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ArrayObject::getArrayCopy

(PHP 5, PHP 7)

ArrayObject::getArrayCopyCrea una copia de la clase ArrayObject

Descripción

public ArrayObject::getArrayCopy ( void ) : array

Exporta la clase ArrayObject a un array.

Parámetros

Esta función no tiene parámetros.

Valores devueltos

Devuelve una copia del array. Cuando la clase ArrayObject hace referencia a un objeto, un array de las propiedades públicas del objeto que será devuelto.

Ejemplos

Ejemplo #1 ArrayObject::getArrayCopy() example

<?php
// Array de frutas
$fruits = array("limones" => 1"naranjas" => 4"bananas" => 5"manzanas" => 10);

$fruitsArrayObject = new ArrayObject($fruits);
$fruitsArrayObject['peras'] = 4;

// crear una copia del array
$copy $fruitsArrayObject->getArrayCopy();
print_r($copy);

?>

El resultado del ejemplo sería:

Array
(
    [limones] => 1
    [naranjas] => 4
    [bananas] => 5
    [manzanas] => 10
    [peras] => 4
)

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User Contributed Notes 5 notes

up
3
jlshor at buffalo dot edu
3 years ago
Is there a difference between casting to an array and using this function?

For instance, if we have:
$arrayObject = new ArrayObject([1, 2, 3]);

Is there a difference between these:
$array = (array) $arrayObject;
vs
$array = $arrayObject->getArrayCopy();

If not, is there any scenario where they would produce different results, or do they produce the result in different ways?
up
3
Ivo von Putzer
8 years ago
If you did something like this to make your constructor multidimensional capable you will have some trouble using getArrayCopy to get a plain array straight out of the method:
<?php
public function __construct( $array = array(), $flags = 2 )
{
   
// let’s give the objects the right and not the inherited name
   
$class = get_class($this);

    foreach(
$array as $offset => $value)
       
$this->offsetSet($offset, is_array($value) ? new $class($value) : $value);

   
$this->setFlags($flags);
}
?>

That’s the way I solved it:

<?php
public function getArray($recursion = false)
{
   
// just in case the object might be multidimensional
   
if ( $this === true)
        return
$this->getArrayCopy();

    return
array_map( function($item){
        return
is_object($item) ? $item->getArray(true) : $item;
    },
$this->getArrayCopy() );
}
?>

Hope this was useful!
up
1
php at webflips dot net
6 years ago
"When the ArrayObject refers to an object an array of the public properties of that object will be returned."

This description does not seem to be right:

<?php
class A
{
    public
$var = 'var';
    protected
$foo = 'foo';
    private
$bar = 'bar';
}

$o = new ArrayObject(new A());
var_dump($o->getArrayCopy());

/*
Dumps:

array(3) {
  ["var"]=>
  string(3) "var"
  ["*foo"]=>
  string(3) "foo"
  ["Abar"]=>
  string(3) "bar"
}
*/
?>

So it does not only include the public properties.
up
1
sorcerer
3 years ago
When I used print_r ($fruitsArrayObject) instead of print_r ($copy), i.e. ignoring the getArrayCopy() step, I still got the same output. Why?
up
1
spidgorny at gmail dot com
3 years ago
<?php
$data
= $likeArray->getArrayCopy();
?>
will NOT be magically called if you cast to array. Although I've expected it.
<?php
$nothing
= (array)$likeArray;
?>
Here, $data != $nothing.
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