?>



It basically takes an array starting with Monday and shifts each day to the end of the array until the first element in the array is today.

con_tobe at yahoo dot com
09-Jul-2008 08:46


Doing $w-- for months ending on Sat won't hurt (i.e. if you're counting weeks as is the case below), but halocastle's code is perfectly fine as is and quite fast.  He/she uses $w as a key for the $weeks array.  "Halo" does this BEFORE $w++, so $w-- is superfluous as the loop has already ended.  For May, 2008, I get 5 weeks as expected...





Array


(


    [1] => Array


        (


            [4] => 1


            [5] => 2


            [6] => 3


        )





    [2] => Array


        (


            [0] => 4


            [1] => 5





------------OMITTED-----------------





            [4] => 22


            [5] => 23


            [6] => 24


        )





    [5] => Array


        (


            [0] => 25


            [1] => 26


            [2] => 27


            [3] => 28


            [4] => 29


            [5] => 30


            [6] => 31


        )





)





I guess the one pit-fall of the code is if you overlap months, say the following year, then $m-- makes perfect since...I think (haven't gotten that far...yet).





I modified "Halo's" code to include months, too (this is from a snippet that produces a three month calendar, hence the outer $months loop, omitted here).





<?php


$m = date('m');


$Y = date('Y');





// for() {months loop omitted


$var_date = mktime(0, 0, 0, $m, 1, $Y);


$month_name = date('F', $var_date);


$months[$month_name]['DAYS'] = date('t', $var_date);


$months[$month_name]['FIRST_DAY'] = date('w', $var_date);


//}


foreach($months as $month => $key) {


  $weeks = array();


  for($i = 1, $j = $key['FIRST_DAY'], $w = 1;$i <= $key['DAYS'];$i++) {


    $weeks[$w][$j] = $i;


    $j++;


    if($j == 7) {


      $j = 0;


      $w++;


    }


  }


  $months[$month]['WEEKS'] = $weeks;


}


?>





Enjoy!

dmagick at gmail dot com
02-Jul-2008 07:44


Slight amendment to halocastle at yahoo dot com 's code as it doesn't take into account when a month finishes on a Saturday (eg May 2008).





<?php


$start_date = mktime(0, 0, 0,$start_month, 1, $start_year);





$days_in_month = date('t', $start_date);


$month_first_day = date('w', $start_date);





$j = $month_first_day;


$num_weeks = 1;





for($i = 1; $i <= $days_in_month; $i++) {


    $j++;


    if($j == 7) {


        $j = 0;


        $num_weeks++;


    }


}





// if the last day of the month happens to be a Saturday,


// take one off the number of weeks


// because it was being added inside the for loop.


if ($j == 0) {


    $num_weeks--;


}


?>

halocastle at yahoo dot com
30-Jun-2008 09:20


Weeks and days for any month/year combo:





<?php


$m = 2; // February


$Y = 2008;





// constants used here for legibility, use $vars for dynamicon...


define('MONTH_DAYS',date('t', strtotime(date($m . '/01/' . $Y))));


// w:0->6 = Sun->Sat


define('MONTH_FIRST_DAY',date('w', strtotime(date($m . '/01/' . $Y))));





for($i = 1, $j = MONTH_FIRST_DAY, $w = 1;$i <= MONTH_DAYS;$i++) {


  $week[$w][$j] = $i;


  $j++;


  if($j == 7) {


    $j = 0;


    $w++;


  }


}


?>





print_r($week):


-----------------------


Array


(


    [1] => Array


        (


            [5] => 1


            [6] => 2


        )





    [2] => Array


        (


            [0] => 3


            [1] => 4


            [2] => 5


            [3] => 6


            [4] => 7


            [5] => 8


            [6] => 9


        )





    [3] => Array


        (


            [0] => 10


            [1] => 11


            [2] => 12


            [3] => 13


            [4] => 14


            [5] => 15


            [6] => 16


        )





    [4] => Array


        (


            [0] => 17


            [1] => 18


            [2] => 19


            [3] => 20


            [4] => 21


            [5] => 22


            [6] => 23


        )





    [5] => Array


        (


            [0] => 24


            [1] => 25


            [2] => 26


            [3] => 27


            [4] => 28


            [5] => 29


        )





)

Kavi Siegel
29-Jun-2008 07:18


I wrote the following function to show a series of drop down boxes to select the date. When provided with a timestamp, that date is selected by default, when none is provided, the current date is selected.





