require

(PHP 4, PHP 5, PHP 7, PHP 8)

require є ідентичною до include, за одним виключенням - після збою вона генеруватиме фатальну помилку рівня E_COMPILE_ERROR. Іншими словами, вона припинятиме виконання скрипта, тоді як include тільки видасть попередження (E_WARNING), а скрипт буде виконуватись далі.

Прогляньте документацію include для уточнень, як ці функції працюють.

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User Contributed Notes 3 notes

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148
chris at chrisstockton dot org
17 years ago
Remember, when using require that it is a statement, not a function. It's not necessary to write:
<?php
require('somefile.php');
?>

The following:
<?php
require 'somefile.php';
?>

Is preferred, it will prevent your peers from giving you a hard time and a trivial conversation about what require really is.
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31
Marcel Baur
3 years ago
If your included file returns a value, you can get it as a result from require(), i.e.

foo.php:
<?php
return "foo";
?>

$bar = require("foo.php");
echo $bar; // equals to "foo"
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2
jave dot web at seznam dot cz
8 months ago
Always use __DIR__ to define path relative to your current __FILE__.
(Or another setting that is originally based on __DIR__/__FILE__)

try & catch - don't get confused by the words "fatal E_COMPILE_ERROR" - it's still just an internal Error that implements Throwable - it can be caught:

<?php
try {
require(
__DIR__ . '/something_that_does_not_exist');
} catch (
\Throwable $e) {
echo
"This was caught: " . $e->getMessage();
}
echo
" End of script.";
?>

Note that this will still emit a warning "Failed to open stream: No such file or directory..." ...unless you prefix the require with "@" - which I strongly don't recommend as it would ignore/supress any diagnostic error (unless you have specified set_error_handler()). But even if you'd prefix the require with "@" it would still be caught.
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