PHP Conference Nagoya 2025

jdtounix

(PHP 4, PHP 5, PHP 7, PHP 8)

jdtounixConvierte una Fecha Juliana a una fecha Unix

Descripción

jdtounix(int $jday): int

Esta funcion devolverá una fecha Unix correspondiente a la Fecha Juliana dada en jday o false si jday no está dentro de la época Unix (años gregorianos entre 1970 y 2037 o 2440588 <= jday <= 2465342 ). El momento devuleto es como hora local (y no GMT).

Parámetros

jday

Un número de día juliano entre 2440588 y 2465342.

Valores devueltos

La fecha Unix para el comienzo de la Fecha Juliana dada.

Ver también

  • unixtojd() - Convertir una fecha Unix en una Fecha Juliana

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User Contributed Notes 5 notes

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7
fabio at llgp dot org
18 years ago
If you need an easy way to convert a decimal julian day to an unix timestamp you can use:

$unixTimeStamp = ($julianDay - 2440587.5) * 86400;

2440587.5 is the julian day at 1/1/1970 0:00 UTC
86400 is the number of seconds in a day
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3
Anonymous
19 years ago
Warning: the calender functions involving julian day operations seem to ignore the decimal part of the julian day count.

This means that the returned date is wrong 50% of the time, since a julian day starts at decimal .5 . Take care!!
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0
seb at carbonauts dot com
21 years ago
Remember that unixtojd() assumes your timestamp is in GMT, but jdtounix() returns a timestamp in localtime.

This fooled me a few times.

So if you have:

$timestamp1 = time();
$timestamp2 = jdtounix(unixtojd($timestamp1));

Unless your localtime is the same as GMT, $timestamp1 will not equal $timestamp2.
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-2
Saeed Hubaishan
10 years ago
unixtojd() assumes that your timestamp is in GMT, but jdtounix() returns a timestamp in localtime.
so
<?php
$d1
=jdtogregorian(unixtojd(time()));
$d2= gmdate("m/d/Y");
$d3=date("m/d/Y");
?>
$d1 always equals $d2 but $d1 may differ from $d3
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-2
pipian at pipian dot com
21 years ago
Remember that UNIX timestamps indicate a number of seconds from midnight of January 1, 1970 on the Gregorian calendar, not the Julian Calendar.
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