Statement on glibc/iconv Vulnerability

    apcu_cas

    (PECL apcu >= 4.0.0)

    apcu_cas — Updates an old value with a new value

    Descrizione

    apcu_cas(string $key, int $old, int $new): bool

    apcu_cas() updates an already existing integer value if the old parameter matches the currently stored value with the value of the new parameter.

    Elenco dei parametri

    key

    The key of the value being updated.

    old

    The old value (the value currently stored).

    new

    The new value to update to.

    Valori restituiti

    Restituisce true in caso di successo, false in caso di fallimento.

    Esempi

    Example #1 apcu_cas() example

    <?php
    apcu_store    ('foobar', 2);
    echo     '$foobar = 2', PHP_EOL;
    echo     '$foobar == 1 ? 2 : 1 = ', (apcu_cas('foobar', 1, 2) ? 'ok' : 'fail'), PHP_EOL;
    echo     '$foobar == 2 ? 1 : 2 = ', (apcu_cas('foobar', 2, 1) ? 'ok' : 'fail'), PHP_EOL;

    echo     '$foobar = ', apcu_fetch('foobar'), PHP_EOL;

    echo     '$f__bar == 1 ? 2 : 1 = ', (apcu_cas('f__bar', 1, 2) ? 'ok' : 'fail'), PHP_EOL;

    apcu_store('perfection', 'xyz');
    echo     '$perfection == 2 ? 1 : 2 = ', (apcu_cas('perfection', 2, 1) ? 'ok' : 'epic fail'), PHP_EOL;

    echo     '$foobar = ', apcu_fetch('foobar'), PHP_EOL;
    ?>

    Il precedente esempio visualizzerà qualcosa simile a:

    $foobar = 2
$foobar == 1 ? 2 : 1 = fail
$foobar == 2 ? 1 : 2 = ok
$foobar = 1
$f__bar == 1 ? 2 : 1 = fail
$perfection == 2 ? 1 : 2 = epic fail
$foobar = 1

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    User Contributed Notes 1 note

    up
    -7
    Anonymous
    6 years ago
    The output in the example says:

    $f__bar == 1 ? 2 : 1 = fail

    but in reality it should be:

    $f__bar == 1 ? 2 : 1 = ok

    the first time the code is ran as the cache is empty and apcu_cas allows the key to be inserted.
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