PHP 8.4.0 Alpha 2 available for testing

ArrayObject::getArrayCopy

(PHP 5, PHP 7, PHP 8)

ArrayObject::getArrayCopyСоздаёт копию ArrayObject

Описание

public ArrayObject::getArrayCopy(): array

Экспортирует ArrayObject в массив.

Список параметров

У этой функции нет параметров.

Возвращаемые значения

Возвращает копию массива. Если ArrayObject ссылается на объект, то будет возвращён массив свойств данного объекта.

Примеры

Пример #1 Пример использования ArrayObject::getArrayCopy()

<?php
// Массив с количеством фруктов
$fruits = array("lemons" => 1, "oranges" => 4, "bananas" => 5, "apples" => 10);

$fruitsArrayObject = new ArrayObject($fruits);
$fruitsArrayObject['pears'] = 4;

// Создать копию массива
$copy = $fruitsArrayObject->getArrayCopy();
print_r($copy);

?>

Результат выполнения приведённого примера:

Array
(
    [lemons] => 1
    [oranges] => 4
    [bananas] => 5
    [apples] => 10
    [pears] => 4
)

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User Contributed Notes 5 notes

up
4
spidgorny at gmail dot com
7 years ago
<?php
$data
= $likeArray->getArrayCopy();
?>
will NOT be magically called if you cast to array. Although I've expected it.
<?php
$nothing
= (array)$likeArray;
?>
Here, $data != $nothing.
up
5
Ivo von Putzer
12 years ago
If you did something like this to make your constructor multidimensional capable you will have some trouble using getArrayCopy to get a plain array straight out of the method:
<?php
public function __construct( $array = array(), $flags = 2 )
{
// let’s give the objects the right and not the inherited name
$class = get_class($this);

foreach(
$array as $offset => $value)
$this->offsetSet($offset, is_array($value) ? new $class($value) : $value);

$this->setFlags($flags);
}
?>

That’s the way I solved it:

<?php
public function getArray($recursion = false)
{
// just in case the object might be multidimensional
if ( $this === true)
return
$this->getArrayCopy();

return
array_map( function($item){
return
is_object($item) ? $item->getArray(true) : $item;
},
$this->getArrayCopy() );
}
?>

Hope this was useful!
up
2
jlshor at buffalo dot edu
7 years ago
Is there a difference between casting to an array and using this function?

For instance, if we have:
$arrayObject = new ArrayObject([1, 2, 3]);

Is there a difference between these:
$array = (array) $arrayObject;
vs
$array = $arrayObject->getArrayCopy();

If not, is there any scenario where they would produce different results, or do they produce the result in different ways?
up
1
php at webflips dot net
10 years ago
"When the ArrayObject refers to an object an array of the public properties of that object will be returned."

This description does not seem to be right:

<?php
class A
{
public
$var = 'var';
protected
$foo = 'foo';
private
$bar = 'bar';
}

$o = new ArrayObject(new A());
var_dump($o->getArrayCopy());

/*
Dumps:

array(3) {
["var"]=>
string(3) "var"
["*foo"]=>
string(3) "foo"
["Abar"]=>
string(3) "bar"
}
*/
?>

So it does not only include the public properties.
up
0
sorcerer
7 years ago
When I used print_r ($fruitsArrayObject) instead of print_r ($copy), i.e. ignoring the getArrayCopy() step, I still got the same output. Why?
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