Generator::current

(PHP 5 >= 5.5.0, PHP 7, PHP 8)

Generator::current返回当前产生的值

说明

public Generator::current(): mixed

参数

此函数没有参数。

返回值

返回当前产生的值。

添加备注

用户贡献的备注 3 notes

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2
gib-o-master
2 years ago
current() advances untouched generator, same as next(), it makes the first step/iteration. the following calls will not.

non-yielded value will be NULL
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0
ctx2002 at gmail dot com
6 days ago
I think what "gib-o-master" said is wrong.
Generator::current method does not advances "untouched generator".

let me give an example:

function y1()
{
yield 1;
}

$g = y1();

if ($g->valid()) { //at this point, PHP outputs "valid"
echo "valid\n";
}

echo "current v:" . $g->current() . "\n"; //at this point, PHP outputs current v:1

if ($g->valid()) { //at this point, PHP still outputs "valid"
echo "valid\n";
} else {
echo "not valid\n";
}

if Generator::current method advances generator, then above If statement should outputs "not valid"
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0
mrsoftware73 at gmail dot com
6 years ago
<?php
function gen_one_to_three() {
for (
$i = 1; $i <= 3; $i++) {
// Note that $i is preserved between yields.
yield $i;
}
}

$generator = gen_one_to_three();
foreach (
$generator as $value) {
echo
"regular : ".$value , PHP_EOL;
echo
"With current function : ".$generator->current(),PHP_EOL;
}
?>
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