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imagechar> <imageantialias
Last updated: Fri, 14 Aug 2009

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imagearc

(PHP 4, PHP 5)

imagearcDessine une ellipse partielle

Description

bool imagearc ( resource $image , int $cx , int $cy , int $width , int $height , int $start , int $end , int $color )

imagearc() dessine une ellipse partielle, centrée sur les coordonnées fournies.

Liste de paramètres

image

Une ressource d'image, retourné par une des fonctions de création d'images, comme imagecreatetruecolor().

cx

X : coordonnée du centre.

cy

Y : coordonnée du centre.

width

La largeur de l'ellipse.

height

La hauteur de l'ellipse.

start

L'angle de début de l'ellipse, en degrés.

end

L'angle de fin de l'ellipse, en degrés. 0° correspond à la position "trois heures" et l'ellipse est dessiné dans le sens des aiguilles d'une montre.

color

Un identifiant de couleur, créé par la fonction imagecolorallocate().

Valeurs de retour

Cette fonction retourne TRUE en cas de succès, FALSE en cas d'échec.

Exemples

Exemple #1 Dessine d'un cercle avec imagearc()

<?php

// Création d'une image 200*200
$img imagecreatetruecolor(200200);

// Allocation de couleurs
$white imagecolorallocate($img255255255);
$red   imagecolorallocate($img255,   0,   0);
$green imagecolorallocate($img,   0255,   0);
$blue  imagecolorallocate($img,   0,   0255);

// Dessine la tête
imagearc($img100100200200,  0360$white);
// La bouche
imagearc($img10010015015025155$red);
// les yeux gauche et droit
imagearc($img,  60,  75,  50,  50,  0360$green);
imagearc($img140,  75,  50,  50,  0360$blue);

// Affichage au navigateur
header("Content-type: image/png");
imagepng($img);

// Libération de la mémoire
imagedestroy($img);

?>

L'exemple ci-dessus va afficher quelque chose de similaire à :

Voir aussi



imagechar> <imageantialias
Last updated: Fri, 14 Aug 2009
 
add a note add a note User Contributed Notes
imagearc
mojiro at awmn dot net
13-Dec-2005 08:28
A previous for the Rotated (Filled)Ellipse note from(nojer2 at yahoo dot com, 02-Apr-2001 12:06) has a mistake, at the second arc. Replace them with the following listing.

if ($filled) {
    triangle($im, $cx, $cy, $cx+$px, $cy+$py, $cx+$x, $cy+$y, $colour);
    triangle($im, $cx, $cy, $cx-$px, $cy-$py, $cx-$x, $cy-$y, $colour);
} else {
    imageline($im, $cx+$px, $cy+$py, $cx+$x, $cy+$y, $colour);
    imageline($im, $cx-$px, $cy-$py, $cx-$x, $cy-$y, $colour);
}
ruturaj_v at yahoo dot com
17-May-2004 01:32
this is another piechart eg. very simple ...

<?php
global $deg;

function
get_polar($xrel, $yrel, $ang, $radius) {
   
$i = $ang;
   
$ang = ($ang * pi())/ 180;
   
   
$ix = abs($radius*cos($ang));
   
$iy = abs($radius*sin($ang));
   
    if (
$i>=0 && $i<=90) {
       
$ix = $xrel + $ix;
       
$iy = $yrel - $iy;
    }
    if (
$i>90 && $i<=180) {
       
$ix = $xrel - $ix;
       
$iy = $yrel - $iy;
    }
    if (
$i>180 && $i<=270) {
       
$ix = $xrel - $ix;
       
$iy = $yrel + $iy;
    }
    if (
$i>270 && $i<=360) {
       
$ix = $xrel + $ix;
       
$iy = $yrel + $iy;
    }

   
$ix = floor($ix);
   
$iy = floor($iy);
   
//echo ($ix . " $iy<br>");
   
$returnvals = array (
                       
'x1' => $xrel,
                       
'y1' => $yrel,
                       
'x2' => $ix,
                       
'y2' => $iy
                       
);
    return
$returnvals;
}

function
get_degtotal($degindex)
{
    global
$deg;
    if (
$degindex == 0 ) {
       return ( 
$deg[$degindex] );
    }
    else {       
        return (
$deg[$degindex] + get_degtotal($degindex-1) );
    }   
}

$im  = imagecreate (400, 400);
$w   = imagecolorallocate ($im, 255, 255, 255);
$black   = imagecolorallocate ($im, 0, 0, 0);
$red = imagecolorallocate ($im, 255, 0, 0);
$green = imagecolorallocate ($im, 0, 180, 0);

