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filter_has_var

(PHP 5 >= 5.2.0, PHP 7, PHP 8)

filter_has_varChecks if variable of specified type exists

Опис

filter_has_var(int $input_type, string $var_name): bool

Параметри

input_type

One of INPUT_GET, INPUT_POST, INPUT_COOKIE, INPUT_SERVER, or INPUT_ENV.

var_name

Name of a variable to check.

Значення, що повертаються

Повертає true у разі успіху або false в разі помилки.

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User Contributed Notes 2 notes

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33
drm at melp dot nl
15 years ago
Please note that the function does not check the live array, it actually checks the content received by php:

<?php
$_GET
['test'] = 1;
echo
filter_has_var(INPUT_GET, 'test') ? 'Yes' : 'No';
?>

would say "No", unless the parameter was actually in the querystring.

Also, if the input var is empty, it will say Yes.
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19
nanhe dot kumar at gmail dot com
11 years ago
Through this example i think you can better understand

if ( !filter_has_var(INPUT_GET, 'email') ) {
echo "Email Not Found";
}else{
echo "Email Found";
}
Output

localhost/nanhe/test.php?email=1 //Email Found
localhost/nanhe/test.php?email //Email Found
http://localhost/nanhe/test.php //Email Not Found

Consider on second example

http://localhost/nanhe/test.php
$_GET['email']="info@nanhe.in";
if ( !filter_has_var(INPUT_GET, 'email') ) {
echo "Email Not Found";
}else{
echo "Email Found";
}
But output will be Email Not Found
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