ArrayObject::getArrayCopy

(PHP 5, PHP 7)

ArrayObject::getArrayCopyCrée une copie de l'objet ArrayObject

Description

public ArrayObject::getArrayCopy ( void ) : array

Exporte l'objet ArrayObject vers un tableau.

Liste de paramètres

Cette fonction ne contient aucun paramètre.

Valeurs de retour

Retourne une copie du tableau. Lorsque l'objet ArrayObject est un objet, le tableau retourné contient les propriétés publiques de cet objet.

Exemples

Exemple #1 Exemple avec ArrayObject::getArrayCopy()

<?php
// Liste de fruits
$fruits = array("citrons" => 1"oranges" => 4"bananes" => 5"pommes" => 10);

$fruitsArrayObject = new ArrayObject($fruits);
$fruitsArrayObject['poires'] = 4;

// Crée un copie des tableaux
$copy $fruitsArrayObject->getArrayCopy();
print_r($copy);

?>

L'exemple ci-dessus va afficher :

Array
(
    [citrons] => 1
    [oranges] => 4
    [bananes] => 5
    [pommes] => 10
    [poires] => 4
)

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User Contributed Notes 5 notes

up
3
jlshor at buffalo dot edu
3 years ago
Is there a difference between casting to an array and using this function?

For instance, if we have:
$arrayObject = new ArrayObject([1, 2, 3]);

Is there a difference between these:
$array = (array) $arrayObject;
vs
$array = $arrayObject->getArrayCopy();

If not, is there any scenario where they would produce different results, or do they produce the result in different ways?
up
3
Ivo von Putzer
8 years ago
If you did something like this to make your constructor multidimensional capable you will have some trouble using getArrayCopy to get a plain array straight out of the method:
<?php
public function __construct( $array = array(), $flags = 2 )
{
   
// let’s give the objects the right and not the inherited name
   
$class = get_class($this);

    foreach(
$array as $offset => $value)
       
$this->offsetSet($offset, is_array($value) ? new $class($value) : $value);

   
$this->setFlags($flags);
}
?>

That’s the way I solved it:

<?php
public function getArray($recursion = false)
{
   
// just in case the object might be multidimensional
   
if ( $this === true)
        return
$this->getArrayCopy();

    return
array_map( function($item){
        return
is_object($item) ? $item->getArray(true) : $item;
    },
$this->getArrayCopy() );
}
?>

Hope this was useful!
up
2
php at webflips dot net
5 years ago
"When the ArrayObject refers to an object an array of the public properties of that object will be returned."

This description does not seem to be right:

<?php
class A
{
    public
$var = 'var';
    protected
$foo = 'foo';
    private
$bar = 'bar';
}

$o = new ArrayObject(new A());
var_dump($o->getArrayCopy());

/*
Dumps:

array(3) {
  ["var"]=>
  string(3) "var"
  ["*foo"]=>
  string(3) "foo"
  ["Abar"]=>
  string(3) "bar"
}
*/
?>

So it does not only include the public properties.
up
1
sorcerer
2 years ago
When I used print_r ($fruitsArrayObject) instead of print_r ($copy), i.e. ignoring the getArrayCopy() step, I still got the same output. Why?
up
1
spidgorny at gmail dot com
2 years ago
<?php
$data
= $likeArray->getArrayCopy();
?>
will NOT be magically called if you cast to array. Although I've expected it.
<?php
$nothing
= (array)$likeArray;
?>
Here, $data != $nothing.
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