XML hatalarıya ilgilenmek

Belgeleri yüklerken XML hatalarını ele almak basit bir işlemdir. Belgeyi yüklerken XML hatalarını libxml işlevselliğini kullanarak bastırdıktan sonra hatalar tek tek ele alınabilir.

libxml_get_errors() işlevi tarafından döndürülen libXMLError nesnesi, hata ile ilgili ileti, satır ve sütun gibi özellikler içerir.

Örnek 1 - Hatalı bir XML dizgesinin yüklenmesi

<?php
libxml_use_internal_errors
(true);
$sxe simplexml_load_string("<?xml version='1.0'><broken><xml></broken>");
if (!
$sxe) {
    echo 
"XML yüklemesi başarısız oldu\n";
    foreach(
libxml_get_errors() as $error) {
        echo 
"\t"$error->message;
    }
}

Yukarıdaki örneğin çıktısı:

XML yüklemesi başarısız oldu
 Blank needed here
 parsing XML declaration: '?>' expected
 Opening and ending tag mismatch: xml line 1 and broken
 Premature end of data in tag broken line 1

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User Contributed Notes 4 notes

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19
openbip at gmail dot com
10 years ago
Note that "if (! $sxe) {" may give you a false-negative if the XML document was empty (e.g. "<root />").  In that case, $sxe will be:

object(SimpleXMLElement)#1 (0) {
}

which will evaluate to false, even though nothing technically went wrong.

Consider instead: "if ($sxe === false) {"
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2
1337 at netapp dot com
4 years ago
If you need to process the content of your broken XML-doc you might find this interesting. It has blown past a few simple corruptions for me.
http://php.net/manual/en/class.domdocument.php#domdocument.props.recover
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3
tuxedobob
5 years ago
Now that the /e modifier is considered deprecated in preg_replace, you can use a negative lookahead to replace unescaped ampersands with &amp; without throwing warnings:

$str = preg_replace('/&(?!;{6})/', '&amp;', $str);

You probably should have been doing this before /e was deprecated, actually.
up
-8
Jacob Tabak
10 years ago
If you are trying to load an XML string with some escaped and some unescaped ampersands, you can pre-parse the string to ecsape the unescaped ampersands without modifying the already escaped ones:
<?php
$s
= preg_replace('/&[^; ]{0,6}.?/e', "((substr('\\0',-1) == ';') ? '\\0' : '&amp;'.substr('\\0',1))", $s);
?>
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