$randcolor[0] = imagecolorallocate($im, 243, 54, 163);
$randcolor[1] = imagecolorallocate($im, 179, 51, 247);
$randcolor[2] = imagecolorallocate($im, 103, 48, 250);
$randcolor[3] = imagecolorallocate($im, 53, 145, 244);
$randcolor[4] = imagecolorallocate($im, 54, 243, 243);
$randcolor[5] = imagecolorallocate($im, 107, 245, 180);
$randcolor[6] = imagecolorallocate($im, 203, 242, 111);
$randcolor[7] = imagecolorallocate($im, 248, 201, 105);

$data[0] = 30;
$data[1] = 20;
$data[2] = 15;
$data[3] = 10;
$data[4] = 8;
$data[5] = 7;
$data[6] = 5;
$data[7] = 5;

$datasum = array_sum($data);

$deg[0] = number_format((30 / $datasum * 360), 2, ".", "");
$deg[1] = number_format((20 / $datasum * 360), 2, ".", "");
$deg[2] = number_format((15 / $datasum * 360), 2, ".", "");
$deg[3] = number_format((10 / $datasum * 360), 2, ".", "");
$deg[4] = number_format((8 / $datasum * 360), 2, ".", "");
$deg[5] = number_format((7 / $datasum * 360), 2, ".", "");
$deg[6] = number_format((5 / $datasum * 360), 2, ".", "");
$deg[7] = number_format((5 / $datasum * 360), 2, ".", "");
echo (
'<pre>');

//print_r($deg);

$datadeg = array();
$datapol = array();
$degbetween = array();
$databetweenpol = array();

for (
$i=0; $i < count($deg) ; $i++) {
   
$datadeg[$i] = get_degtotal($i);
   
$datapol[$i] = get_polar(200, 200, $datadeg[$i], 100);
}

for (
$i=0; $i < count($datadeg) ; $i++) {
   
/*this is a trick where you take 2deg angle before
    and get the smaller radius so that you can have a pt to
    `imagefill` the chartboundary
    */
   
$degbetween[$i] = ($datadeg[$i]-2);
   
$databetweenpol[$i] = get_polar(200, 200, $degbetween[$i], 50);
}

print_r($datadeg);
print_r($degbetween);
print_r($databetweenpol);
//exit;

for ($i=0; $i<count($deg); $i++) {
   
imageline ($im, 200, 200, $datapol[$i]['x2'], $datapol[$i]['y2'], $black);
}
imagearc($im, 200, 200, 200, 200, 0, 360, $black);

for (
$i=0; $i<count($deg); $i++) {
   
imagefill ($im, $databetweenpol[$i]['x2'], $databetweenpol[$i]['y2'], $randcolor[$i]);

}

//header ("Content-type: image/png");
imagepng($im, 'piechart.png');
?>
<img src='piechart.png'>
jerryscript at aol dot com
26-Dec-2003 10:05
[note-Apache/1.3.29 (Win32) PHP/4.3.4]

The imagearc (and imageellipse) functions do not accept line thicknesses when drawn from 0 to 360 degrees.

Drawing from 0 to 359 and again from 359 to 360 does create an ellipse with the current line thickness.

Jerry
eamon at hostelworld dot com
17-Dec-2003 03:24
Right...
possibly the easiest way of drawing a filled circle:
Loop through the imagearc function incrementing the diameter by one pixel:
<?
 // --- code fragment --- //

for($i=1; $i<$Diameter; $i++){
  imagearc($Image, $CenterX, $CenterY, $i, $i, $Start, $End, $Color);
}

// --------------------- //

?>

This works great for circles with diameters up to about 60 or 70 pixels wide. After that, you start to get pixle gaps.
logang at deltatee dot com
05-Aug-2003 03:19
Heres a function to make a curve between two points... This will be a downward curve but it wouldn't be hard to make a similar function to make an upward curve. The first point has to be to the left of the second point ($x1 < $x2), and height is actually backwards. The larger height is the less of a crest the curve has. I imagine with a few modifications this functions could make upward curves as well.

