(PHP 4, PHP 5, PHP 7)

bcsubSubtract one arbitrary precision number from another


bcsub ( string $left_operand , string $right_operand [, int $scale = 0 ] ) : string

Subtracts the right_operand from the left_operand.



The left operand, as a string.


The right operand, as a string.


This optional parameter is used to set the number of digits after the decimal place in the result. If omitted, it will default to the scale set globally with the bcscale() function, or fallback to 0 if this has not been set.

Return Values

The result of the subtraction, as a string.


Example #1 bcsub() example


$b '5';

bcsub($a$b);     // -3
echo bcsub($a$b4);  // -3.7660


See Also

  • bcadd() - Add two arbitrary precision numbers

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User Contributed Notes 2 notes

nd at snackbox dot org
1 year ago
The parameter order here is probably fairly obvious to most people (subtract right from left), but to clarify with a simple use case since I was struggling with this at the end of a long day:

echo bcsub('7', '5'); // 7 - 5 = '2'
echo bcsub('12', '17'); // 12 - 17 = '-5'

Provide the parameters in the same order you would when using a normal subtraction operator.
charles dot adrian dot wood at gmail dot com
8 days ago
Please note that bcsub will fail in non-obvious ways if it's fed something that cannot be converted to a number. For instance:

bcsub('yes', 'no') === '0'

Yes, if you put garbage in, you get garbage out. Just don't expect bcsub to throw an error when you feed it an entirely non-numeric value.
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