When using mode 1 or 2, the number returned will NOT match mode 0.
jddayofweek(0, 1) = 'Monday' not 'Sunday' as expected.
This can cause discordance between the UI and the value saved.
jddayofweek
(PHP 4, PHP 5, PHP 7, PHP 8)
jddayofweek — Devuelve el día de la semana
Descripción
Devuelve el día de la semana. Puede devolver una cadena o un entero dependiendo del modo.
Parámetros
-
julianday -
Un número de día juliano como un entero
-
mode -
Modos de semana de calendario Modo Significado 0 (Por defecto) Devuelve el número de día como un entero (0=domingo, 1=lunes, etc.) 1 Devuelve una cadena que contiene el día de la semana (Inglés-Gregoriano) 2 Devuelve una cadena que contiene el día de la semana abreviado (Inglés-Gregoriano)
Valores devueltos
El día de la semada gregoriana como un entero o cadena.
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User Contributed Notes 2 notes
phimuskapsi at gmail dot com ¶
9 months ago
kevind at communitycolor dot com ¶
4 years ago
You need to check to see how your client wants to represent the day of week. This function returns 0 for Sundays. ISO 8601 uses 7 for Sundays.
BTW, You can also calculate the day of week with modular division:
$dow = (1 + $julianday) % 7; // returns 0 for Sundays.
$dow = ($julianday % 7) + 1; // returns 7 for Sundays.
https://en.wikipedia.org/wiki/Julian_day#Finding_day_of_week_given_Julian_day_number
To make matters confusing. The Julian Date starts at noon UTC. Some programs such as SQLITE3 use real numbers to record date and time. If you pass this function a float; it will return a different day of week for the morning than for the afternoon.
When given a julianday with a decimal part you will need to add a half day and may need further adjustment for your timezone.
