(PHP 8 >= 8.6.0)
mysqli::quote_string -- mysqli_quote_string — Quotes and escapes a string for use in an SQL statement
Об'єктно-орієнтований стиль
Процедурний стиль
Creates a legal SQL string literal that can be used in an SQL statement. The given string is escaped in the same way as mysqli::real_escape_string(), taking into account the current character set of the connection, and the result is wrapped in single quotes. The returned value must therefore be inserted into the query without adding any further quotes around it.
Unlike mysqli::real_escape_string(), the result is
also safe when the NO_BACKSLASH_ESCAPES SQL mode is
enabled on the connection.
The character set must be set either at the server level, or with the API function mysqli_set_charset() for it to affect mysqli_quote_string(). See the concepts section on character sets for more information.
Зауваження:
Quoting is only suitable for string literals. It does not make identifiers, such as table or column names, safe. Whenever possible, use prepared statements instead of building queries manually.
mysqlТільки процедурний стиль: об'єкт mysqli, якого повертає функція mysqli_connect() або mysqli_init()
stringThe string to be quoted and escaped.
Characters encoded are NUL (ASCII 0),
\n, \r, \,
', ", and
CTRL+Z.
If the NO_BACKSLASH_ESCAPES SQL mode is enabled on
the connection, only ' is encoded, by doubling it.
Returns the escaped string enclosed in single quotes.
Приклад #1 mysqli::quote_string() example
Об'єктно-орієнтований стиль
<?php
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
$city = "'s-Hertogenbosch";
/* this query with quoted $city will work */
$query = sprintf("SELECT CountryCode FROM City WHERE name=%s", $mysqli->quote_string($city));
$result = $mysqli->query($query);
printf("Select returned %d rows.\n", $result->num_rows);
/* this query will fail, because we didn't quote and escape $city */
$query = sprintf("SELECT CountryCode FROM City WHERE name='%s'", $city);
$result = $mysqli->query($query);Процедурний стиль
<?php
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$mysqli = mysqli_connect("localhost", "my_user", "my_password", "world");
$city = "'s-Hertogenbosch";
/* this query with quoted $city will work */
$query = sprintf("SELECT CountryCode FROM City WHERE name=%s", mysqli_quote_string($mysqli, $city));
$result = mysqli_query($mysqli, $query);
printf("Select returned %d rows.\n", mysqli_num_rows($result));
/* this query will fail, because we didn't quote and escape $city */
$query = sprintf("SELECT CountryCode FROM City WHERE name='%s'", $city);
$result = mysqli_query($mysqli, $query);Подані вище приклади виведуть щось схоже на:
Select returned 1 rows. Fatal error: Uncaught mysqli_sql_exception: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 's-Hertogenbosch'' at line 1 in...