function ImageCurveDown ($image, $x1, $y1, $x2, $y2, $height, $color) {
    $presicion = 1;

    for ($left = ($x1-$x2); $left < 0; $left++){
        if ($y1 < $y2) {
            $cy = $y2 + $height;
            $cx = $x1 - $left;
        } else {
            $cy = $y1 + $height;
            $cx = $x2 + $left;
        }
        $nx1 = abs($x1 - $cx);
        $ny1 = abs($y1 - $cy);
        $nx2 = abs($x2 - $cx);
        $ny2 = abs($y2 - $cy);

        if ($y1 < $y2) {
            if ($nx2 == 0 || $ny1 == 0) continue;
            $angle1 = atan($height/$nx2);
            $A1 = $nx2/cos ($angle1);
            $B1 = $ny2/sin ($angle1);
            $angle2 = pi()/2 +atan($left/$ny1);
            $A2 = $nx1/cos ($angle2);
            $B2 = $ny1/sin ($angle2);
        } else {
            if ($ny2 == 0 || $nx1 == 0) continue;
            $angle1 = atan($ny2/$nx2);
            $A1 = abs($nx2/cos ($angle1));
            $B1 = abs($ny2/sin ($angle1));
            $angle2 = atan($height/$nx1);
            $A2 = abs ($nx1/cos ($angle2));
            $B2 = abs($ny1/sin ($angle2));
        }

        if (abs($A1 - $A2) < $presicion && abs ($B1 - $B2) < $presicion) {
            ImageArc($image, $cx, $cy, $A1*2, $B1*2, 180+rad2deg($angle2), 360-rad2deg($angle1), $color);
        }
    }
}
23-Jan-2003 04:55
Please note that in order to draw a complete circle or ellipse (without using the imageellipse) you mustn't use 0° for both s and e. If you do this you will get, umm, nothing. Instead set s to 0° and e to 360° to get a complete circle or ellipse.
jinny at 263 dot net
14-May-2002 05:27
imagesetstyle() sets the style to be used by all line drawing functions when drawing with the special color .

Here goes a example of drawing a dashed-line circle.enjoy!

<?php

header
("Content-type: image/jpeg");
$im = imagecreate(100,100);

$b   = imagecolorallocate ($im, 0, 0, 0);
$w   = imagecolorallocate ($im, 255, 255, 255);

$style = array ($b,$b,$b,$b,$b,$w,$w,$w,$w,$w);

imagesetstyle ($im, $style);

imagearc($im,50,50,100,100,0,360,IMG_COLOR_STYLED);

imagejpeg($im);
imagedestroy($im);
?>
arve at skogvold dot as
30-Nov-2001 09:04
I found a better way for drawing a pie chart:

header ("Content-type: image/png");
$diameter = 100;
$radius = $diameter / 2;
$centerX = $radius;
$centerY = $radius;

$im = @ImageCreate ($diameter, $diameter)
    or die ("Cannot Initialize new GD image stream");

$background = ImageColorAllocate ($im, 0, 0, 0);
$red = ImageColorAllocate ($im, 176, 0, 0);

function fill_arc($start, $end, $color) {
    global $diameter, $centerX, $centerY, $im, $radius;
    imagearc($im, $centerX, $centerY, $diameter, $diameter, $start, $end, $color);
    imageline($im, $centerX, $centerY, $centerX + cos(deg2rad($start)) * $radius, $centerY + sin(deg2rad($start)) * $radius, $color);
    imageline($im, $centerX, $centerY, $centerX + cos(deg2rad($end)) * $radius, $centerY + sin(deg2rad($end)) * $radius, $color);
    imagefill ($im,$centerX + $radius * 0.5 *cos(deg2rad($start+($end-$start)/2)), $centerY + $radius * 0.5 * sin(deg2rad($start+($end-$start)/2)), $color);
    }


fill_arc(0,30,$red);
// Will make a red filled arc, starting at 0 degrees, ending at 30 degrees

ImagePng ($im);
marc at resiteit dot com
08-Nov-2001 09:04
Round cornered anti-aliased dynamically sized button.

$w=40;
$h=20;
$im = ImageCreate($w,$h);
$white=ImageColorAllocate($im,255,255,255);
ImageFilledRectangle($im,0,0,$w,$h,$white);
imagecolortransparent ($im, $white);
ImageTTFText ($im, $h+ceil($h/3)+1, 0, -1, $h-1, $col1, "arialbd.ttf", "O");
ImageTTFText ($im, $h+ceil($h/3)+1, 0, $w-$h, $h-1, $col1, "arialbd.ttf", "O");
ImageTTFText ($im, $h+ceil($h/3)+1, 0, 1, $h-1, $col1, "arialbd.ttf", "O");
ImageTTFText ($im, $h+ceil($h/3)+1, 0, $w-$h-2, $h-1, $col1, "arialbd.ttf", "O");
$points=array(
    1,round($h/2),
    round($h/4),$h-round($h/4),
    round($h/2),$h,
    $w-(round($h/2)),$h,
    $w-(round($h/4)),$h-round($h/4),
    $w-2,round($h/2),
    $w-round($h/4),round($h/4),
    $w-round($h/2),0,
    round($h/2),0,
    round($h/4),round($h/4)
);
imagefilledpolygon ($im, $points, 10, $col1);

header("content-type: image/gif");
header("Content-Disposition: filename=name.gif");
ImageGif($im);
ImageDestroy($im);
foripepe at yahoo dot com
02-Sep-2001 04:56
To fill an arc (DiameterX != DiameterY):

