CascadiaPHP 2024

require

(PHP 4, PHP 5, PHP 7, PHP 8)

requireinclude 几乎完全一样,除了处理失败的方式不同之外。require 在出错时产生 E_COMPILE_ERROR 级别的错误。换句话说将导致脚本中止而 include 只产生警告(E_WARNING),脚本会继续运行。

参见 include 文档了解详情。

add a note

User Contributed Notes 3 notes

up
150
chris at chrisstockton dot org
17 years ago
Remember, when using require that it is a statement, not a function. It's not necessary to write:
<?php
require('somefile.php');
?>

The following:
<?php
require 'somefile.php';
?>

Is preferred, it will prevent your peers from giving you a hard time and a trivial conversation about what require really is.
up
31
Marcel Baur
2 years ago
If your included file returns a value, you can get it as a result from require(), i.e.

foo.php:
<?php
return "foo";
?>

$bar = require("foo.php");
echo $bar; // equals to "foo"
up
1
jave dot web at seznam dot cz
6 months ago
Always use __DIR__ to define path relative to your current __FILE__.
(Or another setting that is originally based on __DIR__/__FILE__)

try & catch - don't get confused by the words "fatal E_COMPILE_ERROR" - it's still just an internal Error that implements Throwable - it can be caught:

<?php
try {
require(
__DIR__ . '/something_that_does_not_exist');
} catch (
\Throwable $e) {
echo
"This was caught: " . $e->getMessage();
}
echo
" End of script.";
?>

Note that this will still emit a warning "Failed to open stream: No such file or directory..." ...unless you prefix the require with "@" - which I strongly don't recommend as it would ignore/supress any diagnostic error (unless you have specified set_error_handler()). But even if you'd prefix the require with "@" it would still be caught.
To Top