You should destroy the $img too...
So it would be :
$img = @imagecreatefromjpeg("http://www.mysite.com/my_image.jpg");
if ($img) {
$img_height = imagesy($img);
ImageDestroy($img);
}
echo "My height is " . $img_height;
imagesy
(PHP 4, PHP 5)
imagesy — 取得图像高度
说明
int imagesy
( resource
$image
)
imagesy() 返回
image 所代表的图像的高度。
Example #1 使用 imagesy()
<?php
// create a 300*200 image
$img = imagecreatetruecolor(300, 200);
echo imagesy($img); // 200
?>
BSE_Icheb at hotmail dot com
20-Jun-2003 04:13
boo at php dot net
13-Aug-2002 11:01
To use this function notice that 'image' parameter it's a RESOURCE and NOT an Image File Path !
Here comes an exemple:
$img = @imagecreatefromgif("http://www.mysite.com/my_imag.gif");
if ($img) $img_height = imagesy($img);
echo "My height is " . $img_height;