<?
function imagefilledarc($Image, $CenterX, $CenterY, $DiameterX, $DiameterY, $Start, $End, $Color) {
    // To draw the arc
    imagearc($Image, $CenterX, $CenterY, $DiameterX, $DiameterY, $Start, $End, $Color);
    // To close the arc with 2 lines between the center and the 2 limits of the arc
    $x = $CenterX + (cos(deg2rad($Start))*($DiameterX/2));
    $y = $CenterY + (sin(deg2rad($Start))*($DiameterY/2));
    imageline($Image, $x, $y, $CenterX, $CenterY, $Color);
    $x = $CenterX + (cos(deg2rad($End))*($DiameterX/2));
    $y = $CenterY + (sin(deg2rad($End))*($DiameterY/2));
    imageline($Image, $x, $y, $CenterX, $CenterY, $Color);
    // To fill the arc, the starting point is a point in the middle of the closed space
    $x = $CenterX + (cos(deg2rad(($Start+$End)/2))*($DiameterX/4));
    $y = $CenterY + (sin(deg2rad(($Start+$End)/2))*($DiameterY/4));
    imagefilltoborder($Image, $x, $y, $Color, $Color);
}
?>

To close the arc with 2 lines (DiameterX != DiameterY):

<?
function imagenofilledarc($Image, $CenterX, $CenterY, $DiameterX, $DiameterY, $Start, $End, $Color) {
    // To draw the arc
    imagearc($Image, $CenterX, $CenterY, $DiameterX, $DiameterY, $Start, $End, $Color);
    // To close the arc with 2 lines between the center and the 2 limits of the arc
    $x = $CenterX + (cos(deg2rad($Start))*($DiameterX/2));
    $y = $CenterY + (sin(deg2rad($Start))*($DiameterY/2));
    imageline($Image, $x, $y, $CenterX, $CenterY, $Color);
    $x = $CenterX + (cos(deg2rad($End))*($DiameterX/2));
    $y = $CenterY + (sin(deg2rad($End))*($DiameterY/2));
    imageline($Image, $x, $y, $CenterX, $CenterY, $Color);
}
?>

An example:
<?
    $destImage = imagecreate( 216, 152 );
    $c0 = imagecolorallocate( $destImage, 0, 255, 255 );
    $c1 = imagecolorallocate( $destImage, 0, 0, 0 );
    $c2 = imagecolorallocate( $destImage, 255, 0, 0 );
    ImageFilledRectangle ( $destImage, 0, 0, 216, 152, $c0 );
    imagefilledarc( $destImage, 108, 76, 180, 80, 0, 130, $c1 );
    imagenofilledarc( $destImage, 108, 76, 180, 80, 0, 130, $c2 );
    header("content-type: image/PNG");
    ImagePNG( $destImage );
    ImageDestroy( $destImage );
?>
09-Apr-2001 05:37
The following site contains heaps of different functions to draw graphs with easy to follow code for newbies and heaps of examples with OVER 60 different predefined graphs
http://www.aditus.nu/jpgraph/index.php
nojer2 at yahoo dot com
01-Apr-2001 09:18
Here's a dashed circle function:

<?php
function dashedcircle($im, $cx, $cy, $radius, $colour, $dashsize=5) {

  
$dash=false;
   for (
$angle=0; $angle<=(180+$dashsize); $angle+=$dashsize) {
     
$x = ($radius * cos(deg2rad($angle)));
     
$y = ($radius * sin(deg2rad($angle)));

      if (
$dash) {
        
imageline($im, $cx+$px, $cy+$py, $cx+$x, $cy+$y, $colour);
        
imageline($im, $cx-$px, $cx-$py, $cx-$x, $cy-$y, $colour);
      }
     
$dash=!$dash;
     
$px=$x;
     
$py=$y;
   }
}
?>
nojer2 at yahoo dot com
01-Apr-2001 09:06
Here's the function to draw rotated ellipses again. This time I've optimised it a bit, fixed the no-fill bug, and used a 'squishratio' rather than a 'radiusmodifier', to make the curves perfect, so ignore my previous version.

