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(PHP 4, PHP 5, PHP 7, PHP 8)

filetypeRestituisce il tipo di file


filetype(string $filename): string

Restituisce il tipo del file. Sono valori possibili fifo, char, dir, block, link, file e unknown.

Restituisce false se si verifica un errore. Inoltre la funzione filetype() genera un errore di livello E_NOTICE se fallisce la chiamata a stat o se il tipo è sconosciuto.

Nota: I risultati di questa funzione saranno memorizzati. Vedere clearstatcache() per maggiori dettagli.


A partire da PHP 5.0.0, questa funzione può essere utilizzata con alcuni URL wrappers. Fare riferimento a Supported Protocols and Wrappers per la lista di quali wrappers supportano le funzioni della famiglia stat().

Example #1 Esempio di uso di filetype()

echo filetype('/etc/passwd'); // file
echo filetype('/etc/'); // dir


Vedere anche: is_dir(), is_file(), is_link(), file_exists(), stat() e mime_content_type().

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User Contributed Notes 6 notes

ruach at chpc dot utah dot edu
20 years ago
There are 7 values that can be returned. Here is a list of them and what each one means

block: block special device

char: character special device

dir: directory

fifo: FIFO (named pipe)

file: regular file

link: symbolic link

unknown: unknown file type
13 years ago
filetype() does not work for files >=2GB on x86 Linux. You can use stat as a workarround:

$type=trim(`stat -c%F $file`);

Note that stat returns diffenerent strings ("regular file","directory",...)
7r6ivyeo at mail dot com
15 years ago
I use the CLI version of PHP on Windows Vista. Here's how to determine if a file is marked "hidden" by NTFS:

function is_hidden_file($fn) {

$attr = trim(exec('FOR %A IN ("'.$fn.'") DO @ECHO %~aA'));

$attr[3] === 'h')


Changing <?php if($attr[3] === 'h') ?> to <?php if($attr[4] === 's') ?> will check for system files.

This should work on any Windows OS that provides DOS shell commands.
Abhi Jain
13 years ago
Putting @ in front of the filetype() function does not prevent it from raising a warning (Lstat failed), if E_WARNING is enabled on your error_reporting.

The most common cause of filetype() raising this warning and not showing a filetype() in the output (it actually returns NULL) is, if you happened to pass just the 'Dir or File Name' and not the complete "Absolute or Relative Path" to that 'file or Dir'. It may still read that file and return its filetype as "file" but for Dir's it shows warning and outputs NULL.
$pathToFile = '/var/www';
$file = 'test.php';
$dir = 'somedir';

Output for filetype($file) will be returned as 'file' and possibly without any warning, but for filetype($dir), it will return NULL with the warning "Lstat failed", unless you pass a complete path to that dir, i.e. filetype($pathToFile.'/'.$dir).

This happened to me and found this solution after a lot of trial and error. Thought, it might help someone.
9 years ago
Note there is a bug when using filetype with for example Japanese filenames :

The whole PHP interpreter comes crashing down without anyway to avoid it or capture an exception.
r dot koelpin at evisionteam dot de
10 years ago

echo "Zum testen müssen tatsächlich existente Namen verwendet werden.<br>";
"Pfad und Dateiname müssen getrennt eingetragen und durch einen Punkt verbunden sein.<br>";
"Example: [filetype(\"../dir/u_dir/\".\"temp.jpg\")] liefert -> file<br>";
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