(PHP 4, PHP 5, PHP 7, PHP 8)
basename — Restituisce il nome del file dal percorso indicato
Data una stringa contenente il percorso di un file, questa funzione
restituisce il nome del file.
Se il nome del file finisce in suffix
quest'ultimo verrà tagliato.
Su Windows, sia gli slash (/) che i backslash
(\) vengono utilizzati come carattere di separazione delle directory.
In altri ambienti, si usa solo lo slash semplice
(/).
Example #1 Esempio di basename()
<?php
$path = "/home/httpd/html/index.php";
$file = basename($path); // la variabile $file contiene "index.php"
$file = basename($path,".php"); // la variabile $file contiene "index"
?>Nota:
Il parametro
suffixè stato aggiunto in PHP 4.1.0.
Vedere anche dirname()
It's a shame, that for a 20 years of development we don't have mb_basename() yet!
// works both in windows and unix
function mb_basename($path) {
if (preg_match('@^.*[\\\\/]([^\\\\/]+)$@s', $path, $matches)) {
return $matches[1];
} else if (preg_match('@^([^\\\\/]+)$@s', $path, $matches)) {
return $matches[1];
}
return '';
}There is only one variant that works in my case for my Russian UTF-8 letters:
<?php
function mb_basename($file)
{
return end(explode('/',$file));
}
><
It is intented for UNIX serversIf you want the current path where youre file is and not the full path then use this :)
<?php
echo('dir = '.basename (dirname($_SERVER['PHP_SELF']),"/"));
// retuns the name of current used directory
?>
Example:
www dir: domain.com/temp/2005/january/t1.php
<?php
echo('dirname <br>'.dirname($_SERVER['PHP_SELF']).'<br><br>');
// returns: /temp/2005/january
?>
<?php
echo('file = '.basename ($PHP_SELF,".php"));
// returns: t1
?>
if you combine these two you get this
<?php
echo('dir = '.basename (dirname($_SERVER['PHP_SELF']),"/"));
// returns: january
?>
And for the full path use this
<?php
echo(' PHP_SELF <br>'.$_SERVER['PHP_SELF'].'<br><br>');
// returns: /temp/2005/january/t1.php
?>Here is a quick way of fetching only the filename (without extension) regardless of what suffix the file has.
<?php
// your file
$file = 'image.jpg';
$info = pathinfo($file);
$file_name = basename($file,'.'.$info['extension']);
echo $file_name; // outputs 'image'
?>