<?php
function rotatedellipse($im, $cx, $cy, $width, $height, $rotateangle, $colour, $filled=true) {
  
$step=2;
  
$cosangle=cos(deg2rad($rotateangle));
  
$sinangle=sin(deg2rad($rotateangle));

  
$squishratio = $height/$width;
  
$nopreviouspoint = true;
   for (
$angle=0; $angle<=(180+$step); $angle+=$step) {
      
     
$ox = ($width * cos(deg2rad($angle)));
     
$oy = ($width * sin(deg2rad($angle))) * $squishratio;

     
$x =  + (($ox * $cosangle) - ($oy * $sinangle));
     
$y = $centrey + (($ox * $sinangle) + ($oy * $cosangle));
 
      if (
$nopreviouspoint) {
       
$px=$x;
       
$py=$y;
       
$nopreviouspoint=false;
      }

      if (
$filled) {
        
triangle($im, $cx, $cy, $cx+$px, $cy+$py, $cx+$x, $cy+$y, $colour);
        
triangle($im, $cx, $cy, $cx-$px, $cx-$py, $cx-$x, $cy-$y, $colour);
      } else {
        
imageline($im, $cx+$px, $cy+$py, $cx+$x, $cy+$y, $colour);
        
imageline($im, $cx-$px, $cx-$py, $cx-$x, $cy-$y, $colour);
      }
     
$px=$x;
     
$py=$y;
   }
}

function
triangle($im, $x1,$y1, $x2,$y2, $x3,$y3, $colour) {
  
$coords = array($x1,$y1, $x2,$y2, $x3,$y3);
  
imagefilledpolygon($im, $coords, 3, $colour);
}
?>
ericquil at yahoo dot com
29-Sep-2000 11:30
If circles overlap, a temporary border is needed when filling:
<?php
ImageArc
($im,$x,$y,$w,$h,0,360,$temp_color);
ImageFillToBorder($im,$x,$y,$temp_color,$fill_color);
ImageArc ($im,$x,$y,$w,$h,0,360,$fill_color);
?>
cbriou at orange-art dot fr
18-Sep-2000 02:03
There is another way to fill an arc :

<?php
// To draw the arc
$Color = imagecolorallocate($Image, $Red, $Green, $Blue);
imagearc($Image, $CenterX, $CenterY, $Diameter, $Diameter, $Start, $End, $Color);
// To close the arc with 2 lines between the center and the 2 limits of the arc
$x = $CenterX + (cos(deg2rad($Start))*($Diameter/2));
$y = $CenterY + (sin(deg2rad($Start))*($Diameter/2));
imageline($Image, $x, $y, $CenterX, $CenterY, $Color);
$x = $CenterX + (cos(deg2rad($End))*($Diameter/2));
$y = $CenterY + (sin(deg2rad($End))*($Diameter/2));
imageline($Image, $x, $y, $CenterX, $CenterY, $Color);
// To fill the arc, the starting point is a point in the middle of the closed space
$x = $CenterX + (cos(deg2rad(($Start+$End)/2))*($Diameter/4));
$y = $CenterY + (sin(deg2rad(($Start+$End)/2))*($Diameter/4));
imagefilltoborder($Image, $x, $y, $Color, $Color);
?>
timothyhouck at yahoo dot com
16-Aug-2000 10:58
To do filled arcs, try something like this:

<?php
$diameter
= 50;
imagearc($image, 25, 25, $diameter, $diameter, $start, $end, $color);
while(
$diameter > 0) {
 
imagearc($image, 25, 25, $diameter, $diameter, $start, $start + 1, $color);
 
imagearc($image, 25, 25, $diameter, $diameter, $end - 1, $end, $color);
 
$diameter--;
}
?>

...well you get the point.  It's a kludge, and *very* slow, but it's free.
travis at duluth dot com
23-Dec-1999 02:36
The wierd thing is that the first two integers tell where to place the "circle".
So for example I first create the "pallet" to place the circle on.
$image = imagecreate(500, 500); 
(this makes a huge 500x500 gif :) )
$colorBody = imagecolorallocate($image, 0, 0, 0);
(make the default color of the "pallet" black
$circleColor = imagecolorallocate($image, 255, 0, 255);
(going to make the circle an ugly pink color)
imagearc($image, 250, 250, 300, 300, 0, 360, $circleColor);
Places the image in the center (250,250) and the circle is 300 pixels in diameter.

Hope this helps.
 
Travis Kent Beste

imagechar> <imageantialias
Last updated: Fri, 14 Aug 2009
 
 
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