<?php


function chooseDate($timestamp = ""){


    if($timestamp == ""){


        $timestamp = time();


    }


    $months = array(null, 'Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec');


    unset($months[0]);


    print_r($months);


    $out = '<select name="month">';


    foreach($months as $key => $month){


        if($month == date('M', $timestamp)){


            $out .= '<option value="'.$key.'" selected="selected">'.$month.'</option>';


        }else{


            $out .= '<option value="'.$key.'">'.$month.'</option>';


        }


    }


    $out .= '</select><select name="days">';


    for($i = 1; $i <= 32; $i++){


        if($i == date('j', $timestamp)){


            $out .= '<option value="'.$i.'" selected="selected">'.$i.'</option>';


        }else{


            $out .= '<option value="'.$i.'">'.$i.'</option>';


        }


    }


    $out .= "</select><select name='year'>";


    for($i = date('Y'); $i >= 1970; $i--){


        if($i == date('Y', $timestamp)){


            $out .= '<option value="'.$i.'" selected="selected">'.$i.'</option>';


        }else{


            $out .= '<option value="'.$i.'">'.$i.'</option>';


        }


    }


    $out .= "</select>";


    return $out;


}


?>





Usage is simple:





<?php


echo chooseDate(); // Will select current date


echo chooseDate(1149566400); // Will select June 6th, 2006


?>

aplarsen
26-Jun-2008 01:12


@anonymous (12-Jun-2008 08:45):

date("t") returns the last day of the month, not the last working day of the month.



A cleaner example would be as follows:

<?php

function lastworkingday($date)

{    

   for($lastday=mktime(0,0,0,date("m",$date),

       date("t",$date),date("Y",$date)); 

     date("w",$lastday)==0 || date("w",$lastday)==6; 

     $lastday-=60*60*24);

   return date("j",$lastday);

}

?>

kontakt at arthur minus schiwon dot de
18-Jun-2008 03:29


to get the week of the month simply use:

ceil( date("j") / 7 );

diego at diego dot eng dot br
09-Jun-2008 04:27


I made a small code to get the last working day of the month:



<?php



$times = strtotime(date("Y")."-".date("m")."-".date("t"));

for ($lastworkingday=0;$lastworkingday==0;$times-=86400)

   if (date("w",$times)!=0 && date("w",$times)!=6) $lastworkingday = date("j",$times);

print $lastworkingday;



?>

phil dot taylor at enilsson dot com
25-May-2008 10:37


Found this helpful when converting unix dates for use with the ical file format.





<?php


// Converts a unix timestamp to iCal format (UTC) - if no timezone is 


// specified then it presumes the uStamp is already in UTC format.


// tzone must be in decimal such as 1hr 45mins would be 1.75, behind 


// times should be represented as negative decimals 10hours behind


// would be -10


        


    function unixToiCal($uStamp = 0, $tzone = 0.0) {


    


        $uStampUTC = $uStamp + ($tzone * 3600);        


        $stamp  = date("Ymd\THis\Z", $uStampUTC);


        


        return $stamp;        





    }


?>

chubby at chicks dot com
23-May-2008 06:54


<?php


/**


     * Checks wether a date is between an interval


     *


     * Usage:


     *      


     * // check if today is older than 2008/12/31


     * var_dump(currentDayIsInInterval('2008/12/31'));


     * // check if today is younger than 2008/12/31


     * var_dump(currentDayIsInInterval(null,'2008/12/31'));


     * // check if today is between 2008/12/01 and 2008/12/31


     * var_dump(currentDayIsInInterval('2008/12/01','2008/12/31'));  


     * 


     * Will trigger errors if date is in wrong format, notices if $begin > $end     


     *          


     * @param string $begin Date string as YYYY/mm/dd


     * @param string $end Date string as YYYY/mm/dd


     * @return bool  


     */


function currentDayIsInInterval($begin = '',$end = '')


{


        $preg_exp = '"[0-9][0-9][0-9][0-9]/[0-9][0-9]/[0-9][0-9]"';


        $preg_error = 'Wrong parameter passed to function '.__FUNCTION__.' : Invalide date


format. Please use YYYY/mm/dd.';


        $interval_error = 'First parameter in '.__FUNCTION__.' should be smaller than


second.';


        if(empty($begin))


        {


                $begin = 0;


        }


        else


        {


                if(preg_match($preg_exp,$begin))


                {


                        $begin = (int)str_replace('/','',$begin);


                }


                else


                {


                        trigger_error($preg_error,E_USER_ERROR);


                }


        }


        if(empty($end))


        {


                $end = 99999999;


        }


        else


        {


                if(preg_match($preg_exp,$end))


                {


                        $end = (int)str_replace('/','',$end);


                }


                else


                {


                        trigger_error($preg_error,E_USER_ERROR);


                }


        }